Add Digits LeetCode Solution

Problem – Add Digits LeetCode Solution

Given an integer num, repeatedly add all its digits until the result has only one digit, and return it.

Example 1:

Input: num = 38
Output: 2
Explanation: The process is
38 --> 3 + 8 --> 11
11 --> 1 + 1 --> 2 
Since 2 has only one digit, return it.

Example 2:

Input: num = 0
Output: 0

Constraints:

• 0 <= num <= 231 - 1

Follow up: Could you do it without any loop/recursion in O(1) runtime?

Add Digits LeetCode Solution in Java

class Solution {
    public int addDigits(int num) {
        if(num == 0) return 0;
        else if(num % 9 == 0) return 9;
        else return num % 9;
    }
}

Add Digits LeetCode Solution in C++

class Solution {
public:
    int addDigits(int num) {
        if(num == 0) return 0;
        else if(num % 9 == 0) return 9;
        else return num % 9;
    }
};

Add Digits LeetCode Solution in Python

class Solution:
    def addDigits(self, num: int) -> int:
        if num == 0 : return 0
        if num % 9 == 0 : return 9
        else : return (num % 9)

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