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# Alphabet Rangoli Hacker Rank Solution – Queslers

## Problem: Alphabet Rangoli Hacker Rank Solution

You are given an integer, N. Your task is to print an alphabet rangoli of size N. (Rangoli is a form of Indian folk art based on creation of patterns.)

Different sizes of alphabet rangoli are shown below:

``````#size 3

----c----
--c-b-c--
c-b-a-b-c
--c-b-c--
----c----

#size 5

--------e--------
------e-d-e------
----e-d-c-d-e----
--e-d-c-b-c-d-e--
e-d-c-b-a-b-c-d-e
--e-d-c-b-c-d-e--
----e-d-c-d-e----
------e-d-e------
--------e--------

#size 10

------------------j------------------
----------------j-i-j----------------
--------------j-i-h-i-j--------------
------------j-i-h-g-h-i-j------------
----------j-i-h-g-f-g-h-i-j----------
--------j-i-h-g-f-e-f-g-h-i-j--------
------j-i-h-g-f-e-d-e-f-g-h-i-j------
----j-i-h-g-f-e-d-c-d-e-f-g-h-i-j----
--j-i-h-g-f-e-d-c-b-c-d-e-f-g-h-i-j--
j-i-h-g-f-e-d-c-b-a-b-c-d-e-f-g-h-i-j
--j-i-h-g-f-e-d-c-b-c-d-e-f-g-h-i-j--
----j-i-h-g-f-e-d-c-d-e-f-g-h-i-j----
------j-i-h-g-f-e-d-e-f-g-h-i-j------
--------j-i-h-g-f-e-f-g-h-i-j--------
----------j-i-h-g-f-g-h-i-j----------
------------j-i-h-g-h-i-j------------
--------------j-i-h-i-j--------------
----------------j-i-j----------------
------------------j------------------``````

The center of the rangoli has the first alphabet letter a, and the boundary has the Nth alphabet letter (in alphabetical order).

#### Input Format

Only one line of input containing N, the size of the rangoli.

0 < N < 27

#### Output Format

Print the alphabet rangoli in the format explained above.

Sample Input

``5``

Sample Output

``````--------e--------
------e-d-e------
----e-d-c-d-e----
--e-d-c-b-c-d-e--
e-d-c-b-a-b-c-d-e
--e-d-c-b-c-d-e--
----e-d-c-d-e----
------e-d-e------
--------e--------``````

### Alphabet Rangoli Hacker Rank Solution in Python 2

``````from copy import deepcopy
N = int(raw_input())
row = 2 * (N - 1) + 1
col = (N - 1) * 4 + 1
arr = ['-'] * col
res = []
for _ in xrange(row): res.append(deepcopy(arr))
mr = row / 2
mc = col / 2
for i in xrange(mr + 1):
ch = ord('a') + i
for j in xrange(N - i):
res[mr - i][mc - 2 * j] = chr(ch + j)
res[mr - i][mc + 2 * j] = chr(ch + j)
res[mr + i][mc - 2 * j] = chr(ch + j)
res[mr + i][mc + 2 * j] = chr(ch + j)
for r in res:
print ''.join(r)``````

### Alphabet Rangoli Hacker Rank Solution in Python 3

``````def print_rangoli(size):
alpha = "abcdefghijklmnopqrstuvwxyz"
data = [alpha[i] for i in range(n)]
items = list(range(n))
items = items[:-1]+items[::-1]
for i in items:
temp = data[-(i+1):]
row = temp[::-1]+temp[1:]
print("-".join(row).center(n*4-3, "-"))``````

### Alphabet Rangoli Hacker Rank Solution in pypy

``````import string
def print_rangoli(size):
alpha = string.ascii_lowercase
n = size
L = []
for i in range(n):
s = "-".join(alpha[i:n])
L.append((s[::-1]+s[1:]).center(4*n-3, "-"))
print('\n'.join(L[:0:-1]+L))``````

### Alphabet Rangoli Hacker Rank Solution in pypy3

``````import string
alpha = string.ascii_lowercase

n = int(input())
L = []
for i in range(n):
s = "-".join(alpha[i:n])
L.append((s[::-1]+s[1:]).center(4*n-3, "-"))
print('\n'.join(L[:0:-1]+L))``````
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