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Average Gift CodeChef Solution
Problem -Average Gift CodeChef Solution
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Average Gift CodeChef Solution in C++17
#include <bits/stdc++.h>
using namespace std;
#define for0(i, n) for(int i=0;i<n;i++)
#define for1(i, n) for(int i=1;i<=n;i++)
#define forr0(i, n) for(int i=n-1;i>=0;i--)
#define forr1(i, n) for(int i=n;i>0;i--)
#define forc(i, m, n) for(int i=m; i<n;i++)
#define ll long long
#define fs first
#define se second
#define push push_back
#define pop pop_back
const ll mod1 = 1000000007, mod2 = 998244353;
int main(){
#ifndef ONLINE_JUDGE
freopen("input.txt", "r", stdin);
freopen("output.txt", "w", stdout);
#endif
int t,n,x;
int a[100000];
cin>>t;
while(t--){
cin>>n>>x;
for0(i, n) cin>>a[i];
int m = a[0], M = a[0];
for0(i, n){
m = min(m, a[i]);
M = max(M, a[i]);
}
if(x <= M && x >= m) cout<<"YES"<<endl;
else cout<<"NO"<<endl;
}
return 0;
}Average Gift CodeChef Solution in C++14
#include <bits/stdc++.h>
using namespace std;
#define for0(i, n) for(int i=0;i<n;i++)
#define for1(i, n) for(int i=1;i<=n;i++)
#define forr0(i, n) for(int i=n-1;i>=0;i--)
#define forr1(i, n) for(int i=n;i>0;i--)
#define forc(i, m, n) for(int i=m; i<n;i++)
#define ll long long
#define fs first
#define se second
#define push push_back
#define pop pop_back
const ll mod1 = 1000000007, mod2 = 998244353;
int main(){
#ifndef ONLINE_JUDGE
freopen("input.txt", "r", stdin);
freopen("output.txt", "w", stdout);
#endif
int t,n,x;
int a[100000];
cin>>t;
while(t--){
cin>>n>>x;
for0(i, n) cin>>a[i];
int m = a[0], M = a[0];
for0(i, n){
m = min(m, a[i]);
M = max(M, a[i]);
}
if(x <= M && x >= m) cout<<"YES"<<endl;
else cout<<"NO"<<endl;
}
return 0;
}Average Gift CodeChef Solution in PYTH 3
for _ in range(int(input())):
n,x=map(int,input().split())
s=list(map(int,input().split()))
s.sort()
if s[0]<=x<=s[-1]: print("YES")
else: print("NO")Average Gift CodeChef Solution in C
#include <stdio.h>
int main(void) {
int t, n, x, i, min, max;
scanf("%d", &t);
while(t--){
scanf("%d %d", &n, &x);
int S[n];
for ( i = 0; i < n; i++)
{
scanf("%d", &S[i]);
}
min = S[0];
max = S[0];
for(i=0; i<n; ++i)
{
// scanf("%d", &S[i]);
if(S[i]<min)
min = S[i];
if(S[i]>max)
max = S[i];
}
if(x>=min && x<= max) printf("YES\n");
else printf("NO\n");
//printOutput(x, n, S);
}
return 0;
}
Average Gift CodeChef Solution in JAVA
/* package codechef; // don't place package name! */
import java.util.*;
import java.lang.*;
import java.io.*;
/* Name of the class has to be "Main" only if the class is public. */
class Codechef
{
public static String solve(int[]arr,int n,int x){
// for(int i:arr)if(i==x)return "YES";
int max=0,min=arr[0];
for(int i=0;i<n;i++){
min=Math.min(min,arr[i]);
max=Math.max(max,arr[i]);
}
if(max>=x && x>=min)return "YES";
return "NO";
}
public static void main (String[] args) throws java.lang.Exception
{
// your code goes here
Scanner sc=new Scanner(System.in);
int t=sc.nextInt();
while(t-->0){
int n=sc.nextInt();
int x=sc.nextInt();
int[]arr=new int[n];
for(int i=0;i<n;i++)
arr[i]=sc.nextInt();
System.out.println(solve(arr,n,x));
}
}
}Average Gift CodeChef Solution in PYPY 3
for _ in range(int(input())):
n, x = map(int, input().split())
s = list(map(int, input().split()))
if min(s) <= x <= max(s):
print('YES')
else:
print('NO')
# Proof
# If S contains two elements x-a and x+b (a,b >= 0), then let A be as follows:
# [b copies of (x-a), a copies of (x-b)]. The average will be x. (easy to check)
# So you just need to check if you have two such elements in S. It's enough to check min and max.Average Gift CodeChef Solution in PYTH
T = input()
while T>0:
N,X = map(int,raw_input().split())
S = map(int,raw_input().split())
if X in S: print "YES"
elif max(S)<X: print "NO"
elif min(S)>X: print "NO"
else: print "YES"
T-=1Average Gift CodeChef Solution in C#
using System;
using System.Linq;
using System.Collections.Generic;
using System.Text.RegularExpressions;
using System.Text;
using System.Numerics;
public class Test
{
public static void Main()
{
int A = GetInt();
while(A-- != 0)
{
int[] arr = GetIntArray();
int[] ar2 = GetIntArray();
int maxi=int.MinValue, mini=int.MaxValue;
for(int i=0;i<arr[0];i++){
maxi = Math.Max(maxi, ar2[i]);
mini = Math.Min(mini, ar2[i]);
}
if(arr[1]>=mini && arr[1]<=maxi) Console.WriteLine("YES");
else Console.WriteLine("NO");
}
// your code goes here
}
public static void Writex(string s) => (Console.WriteLine(s));
public static int GetInt() => int.Parse(Console.ReadLine());
public static long GetLong() => long.Parse(Console.ReadLine());
public static string GetString() => (Console.ReadLine());
public static string[] GetStringArray() => Console.ReadLine().Trim().Split(' ');
public static int[] GetIntArray() => Console.ReadLine().Trim().Split(' ').Select(int.Parse).ToArray();
public static long[] GetLongArray() => Console.ReadLine().Trim().Split(' ').Select(long.Parse).ToArray();
}Average Gift CodeChef Solution in NODEJS
process.stdin.resume();
process.stdin.setEncoding('utf8');
let array = "";
process.stdin.on('data', function (line) {
array += line;
});
process.stdin.on('end', function () {
array = array.split("\n");
let cases = parseInt(array.shift());
for (let i = 0; i < cases; i++) {
let newArr=array.shift().split(' ').map(x=>parseInt(x));
let s=array.shift().split(' ').map(x=>parseInt(x));
s.sort((a,b)=>{return a-b});
if(s[0]<=newArr[1] && s[newArr[0]-1]>=newArr[1]){
console.log('YES')
}else{
console.log('NO')
}
}
});Average Gift CodeChef Solution in GO
package main
import (
"bufio"
"bytes"
"fmt"
"os"
"sort"
)
func main() {
reader := bufio.NewReader(os.Stdin)
tc := readNum(reader)
var buf bytes.Buffer
for tc > 0 {
tc--
n, x := readTwoNums(reader)
A := readNNums(reader, n)
res := solve(x, A)
if res {
buf.WriteString("YES\n")
} else {
buf.WriteString("NO\n")
}
}
fmt.Print(buf.String())
}
func readUint64(bytes []byte, from int, val *uint64) int {
i := from
var tmp uint64
for i < len(bytes) && bytes[i] >= '0' && bytes[i] <= '9' {
tmp = tmp*10 + uint64(bytes[i]-'0')
i++
}
*val = tmp
return i
}
func readInt(bytes []byte, from int, val *int) int {
i := from
sign := 1
if bytes[i] == '-' {
sign = -1
i++
}
tmp := 0
for i < len(bytes) && bytes[i] >= '0' && bytes[i] <= '9' {
tmp = tmp*10 + int(bytes[i]-'0')
i++
}
*val = tmp * sign
return i
}
func readString(reader *bufio.Reader) string {
s, _ := reader.ReadString('\n')
for i := 0; i < len(s); i++ {
if s[i] == '\n' {
return s[:i]
}
}
return s
}
func readNum(reader *bufio.Reader) (a int) {
bs, _ := reader.ReadBytes('\n')
readInt(bs, 0, &a)
return
}
func readTwoNums(reader *bufio.Reader) (a int, b int) {
res := readNNums(reader, 2)
a, b = res[0], res[1]
return
}
func readThreeNums(reader *bufio.Reader) (a int, b int, c int) {
res := readNNums(reader, 3)
a, b, c = res[0], res[1], res[2]
return
}
func readNNums(reader *bufio.Reader, n int) []int {
res := make([]int, n)
x := 0
bs, _ := reader.ReadBytes('\n')
for i := 0; i < n; i++ {
for x < len(bs) && (bs[x] < '0' || bs[x] > '9') && bs[x] != '-' {
x++
}
x = readInt(bs, x, &res[i])
}
return res
}
func solve(X int, A []int) bool {
sort.Ints(A)
if X < A[0] || A[len(A)-1] < X {
return false
}
return true
}Average Gift CodeChef Solution Review:
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