A Small Array CodeChef Solution

Problem -A Small Array CodeChef Solution

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A Small Array CodeChef Solution in C++14

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#include "bits/stdc++.h"
using namespace std;
typedef long long ll;
typedef unsigned long long lll;
typedef pair<ll, ll> Pii;
#define nl "\n"
#define all(x) (x).begin(), (x).end()
#define rall(x) (x).rbegin(), (x).rend()
#define YES cout << "YES\n";
#define NO cout << "NO\n";
#define Yes puts("Yes");
#define No puts("No");
#define ansr cout << ans << nl;
#define pii pair<ll, ll>
#define pdi pair<double, ll>
#define pid pair<ll, double>
#define vpii vector<pair<ll, ll>>
#define vi vector<ll>
#define si set<ll>
#define mii map<ll, ll>
#define umii unordered_map<ll, ll>
#define fi first
#define se second
#define pb push_back
#define rp(i, a, n) for (ll i = a; i < n; i++)
#define rpn(i, n, a) for (ll i = n - 1; i >= a; i--)
#define inp(a, n) rp(i, 0, n) cin >> a[i]
#define MAX 100005
#define withMOD % 1000000007
const ll INF = 2e9;
const ll N = 2e5 + 1;

void solve()
{
  ll n,x;
  cin>>n>>x;
  vi a(n);inp(a,n);
  ll sum = accumulate(all(a),0ll);
  ll x1 = 0,sum1 = 0;
  ll x2 = 0,sum2 = 0;
  rp(i,0,n){
    sum1 = max(a[i],a[i]+sum1);
    x1 = max(x1,sum1);
    sum2 = min(a[i],a[i]+sum2);
    x2 = min(x2,sum2);
  }
  float ans = 0.00;
  if(x>0){
    // sum -= x1;
    ans += sum - x1;
    ans += float(x1)/x;
    // sum += x1;
  }
  else if(x<0){
    // sum -= x2;
    ans += sum - x1;
    ans += float(x1)/x;
    // x2 /= x;
    // sum += x2;
  }
  cout<<setprecision(5)<<ans<<nl;
}

int main()
{
#ifdef LOCAL
  freopen("input.txt", "r", stdin);
  freopen("output.txt", "w", stdout);
#else
  ios_base::sync_with_stdio(0);
  cin.tie(0);
  cout.tie(0);
#endif
  int t;
  // cin >> t;
  t = 1;
  while (t--)
    solve();
  return 0;
}

A Small Array CodeChef Solution in PYTH 3

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# cook your dish here
n, x = map(int, input().split())
a = list(map(int, input().split()))
maxsum = 0
allsum = 0
currsum = 0
for i in a:
    currsum += i
    allsum += i
    maxsum = max(maxsum, currsum)
    
    if currsum < 0:
        currsum = 0
        
print(allsum-(maxsum-maxsum/x))

A Small Array CodeChef Solution in C

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#include<stdio.h>
int main()
{
    int x,n,sum = 0,min = 0,dif = 0;
    scanf("%d %d", &n,&x);
    int c;
    for(int i=0; i<n; i++)
    {
        scanf("%d", &c);
        sum = sum + c;
        if(sum - min > dif){
            dif = sum - min;
        }
        if(sum < min){
            min = sum;
        }
    }
    float ans = sum - (x-1)*(1.0)*(dif)/x;
    printf("%.1f",ans);
    return 0;
    
}

A Small Array CodeChef Solution in JAVA

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/* package codechef; // don't place package name! */

import java.util.*;
import java.lang.*;
import java.io.*;

/* Name of the class has to be "Main" only if the class is public. */
class Codechef
{
    
    public static double getMax(int a[]){
        
        int n = a.length;
        
        double max = Double.MIN_VALUE;
        
        double sum = 0;
        
        for(int i=0;i<n;i++){
            sum+=a[i];
            if(sum>=0){
                
                max = Math.max(sum,max);
                
            }else{
                sum = 0;
            }
        }
        
        return max;
        
    }
	public static void main (String[] args) throws java.lang.Exception
	{
		// your code goes here
		Scanner sc = new Scanner(System.in);
		
		int n = sc.nextInt();
		int x = sc.nextInt();
		double sum = 0;
		int a[] = new int[n];
		for(int i=0;i<n;i++){
		    a[i] = sc.nextInt();
		    sum+=a[i];
		}
		double ans =(double) getMax(a);
		if(ans>0){
		    
		    sum = (sum-ans) + (ans/x);
		    
		}
		System.out.println(sum);
	}
}

A Small Array CodeChef Solution in PYPY 3

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# You don't need to add/edit anything to the below solution. 
# Click on the SUBMIT button to solve your first problem on CodeChef.
from math import isclose
n, x = map(int, input().split())
arr = list(map(int, input().split()))

p = [arr[0]]
m, idx = arr[0], 0
for i in range(1, n):
    p.append(max(p[i-1]+arr[i], 0))
    if p[i] > m:
        m = p[i]
        idx = i

if m == 0:
    print(sum(arr))
else:
    s = 0
    while s != m:
        s += arr[idx]
        arr[idx] /= x
        idx -= 1
    
    
    print(sum(arr))

A Small Array CodeChef Solution in PYTH

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st = raw_input().split()
N = int(st[0]) 
X = int(st[1]) 
st = raw_input().split()
if X == 1:
	tot = 0
	for x in st:
		tot += int(x)
	# endfor x
	print tot
else:
	tot = 0
	W = 0
	MX = 0
	for x in st:
		n = int(x)
		tot += n
		if n > 0:
			W += n
			if W > MX:
				MX = W
			# endif
		else:
			W = max(0,W+n)
		# endif
	# endfor x
	tot -= MX
	tot += 1.0*MX/X
	print tot
# endif

A Small Array CodeChef Solution in GO

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package main

import (
	"bufio"
	"fmt"
	"os"
)

func readInt(bytes []byte, from int, val *int) int {
	i := from
	sign := 1
	if bytes[i] == '-' {
		sign = -1
		i++
	}
	tmp := 0
	for i < len(bytes) && bytes[i] != ' ' {
		tmp = tmp*10 + int(bytes[i]-'0')
		i++
	}
	*val = tmp * sign
	return i
}

func readNum(scanner *bufio.Scanner) (a int) {
	scanner.Scan()
	readInt(scanner.Bytes(), 0, &a)
	return
}

func readTwoNums(scanner *bufio.Scanner) (a int, b int) {
	res := readNNums(scanner, 2)
	a, b = res[0], res[1]
	return
}

func readNNums(scanner *bufio.Scanner, n int) []int {
	res := make([]int, n)
	x := 0
	scanner.Scan()
	for i := 0; i < n; i++ {
		for x < len(scanner.Bytes()) && scanner.Bytes()[x] == ' ' {
			x++
		}
		x = readInt(scanner.Bytes(), x, &res[i])
	}
	return res
}

func fillNNums(scanner *bufio.Scanner, n int, res []int) {
	x := 0
	scanner.Scan()
	for i := 0; i < n; i++ {
		for x < len(scanner.Bytes()) && scanner.Bytes()[x] == ' ' {
			x++
		}
		x = readInt(scanner.Bytes(), x, &res[i])
	}
}

func readUint64(bytes []byte, from int, val *uint64) int {
	i := from

	var tmp uint64
	for i < len(bytes) && bytes[i] != ' ' {
		tmp = tmp*10 + uint64(bytes[i]-'0')
		i++
	}
	*val = tmp

	return i
}

func main() {
	scanner := bufio.NewScanner(os.Stdin)
	n, x := readTwoNums(scanner)
	A := readNNums(scanner, n)
	res := solve(n, x, A)
	fmt.Printf("%.3f\n", res)
}

func solve(n, x int, A []int) float64 {
	var sum int

	for i := 0; i < n; i++ {
		sum += A[i]
	}

	if x == 1 {
		return float64(sum)
	}

	var best int
	var tmp int
	for i := 0; i < n; i++ {
		tmp += A[i]
		best = max(best, tmp)
		if tmp < 0 {
			tmp = 0
		}
	}

	if best == 0 {
		return float64(sum)
	}

	fx := float64(x)
	num := float64(best) * (fx - 1) / fx

	return float64(sum) - num
}

func max(a, b int) int {
	if a >= b {
		return a
	}
	return b
}

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