Any or All Hacker Rank Solution – Queslers

Problem : Any or All Hacker Rank Solution

This expression returns True if any element of the iterable is true.
If the iterable is empty, it will return False

Code :

>>> any([1>0,1==0,1<0])
True
>>> any([1<0,2<1,3<2])
False

all()
This expression returns True if all of the elements of the iterable are true. If the iterable is empty, it will return True.

Code :

>>> all(['a'<'b','b'<'c'])
True
>>> all(['a'<'b','c'<'b'])
False

Task :

You are given a space separated list of integers. If all the integers are positive, then you need to check if any integer is a palindromic integer.


Input Format :

The first line contains an integer N. N is the total number of integers in the list.
The second line contains the space separated list of N integers.

Constraints :

  • 0 < N < 100

Output Format :

Print True if all the conditions of the problem statement are satisfied. Otherwise, print False.


Sample Input :

5
12 9 61 5 14 

Sample Output :

True

Explanation :

Condition 1: All the integers in the list are positive.
Condition 2: 5 is a palindromic integer.
Hence, the output is True.
Can you solve this challenge in 3 lines of code or less?
There is no penalty for solutions that are correct but have more than 3 lines.

Any or All Hacker Rank Solution in python 2

# Enter your code here. Read input from STDIN. Print output to STDOUT
def is_pal(n):
    S=str(n)
    return all((s==t for s,t in zip(S,reversed(S))))
def meets_conditions(L):
    if not all((l>0 for l in L)):
        return False
    return bool(any((is_pal(l) for l in L)))

N=int(raw_input())
L=map(int, raw_input().split())
print meets_conditions(L)

Any or All Hacker Rank Solution in python 3

# Enter your code here. Read input from STDIN. Print output to STDOUT
N,n = int(input()),input().split()
print(all([int(i)>0 for i in n]) and any([j == j[::-1] for j in n]))

Any or All Hacker Rank Solution in pypy

# Enter your code here. Read input from STDIN. Print output to STDOUT
N,n = input(),raw_input().split()
print all([int(i)>0 for i in n]) and any([j == j[::-1] for j in n])

Any or All Hacker Rank Solution in pypy 3

# Enter your code here. Read input from STDIN. Print output to STDOUT
n = int(input())
a = list(input().split())
if all(int(x)>0 for x in a) and any(x ==x[::-1] for x in a):
    print ('True')
else: 
    print('False')
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Any or All Hacker Rank Solution Conclusion:

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