Balanced Binary Tree LeetCode Solution

Problem – Balanced Binary Tree

Given a binary tree, determine if it is height-balanced.

For this problem, a height-balanced binary tree is defined as:

a binary tree in which the left and right subtrees of every node differ in height by no more than 1.

Example 1:

Input: root = [3,9,20,null,null,15,7]
Output: true

Example 2:

Input: root = [1,2,2,3,3,null,null,4,4]
Output: false

Example 3:

Input: root = []
Output: true


  • The number of nodes in the tree is in the range [0, 5000].
  • -104 <= Node.val <= 104

Balanced Binary Tree LeetCode Solution in Python

class Solution(object):
    def isBalanced(self, root):
        def check(root):
            if root is None:
                return 0
            left  = check(root.left)
            right = check(root.right)
            if left == -1 or right == -1 or abs(left - right) > 1:
                return -1
            return 1 + max(left, right)
        return check(root) != -1

Balanced Binary Tree LeetCode Solution in Java

public boolean isBalanced(TreeNode root) {
        return true;
    return height(root)!=-1;
public int height(TreeNode node){
        return 0;
    int lH=height(node.left);
        return -1;
    int rH=height(node.right);
        return -1;
    if(lH-rH<-1 || lH-rH>1){
        return -1;
    return Math.max(lH,rH)+1;

Balanced Binary Tree LeetCode Solution in C++

class Solution {
    bool ans;
    int checkBalance(TreeNode* root){
            return 0;
        if(!ans) // if Answer is already False then return it.
            return 0;
        int leftSubTree = checkBalance(root->left);
        int rightSubTree = checkBalance(root->right);
        if(abs(leftSubTree-rightSubTree) > 1){
            ans = false;
        return 1 + max(leftSubTree, rightSubTree);
    bool isBalanced(TreeNode* root){
        ans = true;
        int temp = checkBalance(root);
        return ans;
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