Pascal’s Triangle LeetCode Solution

Problem – Pascal’s Triangle

Given an integer numRows, return the first numRows of Pascal’s triangle.

In Pascal’s triangle, each number is the sum of the two numbers directly above it as shown:

Example 1:

Input: numRows = 5
Output: [[1],[1,1],[1,2,1],[1,3,3,1],[1,4,6,4,1]]

Example 2:

Input: numRows = 1
Output: [[1]]

Constraints:

  • 1 <= numRows <= 30

Pascal’s Triangle LeetCode Solution in C++

class Solution {
public:
    vector<vector<int> > generate(int numRows) {
        vector<vector<int>> r(numRows);

        for (int i = 0; i < numRows; i++) {
            r[i].resize(i + 1);
            r[i][0] = r[i][i] = 1;
  
            for (int j = 1; j < i; j++)
                r[i][j] = r[i - 1][j - 1] + r[i - 1][j];
        }
        
        return r;
    }
};

Pascal’s Triangle LeetCode Solution in Python

def generate(self, numRows):
        res = [[1]]
        for i in range(1, numRows):
            res += [map(lambda x, y: x+y, res[-1] + [0], [0] + res[-1])]
        return res[:numRows]

Pascal’s Triangle LeetCode Solution in Java

public class Solution {
public List<List<Integer>> generate(int numRows)
{
	List<List<Integer>> allrows = new ArrayList<List<Integer>>();
	ArrayList<Integer> row = new ArrayList<Integer>();
	for(int i=0;i<numRows;i++)
	{
		row.add(0, 1);
		for(int j=1;j<row.size()-1;j++)
			row.set(j, row.get(j)+row.get(j+1));
		allrows.add(new ArrayList<Integer>(row));
	}
	return allrows;
	
}
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