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Alternating Divisibility CodeChef Solution
Problem -Alternating Divisibility CodeChef Solution
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Alternating Divisibility CodeChef Solution in C++17
#include <iostream>
using namespace std;
int main() {
// your code goes here
long long t;
cin>>t;
while(t--){
long long n;
cin>>n;
for(int i=1; i<=n; i++){
if(i%2==0){
cout<<(i-1)*2<<" ";
}
else{
cout<<i<<" ";
}
}
cout<<endl;
}
return 0;
}Alternating Divisibility CodeChef Solution in C++14
#include <iostream>
using namespace std;
int main() {
// your code goes here
long long t;
cin>>t;
while(t--){
long long n;
cin>>n;
for(int i=1; i<=n; i++){
if(i%2==0){
cout<<(i-1)*2<<" ";
}
else{
cout<<i<<" ";
}
}
cout<<endl;
}
return 0;
}Alternating Divisibility CodeChef Solution in PYTH 3
# cook your dish here
for _ in range(int(input())):
n = int(input())
ans = []
for i in range(1,n+1):
if i % 2 == 1:
ans.append(i)
elif i % 2 == 0:
ans.append((i-1)*2)
print(*ans)Alternating Divisibility CodeChef Solution in C
#include<stdio.h>
void solve(){
int n;
scanf("%d",&n);
int a[n];
int temp = 1;
if(n == 1) {
printf("1\n");
return;
}
for(int i =0 ; i<n-1 ; i+=2) {
a[i] = temp;a[i+1] = 2*temp;temp += 2;
}
if(n%2 != 0) {a[n-1] = a[n-2] + 1;}
for(int i =0 ; i < n ; ++i) {
printf("%d ",a[i]);
}
printf("\n");
}
int main() {
int t;
scanf("%d",&t);
while(t--){
solve();
}
return 0;
}Alternating Divisibility CodeChef Solution in JAVA
/* package codechef; // don't place package name! */
import java.util.*;
import java.lang.*;
import java.io.*;
/* Name of the class has to be "Main" only if the class is public. */
class Codechef
{
public static void main (String[] args) throws java.lang.Exception
{
BufferedReader reader=new BufferedReader(new InputStreamReader(System.in));
BufferedWriter writer=new BufferedWriter(new OutputStreamWriter(System.out));
int tt=Integer.parseInt(reader.readLine().trim());
while(tt-->0){
int n=Integer.parseInt(reader.readLine().trim());
boolean[] used=new boolean[2*n+1];
boolean isFirst=true;
for(int i=1, j=0;j<n;i++){
if(used[i]){
continue;
}
writer.write((isFirst?"":" ")+i);
used[i]=true;
j++;
isFirst=false;
if(j<n){
writer.write(" "+(2*i));
used[2*i]=true;
j++;
}
}
writer.write("\n");
}
writer.flush();
}
private static int[] parseInt(String str) {
String[] parts=str.split("\\s+");
int[] ans=new int[parts.length];
for(int i=0;i<ans.length;i++){
ans[i]=Integer.parseInt(parts[i]);
}
return ans;
}
private static long[] parseLong(String str) {
String[] parts=str.split("\\s+");
long[] ans=new long[parts.length];
for(int i=0;i<ans.length;i++){
ans[i]=Long.parseLong(parts[i]);
}
return ans;
}
}Alternating Divisibility CodeChef Solution in PYPY 3
t = int(input())
M = 10**5
u = [0 for i in range(2 * M + 1)]
a = []
x = 1
while len(a) < M:
while u[x]:
x += 1
a.append(x)
a.append(2 * x)
u[x] = 1
u[2 * x] = 1
for _ in range(t):
n = int(input())
print(*a[:n])Alternating Divisibility CodeChef Solution in PYTH
t = int(raw_input())
for i in range(t):
N = int(raw_input())
st = ''
v = 1
k = 0
while k < N:
k += 1
if k%2 == 1:
st += str(v) + ' '
else:
st += str(v*2) + ' '
v += 2
# endif
# endwhile
print st
# endfor i
Alternating Divisibility CodeChef Solution in C#
using System;
using System.Linq;
using System.Collections.Generic;
using System.Text.RegularExpressions;
using System.Text;
using System.Numerics;
public class Test
{
public static int GetInt() => int.Parse(Console.ReadLine());
public static long GetLong() => long.Parse(Console.ReadLine());
public static int[] GetIntArray() => Console.ReadLine().Trim().Split(' ').Select(int.Parse).ToArray();
public static long[] GetLongArray() => Console.ReadLine().Trim().Split(' ').Select(long.Parse).ToArray();
public static string[] GetLines(int n)
{
var ans = new string[n];
for(int i=0; i<n; i++)
{
ans[i] = Console.ReadLine();
}
return ans;
}
public static int Gcd(int a, int b) => b == 0 ? a : Gcd(b, a%b);
public static int Gcd(int[] n) => n.Aggregate((a,b) => Gcd(a,b));
public static void Main()
{
var t=GetInt(); for(int i = 0; i<t; i++) { Solve(); }
// Solve();
}
public static void Solve()
{
int n = GetInt();
int[] a = new int[n];
// 1 2 3 6 4 8 5 10
for(int i=0; i<n; i++)
{
if(i%2 == 0)
{
int v = i/2;
a[i] = 2*v+1;
} else
a[i] = 2*a[i-1];
}
// Console.WriteLine("Check : " + Check(a));
string ans = string.Join(" ",a);
Console.WriteLine(ans);
}
public static bool Check(int[] a)
{
for(int i=0; i<a.Length-1; i++)
{
if(a[i] > 2*a.Length)
return false;
if(i%2 == 0 && a[i+1]%a[i] != 0)
return false;
if(i%2 == 1 && a[i+1]%a[i] == 0)
return false;
}
return true;
}
}Alternating Divisibility CodeChef Solution in GO
package main
import (
"bufio"
"bytes"
"fmt"
"os"
)
func main() {
reader := bufio.NewReader(os.Stdin)
tc := readNum(reader)
var buf bytes.Buffer
for tc > 0 {
tc--
n := readNum(reader)
res := solve(n)
for i := 0; i < n; i++ {
buf.WriteString(fmt.Sprintf("%d ", res[i]))
}
buf.WriteByte('\n')
}
fmt.Print(buf.String())
}
func readUint64(bytes []byte, from int, val *uint64) int {
i := from
var tmp uint64
for i < len(bytes) && bytes[i] >= '0' && bytes[i] <= '9' {
tmp = tmp*10 + uint64(bytes[i]-'0')
i++
}
*val = tmp
return i
}
func readInt(bytes []byte, from int, val *int) int {
i := from
sign := 1
if bytes[i] == '-' {
sign = -1
i++
}
tmp := 0
for i < len(bytes) && bytes[i] >= '0' && bytes[i] <= '9' {
tmp = tmp*10 + int(bytes[i]-'0')
i++
}
*val = tmp * sign
return i
}
func readString(reader *bufio.Reader) string {
s, _ := reader.ReadString('\n')
for i := 0; i < len(s); i++ {
if s[i] == '\n' {
return s[:i]
}
}
return s
}
func readNum(reader *bufio.Reader) (a int) {
bs, _ := reader.ReadBytes('\n')
readInt(bs, 0, &a)
return
}
func readTwoNums(reader *bufio.Reader) (a int, b int) {
res := readNNums(reader, 2)
a, b = res[0], res[1]
return
}
func readThreeNums(reader *bufio.Reader) (a int, b int, c int) {
res := readNNums(reader, 3)
a, b, c = res[0], res[1], res[2]
return
}
func readNNums(reader *bufio.Reader, n int) []int {
res := make([]int, n)
x := 0
bs, _ := reader.ReadBytes('\n')
for i := 0; i < n; i++ {
for x < len(bs) && (bs[x] < '0' || bs[x] > '9') && bs[x] != '-' {
x++
}
x = readInt(bs, x, &res[i])
}
return res
}
func solve(n int) []int {
res := make([]int, n)
for i := 1; i <= n; i += 2 {
res[i-1] = 2*(i/2) + 1
}
for i := 2; i <= n; i += 2 {
res[i-1] = 2 * res[i-2]
}
return res
}Alternating Divisibility CodeChef Solution Review:
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