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# Angled Flip CodeChef Solution

## Angled Flip CodeChef Solution in C++17

``````#include <bits/stdc++.h>

#pragma optimization_level 3
#pragma GCC optimize("Ofast,no-stack-protector,unroll-loops,fast-math,O3")
#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx")
#pragma GCC optimize("Ofast")//Comment optimisations for interactive problems (use endl)
#pragma GCC target("avx,avx2,fma")
#pragma GCC optimization ("unroll-loops")

using namespace std;

struct PairHash {inline std::size_t operator()(const std::pair<int, int> &v) const { return v.first * 31 + v.second; }};

// speed
#define Code ios_base::sync_with_stdio(false);
#define By ios::sync_with_stdio(0);
#define Sumfi cout.tie(NULL);

// alias
using ll = long long;
using ld = long double;
using ull = unsigned long long;

// constants
const ld PI = 3.14159265358979323846;  /* pi */
const ll INF = 1e18;
const ld EPS = 1e-9;
const ll MAX_N = 1010101;
const ll mod = 998244353;

// typedef
typedef pair<ll, ll> pll;
typedef vector<pll> vpll;
typedef array<ll,3> all3;
typedef array<ll,5> all5;
typedef vector<all3> vall3;
typedef vector<all5> vall5;
typedef vector<ld> vld;
typedef vector<ll> vll;
typedef vector<vll> vvll;
typedef vector<int> vi;
typedef deque<ll> dqll;
typedef deque<pll> dqpll;
typedef pair<string, string> pss;
typedef vector<pss> vpss;
typedef vector<string> vs;
typedef vector<vs> vvs;
typedef unordered_set<ll> usll;
typedef unordered_set<pll, PairHash> uspll;
typedef unordered_map<ll, ll> umll;
typedef unordered_map<pll, ll, PairHash> umpll;

// macros
#define rep(i,m,n) for(ll i=m;i<n;i++)
#define rrep(i,m,n) for(ll i=n;i>=m;i--)
#define all(a) begin(a), end(a)
#define rall(a) rbegin(a), rend(a)
#define ZERO(a) memset(a,0,sizeof(a))
#define MINUS(a) memset(a,0xff,sizeof(a))
#define INF(a) memset(a,0x3f3f3f3f3f3f3f3fLL,sizeof(a))
#define ASCEND(a) iota(all(a),0)
#define sz(x) ll((x).size())
#define BIT(a,i) (a & (1ll<<i))
#define BITSHIFT(a,i,n) (((a<<i) & ((1ll<<n) - 1)) | (a>>(n-i)))
#define pyes cout<<"YES\n";
#define pno cout<<"NO\n";
#define endl "\n"
#define pneg1 cout<<"-1\n";
#define ppossible cout<<"Possible\n";
#define pimpossible cout<<"Impossible\n";
#define TC(x) cout<<"Case #"<<x<<": ";
#define X first
#define Y second

// utility functions
template <typename T>
void print(T &&t)  { cout << t << "\n"; }
template<typename T>
void printv(vector<T>v){ll n=v.size();rep(i,0,n){cout<<v[i];if(i+1!=n)cout<<' ';}cout<<endl;}
template<typename T>
void printvln(vector<T>v){ll n=v.size();rep(i,0,n)cout<<v[i]<<endl;}
void fileIO(string in = "input.txt", string out = "output.txt") {freopen(in.c_str(),"r",stdin); freopen(out.c_str(),"w",stdout);}
template<typename T>
template<typename T, typename U>
template<typename T, typename U>

struct Combination {
vll fac, inv;
ll n, MOD;

ll modpow(ll n, ll x, ll MOD = mod) { if(!x) return 1; ll res = modpow(n,x>>1,MOD); res = (res * res) % MOD; if(x&1) res = (res * n) % MOD; return res; }

Combination(ll _n, ll MOD = mod): n(_n + 1), MOD(MOD) {
inv = fac = vll(n,1);
rep(i,1,n) fac[i] = fac[i-1] * i % MOD;
inv[n - 1] = modpow(fac[n - 1], MOD - 2, MOD);
rrep(i,1,n - 2) inv[i] = inv[i + 1] * (i + 1) % MOD;
}

ll fact(ll n) {return fac[n];}
ll nCr(ll n, ll r) {
if(n < r or n < 0 or r < 0) return 0;
return fac[n] * inv[r] % MOD * inv[n-r] % MOD;
}
};

struct Matrix {
ll r,c;
vvll matrix;
Matrix(ll r, ll c, ll v = 0): r(r), c(c), matrix(vvll(r,vll(c,v))) {}

Matrix operator*(const Matrix& B) const {
Matrix res(r, B.c);
rep(i,0,r) rep(j,0,B.c) rep(k,0,B.r) {
res.matrix[i][j] = (res.matrix[i][j] + matrix[i][k] * B.matrix[k][j] % mod) % mod;
}
return res;
}

Matrix copy() {
Matrix copy(r,c);
copy.matrix = matrix;
return copy;
}

Matrix pow(ll n) {
assert(r == c);
Matrix res(r,r);
Matrix now = copy();
rep(i,0,r) res.matrix[i][i] = 1;
while(n) {
if(n & 1) res = res * now;
now = now * now;
n /= 2;
}
return res;
}
};

// geometry data structures
template <typename T>
struct Point {
T y,x;
Point(T y, T x) : y(y), x(x) {}
Point(pair<T,T> p) : y(p.first), x(p.second) {}
Point() {}
void input() {cin>>y>>x;}
friend ostream& operator<<(ostream& os, const Point<T>& p) { os<<p.y<<' '<<p.x<<'\n'; return os;}
Point<T> operator+(Point<T>& p) {return Point<T>(y + p.y, x + p.x);}
Point<T> operator-(Point<T>& p) {return Point<T>(y - p.y, x - p.x);}
Point<T> operator*(ll n) {return Point<T>(y*n,x*n); }
Point<T> operator/(ll n) {return Point<T>(y/n,x/n); }
bool operator<(const Point &other) const {if (x == other.x) return y < other.y;return x < other.x;}
Point<T> rotate(Point<T> center, ld angle) {
ld si = sin(angle * PI / 180.), co = cos(angle * PI / 180.);
ld y = this->y - center.y;
ld x = this->x - center.x;

return Point<T>(y * co - x * si + center.y, y * si + x * co + center.x);
}
ld distance(Point<T> other) {
T dy = abs(this->y - other.y);
T dx = abs(this->x - other.x);
return sqrt(dy * dy + dx * dx);
}

T norm() { return x * x + y * y; }
};

template<typename T>
struct Line {
Point<T> A, B;
Line(Point<T> A, Point<T> B) : A(A), B(B) {}
Line() {}

void input() {
A = Point<T>();
B = Point<T>();
A.input();
B.input();
}

T ccw(Point<T> &a, Point<T> &b, Point<T> &c) {
T res = a.x * b.y + b.x * c.y + c.x * a.y;
res -= (a.x * c.y + b.x * a.y + c.x * b.y);
return res;
}

bool isIntersect(Line<T> o) {
T p1p2 = ccw(A,B,o.A) * ccw(A,B,o.B);
T p3p4 = ccw(o.A,o.B,A) * ccw(o.A,o.B,B);
if (p1p2 == 0 && p3p4 == 0) {
pair<T,T> p1(A.y, A.x), p2(B.y,B.x), p3(o.A.y, o.A.x), p4(o.B.y, o.B.x);
if (p1 > p2) swap(p2, p1);
if (p3 > p4) swap(p3, p4);
return p3 <= p2 && p1 <= p4;
}
return p1p2 <= 0 && p3p4 <= 0;
}

pair<bool,Point<ld>> intersection(Line<T> o) {
if(!this->intersection(o)) return {false, {}};
ld det = 1. * (o.B.y-o.A.y)*(B.x-A.x) - 1.*(o.B.x-o.A.x)*(B.y-A.y);
ld t = ((o.B.x-o.A.x)*(A.y-o.A.y) - (o.B.y-o.A.y)*(A.x-o.A.x)) / det;
return {true, {A.y + 1. * t * (B.y - A.y), B.x + 1. * t * (B.x - A.x)}};
}

//@formula for : y = ax + b
//@return {a,b};
pair<ld, ld> formula() {
T y1 = A.y, y2 = B.y;
T x1 = A.x, x2 = B.x;
if(y1 == y2) return {1e9, 0};
if(x1 == x2) return {0, 1e9};
ld a = 1. * (y2 - y1) / (x2 - x1);
ld b = -x1 * a + y1;
return {a, b};
}
};

template<typename T>
struct Circle {
Point<T> center;
Circle() {}

void input() {
center = Point<T>();
center.input();
}

bool circumference(Point<T> p) {
return (center.x - p.x) * (center.x - p.x) + (center.y - p.y) * (center.y - p.y) == radius * radius;
}

bool intersect(Circle<T> c) {
T d = (center.x - c.center.x) * (center.x - c.center.x) + (center.y - c.center.y) * (center.y - c.center.y);
}

bool include(Circle<T> c) {
T d = (center.x - c.center.x) * (center.x - c.center.x) + (center.y - c.center.y) * (center.y - c.center.y);
}
};

ll __gcd(ll x, ll y) { return !y ? x : __gcd(y, x % y); }
all3 __exgcd(ll x, ll y) { if(!y) return {x,1,0}; auto [g,x1,y1] = __exgcd(y, x % y); return {g, y1, x1 - (x/y) * y1}; }
ll __lcm(ll x, ll y) { return x / __gcd(x,y) * y; }
ll modpow(ll n, ll x, ll MOD = mod) { n%=MOD; if(!x) return 1; ll res = modpow(n,x>>1,MOD); res = (res * res) % MOD; if(x&1) res = (res * n) % MOD; return res; }

bool solve(vvll A, vvll B) {
if(sz(A) == 1 or sz(A[0]) == 1) return A == B;
umll freq1, freq2;
rep(i,0,sz(A)) {
bool fl = i % 2;
rep(j,0,sz(A[0])) {
if(fl) {
freq1[A[i][j]] += 1;
freq1[B[i][j]] -= 1;
} else {
freq2[A[i][j]] += 1;
freq2[B[i][j]] -= 1;
}
fl = !fl;
}
}
for(auto& [_,v] : freq1) if(v) return false;
for(auto& [_,v] : freq2) if(v) return false;
return true;
}
int main() {
Code By Sumfi
cout.precision(12);
ll tc = 1;
cin>>tc;
rep(i,1,tc+1) {
ll n,m;
cin>>n>>m;
vvll A(n,vll(m)), B(n,vll(m));
if(solve(A,B)) pyes else pno
}
return 0;
}``````

## Angled Flip CodeChef Solution in C++14

``````#include <bits/stdc++.h>
#define int long long int
#define debug cout<<"K"
#define mod 1000000007

using namespace std;

int32_t main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
int t;
cin>>t;
while(t--)
{
int n,m;
cin>>n>>m;
vector<vector<int>>a(n,vector <int>(m));
vector<vector<int>>b(n,vector <int>(m));
for(int i=0;i<n;i++)
{
for(int j=0;j<m;j++)
cin>>a[i][j];
}
for(int i=0;i<n;i++)
{
for(int j=0;j<m;j++)
cin>>b[i][j];
}
if(n==1||m==1)
{
if(a==b)
cout<<"YES\n";
else
cout<<"NO\n";
continue;
}
multiset<int>black1,black2,white1,white2;
for(int i=0;i<n;i++)
{
for(int j=0;j<m;j++)
{
if((i+j)%2==0)
{
black1.insert(a[i][j]);
black2.insert(b[i][j]);
}
else
{
white1.insert(a[i][j]);
white2.insert(b[i][j]);
}
}
}
if(black1==black2&&white1==white2)
cout<<"YES\n";
else
cout<<"NO\n";

}
return 0;
}``````

## Angled Flip CodeChef Solution in PYTH 3

``````# cook your dish here

for i in range(int(input())):
n,m = map(int,input().split())
a = []
b = []
for i in range(n):
a.append(list(map(int,input().split())))
for i in range(n):
b.append(list(map(int,input().split())))

if m==1 or n==1:
if a==b:
print("YES")
else:
print("NO")
else:
a1=[]
a2=[]
b1=[]
b2=[]
for i in range(n):
for j in range(m):
if (i+j)%2==0:
a1.append(a[i][j])
b1.append(b[i][j])
else:
a2.append(a[i][j])
b2.append(b[i][j])
a1.sort()
b1.sort()
a2.sort()
b2.sort()
if a1==b1 and a2==b2:
print("YES")
else:
print("NO")``````

## Angled Flip CodeChef Solution in C

``````#include <stdio.h>
#include <stdlib.h>
long long cmpfunc (const void * a, const void * b) {
return ( *(long long*)a - *(long long*)b );
}
int main(void) {
int t;
scanf("%d",&t);
l1:while (t--)
{
long long x ,y,a[100000000],b[100000000],c[100000000],d[100000000],i,j,e,f,k,l,m,n,l1=0,l2=0,l3=0,l4=0,flag1=1,flag2=1,flag3=1;
scanf("%lld%lld",&x,&y);
if(x==1||y==1)
{
k=0;
for(i=0;i<x;++i)
{
for(j=0;j<y;++j)
{
scanf("%lld",&a[k]);
k++;
}
}
l=0;
for(i=0;i<x;++i)
{
for(j=0;j<y;++j)
{
scanf("%lld",&b[l]);
l++;
}
}
for(i=0;i<(x*y);i++)
if(a[i]!=b[i])
flag3=0;
if(flag3)
printf("YES\n");
else
printf("NO\n");
goto l1;
}
k=0;
l=0;
for(i=0;i<x;++i)
{
for(j=0;j<y;++j)
{
if((i^j)%2)
{
scanf("%lld",&a[k]);
k++;
l1++;
}
else
{
scanf("%lld",&b[l]);
l++;
l2++;
}
}
}
m=0;
n=0;
for(i=0;i<x;++i)
{
for(j=0;j<y;++j)
{
if((i^j)%2)
{
scanf("%lld",&c[m]);
m++;
l3++;
}
else
{
scanf("%lld",&d[n]);
n++;
l4++;
}
}
}
qsort(a, l1, sizeof(long long), cmpfunc);
qsort(b, l2, sizeof(long long), cmpfunc);
qsort(c, l3, sizeof(long long), cmpfunc);
qsort(d, l4, sizeof(long long), cmpfunc);
if(l1!=l3||l2!=l4)
{
printf("NO\n");
goto l1;
}
else
{
for(i=0;i<l1;i++)
if(a[i]!=c[i])
flag1=0;
for(i=0;i<l2;i++)
if(b[i]!=d[i])
flag2=0;
if(flag1&&flag2)
printf("YES\n");
else
printf("NO\n");
}
}
return 0;
}``````

## Angled Flip CodeChef Solution in JAVA

``````/* package codechef; // don't place package name! */

import java.util.*;
import java.lang.*;
import java.io.*;

/* Name of the class has to be "Main" only if the class is public. */
class Codechef
{
static PrintWriter out=new PrintWriter((System.out));
public static void main(String args[])throws IOException
{

while(t-->0)
{
int m = Integer.parseInt(str.nextToken());
int n = Integer.parseInt(str.nextToken());
HashMap<Integer,Integer> black=new HashMap<>();
HashMap<Integer,Integer> white=new HashMap<>();

for(int i=0; i<m; i++){
for(int j=0; j<n; j++){
int d = Math.abs((i-j)) % 2;
int num = Integer.parseInt(str.nextToken());
if(d==0){
black.put(num,black.getOrDefault(num,0) +1);
}else{
white.put(num,white.getOrDefault(num,0) +1);
}
}
}

for(int i=0; i<m; i++){
for(int j=0; j<n; j++){
int d = Math.abs((i-j)) % 2;
int num = Integer.parseInt(str.nextToken());
if(d==0){
black.put(num,black.getOrDefault(num,0) -1);
}else{
white.put(num,white.getOrDefault(num,0) -1);
}

}
}

if(n==1 || m==1){
out.println("NO");
continue;
}

boolean can = true;
for(Integer a: black.keySet()){
if(black.get(a)!=0){
can=false;
break;
}
}
if(!can){
out.println("NO");
continue;
}

for(Integer a: white.keySet()){
if(white.get(a)!=0){
can=false;
break;
}
}
if(!can){
out.println("NO");
}else{
out.println("YES");
}

}
out.close();
}

}``````

## Angled Flip CodeChef Solution in PYPY 3

``````tc = int(input())

for __ in range(tc):
n,m = map(int,input().split())
a=[]
b=[]
for i in range(n):
tmp = list(map(int,input().split()))
a.append(tmp)

for i in range(n):
tmp = list(map(int,input().split()))
b.append(tmp)

black1,black2,white1,white2=[],[],[],[]

if n==1 or m==1:
if a==b:
print("YES")
else:
print("NO")
continue

for i in range(n):
for j in range(m):
if (i+j)%2==0:
white1.append(a[i][j])
white2.append(b[i][j])
else:
black1.append(a[i][j])
black2.append(b[i][j])

white1.sort()
white2.sort()
black1.sort()
black2.sort()
if white1==white2 and black1==black2:
print("YES")
else:
print("NO")

``````

## Angled Flip CodeChef Solution in PYTH

``````class p3:
def __init__(self, n, m, a, b):
self.n = n
self.m = m
self.a = a
self.b = b

def solve(self):
if self.n == 1 or self.m == 1:
if self.a == self.b:
return 'YES'
else:
return 'NO'
a_odd = [0] * (self.n * self.m // 2)
b_odd = [0] * (self.n * self.m // 2)
if self.n * self.m % 2 == 1:
a_even = [0] * (len(a_odd) + 1)
b_even = [0] * (len(b_odd) + 1)
else:
a_even = [0] * len(a_odd)
b_even = [0] * len(b_odd)
po = 0
pe = 0
for i in range(0, self.n):
for j in range(0, self.m):
if (i + j) % 2 == 0:
a_even[pe] = self.a[i][j]
pe += 1
else:
a_odd[po] = self.a[i][j]
po += 1
po = 0
pe = 0
for i in range(0, self.n):
for j in range(0, self.m):
if (i + j) % 2 == 0:
b_even[pe] = self.b[i][j]
pe += 1
else:
b_odd[po] = self.b[i][j]
po += 1
a_odd.sort()
b_odd.sort()
a_even.sort()
b_even.sort()
'''
print a_odd
print b_odd
print a_even
print b_even
'''
if a_odd == b_odd and a_even == b_even:
return 'YES'
return 'NO'

def main():
t = int(raw_input())
while t > 0:
t -= 1
(n, m) = (int(x) for x in raw_input().split())
a = [[]] * n
for i in range(0, n):
a[i] = [ int(x) for x in raw_input().split()]
b = [[]] * n
for i in range(0, n):
b[i] = [ int(x) for x in raw_input().split()]
ob = p3(n, m, a, b)
print ob.solve()

if __name__ == '__main__':
main()``````

## Angled Flip CodeChef Solution in C#

``````using System;

public class Test
{
public static bool angledFlip(ref long[][] A, ref long[][] B, int N, int M) {
if (N == 1 || M == 1) return A == B;

long even = 0, odd = 0;
for (int i = 0; i < N; i++) {
for (int j = 0; j < M; j++) {
long tmp = A[i][j] ^ B[i][j];

if (((i + j) & 1) == 1) odd ^= tmp;
else even ^= tmp;
}
}

return even == 0 && odd == 0;
}

public static void Main()
{

while (T-- > 0) {
int N = int.Parse(num[0]);
int M = int.Parse(num[1]);

long[][] A = new long[N][];
for (int i = 0; i < N; i++) {
A[i] = Array.ConvertAll(arr, long.Parse);
}

long[][] B = new long[N][];
for (int i = 0; i < N; i++) {
B[i] = Array.ConvertAll(arr, long.Parse);
}

bool flag = angledFlip(ref A, ref B, N, M);
Console.WriteLine(flag ? "YES" : "NO");
}
}
}``````

## Angled Flip CodeChef Solution in GO

``````package main

import (
"bufio"
"bytes"
"fmt"
"os"
"reflect"
)

func main() {

var buf bytes.Buffer
for tc > 0 {
tc--
A := make([][]int, m)
for i := 0; i < m; i++ {
}
B := make([][]int, m)
for i := 0; i < m; i++ {
}
res := solve(A, B)
if res {
buf.WriteString("YES\n")
} else {
buf.WriteString("NO\n")
}
}
fmt.Print(buf.String())
}

func readUint64(bytes []byte, from int, val *uint64) int {
i := from

var tmp uint64
for i < len(bytes) && bytes[i] >= '0' && bytes[i] <= '9' {
tmp = tmp*10 + uint64(bytes[i]-'0')
i++
}
*val = tmp

return i
}

func readInt(bytes []byte, from int, val *int) int {
i := from
sign := 1
if bytes[i] == '-' {
sign = -1
i++
}
tmp := 0
for i < len(bytes) && bytes[i] >= '0' && bytes[i] <= '9' {
tmp = tmp*10 + int(bytes[i]-'0')
i++
}
*val = tmp * sign
return i
}

for i := 0; i < len(s); i++ {
if s[i] == '\n' || s[i] == '\r' {
return s[:i]
}
}
return s
}

return
}

a, b = res[0], res[1]
return
}

a, b, c = res[0], res[1], res[2]
return
}

res := make([]int, n)
x := 0
for i := 0; i < n; i++ {
for x < len(bs) && (bs[x] < '0' || bs[x] > '9') && bs[x] != '-' {
x++
}
}
return res
}
func solve(A, B [][]int) bool {
m := len(A)
n := len(A[0])
if m == 1 || n == 1 {
return reflect.DeepEqual(A, B)
}
// 奇偶性相同的位置可以随便变化
cnt := make([]map[int]int, 2)
for i := 0; i < 2; i++ {
cnt[i] = make(map[int]int)
}

for i := 0; i < m; i++ {
for j := 0; j < n; j++ {
x := A[i][j]
y := B[i][j]
k := (i + j) % 2
cnt[k][x]++
cnt[k][y]--
}
}

for _, cur := range cnt {
for _, v := range cur {
if v != 0 {
return false
}
}
}
return true
}``````
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