3Sum Closest LeetCode Solution

Problem – 3Sum Closest LeetCode Solution

Given an integer array nums of length n and an integer target, find three integers in nums such that the sum is closest to target.

Return the sum of the three integers.

You may assume that each input would have exactly one solution.

Example 1:

Input: nums = [-1,2,1,-4], target = 1
Output: 2
Explanation: The sum that is closest to the target is 2. (-1 + 2 + 1 = 2).

Example 2:

Input: nums = [0,0,0], target = 1
Output: 0

Constraints:

• 3 <= nums.length <= 1000
• -1000 <= nums[i] <= 1000
• -104 <= target <= 104

3Sum Closest LeetCode Solution in Java

public class Solution {
    public int threeSumClosest(int[] num, int target) {
        int result = num[0] + num[1] + num[num.length - 1];
        Arrays.sort(num);
        for (int i = 0; i < num.length - 2; i++) {
            int start = i + 1, end = num.length - 1;
            while (start < end) {
                int sum = num[i] + num[start] + num[end];
                if (sum > target) {
                    end--;
                } else {
                    start++;
                }
                if (Math.abs(sum - target) < Math.abs(result - target)) {
                    result = sum;
                }
            }
        }
        return result;
    }
}

3Sum Closest LeetCode Solution in C++

int threeSumClosest(vector<int>& nums, int target) {
    if(nums.size() < 3) return 0;
    int closest = nums[0]+nums[1]+nums[2];
    sort(nums.begin(), nums.end());
    for(int first = 0 ; first < nums.size()-2 ; ++first) {
        if(first > 0 && nums[first] == nums[first-1]) continue;
        int second = first+1;
        int third = nums.size()-1;            
        while(second < third) {
            int curSum = nums[first]+nums[second]+nums[third];
            if(curSum == target) return curSum;
            if(abs(target-curSum)<abs(target-closest)) {
                closest = curSum;
            }
            if(curSum > target) {
                --third;
            } else {
                ++second;
            }
        }
    }
    return closest;
}

3Sum Closest LeetCode Solution in Python

class Solution:
    # @return an integer
    def threeSumClosest(self, num, target):
        num.sort()
        result = num[0] + num[1] + num[2]
        for i in range(len(num) - 2):
            j, k = i+1, len(num) - 1
            while j < k:
                sum = num[i] + num[j] + num[k]
                if sum == target:
                    return sum
                
                if abs(sum - target) < abs(result - target):
                    result = sum
                
                if sum < target:
                    j += 1
                elif sum > target:
                    k -= 1
            
        return result

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