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Average Gift CodeChef Solution

Problem -Average Gift CodeChef Solution

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Average Gift CodeChef Solution in C++17

#include <bits/stdc++.h>
using namespace std;

#define for0(i, n) for(int i=0;i<n;i++)
#define for1(i, n) for(int i=1;i<=n;i++)
#define forr0(i, n) for(int i=n-1;i>=0;i--)
#define forr1(i, n) for(int i=n;i>0;i--)
#define forc(i, m, n) for(int i=m; i<n;i++)

#define ll long long
#define fs first
#define se second 
#define push push_back 
#define pop pop_back 

const ll mod1 = 1000000007, mod2 = 998244353;

int main(){
  #ifndef ONLINE_JUDGE
	freopen("input.txt", "r", stdin);
	freopen("output.txt", "w", stdout);
	#endif

  int t,n,x;
  int a[100000];
  cin>>t;
  while(t--){
    cin>>n>>x;
    for0(i, n) cin>>a[i];
    int m = a[0], M = a[0];
    for0(i, n){
      m = min(m, a[i]);
      M = max(M, a[i]);
    }
    if(x <= M && x >= m) cout<<"YES"<<endl;
    else cout<<"NO"<<endl; 
  }
  return 0;
}

Average Gift CodeChef Solution in C++14

#include <bits/stdc++.h>
using namespace std;

#define for0(i, n) for(int i=0;i<n;i++)
#define for1(i, n) for(int i=1;i<=n;i++)
#define forr0(i, n) for(int i=n-1;i>=0;i--)
#define forr1(i, n) for(int i=n;i>0;i--)
#define forc(i, m, n) for(int i=m; i<n;i++)

#define ll long long
#define fs first
#define se second 
#define push push_back 
#define pop pop_back 

const ll mod1 = 1000000007, mod2 = 998244353;

int main(){
  #ifndef ONLINE_JUDGE
	freopen("input.txt", "r", stdin);
	freopen("output.txt", "w", stdout);
	#endif

  int t,n,x;
  int a[100000];
  cin>>t;
  while(t--){
    cin>>n>>x;
    for0(i, n) cin>>a[i];
    int m = a[0], M = a[0];
    for0(i, n){
      m = min(m, a[i]);
      M = max(M, a[i]);
    }
    if(x <= M && x >= m) cout<<"YES"<<endl;
    else cout<<"NO"<<endl; 
  }
  return 0;
}

Average Gift CodeChef Solution in PYTH 3

for _ in range(int(input())):
    n,x=map(int,input().split())
    s=list(map(int,input().split()))
    s.sort()
    if s[0]<=x<=s[-1]: print("YES")
    else: print("NO")

Average Gift CodeChef Solution in C

#include <stdio.h>

int main(void) {
	
	int t, n, x, i, min, max; 
	
	scanf("%d", &t); 
	
	while(t--){
	    
	    scanf("%d %d", &n, &x);
	     
	    int S[n];
		for ( i = 0; i < n; i++)
		{
			scanf("%d", &S[i]);
		}
		min = S[0];
		max = S[0];
		
	    for(i=0; i<n; ++i)
		{
	        // scanf("%d", &S[i]);
	        if(S[i]<min) 
				min = S[i];
	        if(S[i]>max)
				max = S[i];
	    } 
	    
	    if(x>=min && x<= max) printf("YES\n");
	    else printf("NO\n");
	    
	    //printOutput(x, n, S);
	}
	
	return 0;
}

Average Gift CodeChef Solution in JAVA

/* package codechef; // don't place package name! */

import java.util.*;
import java.lang.*;
import java.io.*;

/* Name of the class has to be "Main" only if the class is public. */
class Codechef
{
    public static String solve(int[]arr,int n,int x){
       // for(int i:arr)if(i==x)return "YES";
        int max=0,min=arr[0];
        for(int i=0;i<n;i++){
            min=Math.min(min,arr[i]);
            max=Math.max(max,arr[i]);
        }
        if(max>=x && x>=min)return "YES";
        return "NO";
    }
	public static void main (String[] args) throws java.lang.Exception
	{
		// your code goes here
		Scanner sc=new Scanner(System.in);
		int t=sc.nextInt();
		while(t-->0){
		    int n=sc.nextInt();
		    int x=sc.nextInt();
		    int[]arr=new int[n];
		    for(int i=0;i<n;i++)
		    arr[i]=sc.nextInt();
		    System.out.println(solve(arr,n,x));
		    
		}
	}
}

Average Gift CodeChef Solution in PYPY 3

for _ in range(int(input())):
    n, x = map(int, input().split())
    s = list(map(int, input().split()))
    
    if min(s) <= x <= max(s):
        print('YES')
        
    else:
        print('NO')
        
# Proof
# If S contains two elements x-a and x+b (a,b >= 0), then let A be as follows:
# [b copies of (x-a), a copies of (x-b)]. The average will be x. (easy to check)
# So you just need to check if you have two such elements in S. It's enough to check min and max.

Average Gift CodeChef Solution in PYTH

T = input()
while T>0:
    N,X = map(int,raw_input().split())
    S = map(int,raw_input().split())
    if X in S: print "YES"
    elif max(S)<X: print "NO"
    elif min(S)>X: print "NO"
    else: print "YES"
    T-=1

Average Gift CodeChef Solution in C#

using System;
using System.Linq;
using System.Collections.Generic;
using System.Text.RegularExpressions;
using System.Text;
using System.Numerics;

public class Test
{
	public static void Main()
	{
	    int A = GetInt();
	    while(A-- != 0)
	    {
	    int[] arr = GetIntArray();
	    int[] ar2 = GetIntArray();
	     
	    int maxi=int.MinValue, mini=int.MaxValue;
	    
	    for(int i=0;i<arr[0];i++){
	        maxi = Math.Max(maxi, ar2[i]);
	        mini = Math.Min(mini, ar2[i]);
	    }
	    
	    if(arr[1]>=mini && arr[1]<=maxi) Console.WriteLine("YES");
	    else Console.WriteLine("NO");
	    
	    }
		// your code goes here
	}
	
		public static void Writex(string s) => (Console.WriteLine(s));
	public static int GetInt() => int.Parse(Console.ReadLine());
    public static long GetLong() => long.Parse(Console.ReadLine());
    public static string GetString() => (Console.ReadLine());

    public static string[] GetStringArray() => Console.ReadLine().Trim().Split(' ');
    public static int[] GetIntArray() => Console.ReadLine().Trim().Split(' ').Select(int.Parse).ToArray();
        public static long[] GetLongArray() =>  Console.ReadLine().Trim().Split(' ').Select(long.Parse).ToArray();
}

Average Gift CodeChef Solution in NODEJS

process.stdin.resume();
process.stdin.setEncoding('utf8');
let array = "";
process.stdin.on('data', function (line) {
    array += line;
});
process.stdin.on('end', function () {
    array = array.split("\n");
    let cases = parseInt(array.shift());
    for (let i = 0; i < cases; i++) {
        let newArr=array.shift().split(' ').map(x=>parseInt(x));
        let s=array.shift().split(' ').map(x=>parseInt(x));
        s.sort((a,b)=>{return a-b});
        if(s[0]<=newArr[1] && s[newArr[0]-1]>=newArr[1]){
            console.log('YES')
        }else{
            console.log('NO')
        }
    }
});

Average Gift CodeChef Solution in GO

package main

import (
	"bufio"
	"bytes"
	"fmt"
	"os"
	"sort"
)

func main() {

	reader := bufio.NewReader(os.Stdin)

	tc := readNum(reader)
	var buf bytes.Buffer
	for tc > 0 {
		tc--
		n, x := readTwoNums(reader)
		A := readNNums(reader, n)
		res := solve(x, A)
		if res {
			buf.WriteString("YES\n")
		} else {
			buf.WriteString("NO\n")
		}
	}
	fmt.Print(buf.String())
}

func readUint64(bytes []byte, from int, val *uint64) int {
	i := from

	var tmp uint64
	for i < len(bytes) && bytes[i] >= '0' && bytes[i] <= '9' {
		tmp = tmp*10 + uint64(bytes[i]-'0')
		i++
	}
	*val = tmp

	return i
}

func readInt(bytes []byte, from int, val *int) int {
	i := from
	sign := 1
	if bytes[i] == '-' {
		sign = -1
		i++
	}
	tmp := 0
	for i < len(bytes) && bytes[i] >= '0' && bytes[i] <= '9' {
		tmp = tmp*10 + int(bytes[i]-'0')
		i++
	}
	*val = tmp * sign
	return i
}

func readString(reader *bufio.Reader) string {
	s, _ := reader.ReadString('\n')
	for i := 0; i < len(s); i++ {
		if s[i] == '\n' {
			return s[:i]
		}
	}
	return s
}

func readNum(reader *bufio.Reader) (a int) {
	bs, _ := reader.ReadBytes('\n')
	readInt(bs, 0, &a)
	return
}

func readTwoNums(reader *bufio.Reader) (a int, b int) {
	res := readNNums(reader, 2)
	a, b = res[0], res[1]
	return
}

func readThreeNums(reader *bufio.Reader) (a int, b int, c int) {
	res := readNNums(reader, 3)
	a, b, c = res[0], res[1], res[2]
	return
}

func readNNums(reader *bufio.Reader, n int) []int {
	res := make([]int, n)
	x := 0
	bs, _ := reader.ReadBytes('\n')
	for i := 0; i < n; i++ {
		for x < len(bs) && (bs[x] < '0' || bs[x] > '9') && bs[x] != '-' {
			x++
		}
		x = readInt(bs, x, &res[i])
	}
	return res
}

func solve(X int, A []int) bool {
	sort.Ints(A)

	if X < A[0] || A[len(A)-1] < X {
		return false
	}
	return true
}
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