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# AI Analysing Code CodeChef Solution

## Problem – AI Analysing Code CodeChef Solution

Chef has recently introduced a feature which allows you to open any user’s submitted code (not just your own), and ask an AI to explain that code in English. For example, you can go to https://www.codechef.com/viewsolution/70530506 and click on “Analyse This Code”.

But there is a restriction that the feature works only on codes which are at most 10001000 characters long. Given the number of characters, CC, in a particular code, output whether the feature is available on this code or not.

#### Input Format

The only line of input will contain a single integer CC, denoting the number of characters in the code.

#### Output Format

Output a single line which contains either “Yes”, if the feature is available on this code, or “No”, if not.

You may print each character of the string in either uppercase or lowercase (for example, the strings NOnONo, and no will all be treated as identical).

#### Constraints

• 1 \leq C \leq 100001≤C≤10000

#### Sample 1:

Input: 50
Output: Yes

#### Explanation:

The code’s length is only 5050, and 50 \le 100050≤1000. So, the feature is available, and the answer is “Yes”.

#### Sample 2:

Input: 1000
Output: Yes

#### Explanation:

The code’s length is 10001000, and 1000 \le 10001000≤1000. So, the feature is available, and the answer is “Yes”.

#### Sample 3:

Input: 1001
Output: No

#### Explanation:

The code’s length is 10011001, and 1001 \nleq 10001001≰1000. So, the feature is not available, and the answer is “No”.

### AI Analysing Code CodeChef Solution in C++14

#include <iostream>
using namespace std;

int main() {
int c;
cin>>c;
if(c > 1000){
cout<<"NO";
}
else{
cout<<"YES";
}
return 0;
}


### AI Analysing Code CodeChef Solution in Python3

# cook your dish here
C=int(input());
if(C<=1000):
print('Yes')
else:
print('No')

### AI Analysing Code CodeChef Solution in Java

/* package codechef; // don't place package name! */

import java.util.*;
import java.lang.*;
import java.io.*;

/* Name of the class has to be "Main" only if the class is public. */
class Codechef
{
public static void main (String[] args) throws java.lang.Exception
{
Scanner sc=new Scanner(System.in);
int T=sc.nextInt();
if(T<=1000){
System.out.println("YES");
}
else{
System.out.println("NO");
}
}
}

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##### Conclusion:

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This Problem is intended for audiences of all experiences who are interested in learning about Data Science in a business context; there are no prerequisites.

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