Balls and Boxes CodeChef Solution

Problem – Balls and Boxes CodeChef Solution

You have N balls and K boxes. You want to divide the N balls into K boxes such that:

• Each box contains ≥1 balls.
• No two boxes contain the same number of balls.

Determine if it is possible to do so.

Input Format

• The first line contains a single integer T — the number of test cases. Then the test cases follow.
• The first and only line of each test case contains two space-separated integers N and K — the number of balls and the number of boxes respectively.

Output Format

For each test case, output YES if it is possible to divide the N balls into K boxes such that the conditions are satisfied. Otherwise, output NO.

You may print each character of YES and NO in uppercase or lowercase (for example, yes, yEs, Yes will be considered identical).

Constraints

• 1≤T≤10^5
• 1≤N≤10^9
• 1≤K≤10^4

Sample 1:

Input:
4
3 4
30 3
2 2
1 1
Output:
NO
YES
NO
YES

Explanation:

Test Case 1: It is not possible to divide the 3 balls into 4 boxes such that each box contains ≥1 balls.

Test Case 2: One way to divide the 30 balls into 3 boxes is the following: [5,9,16].

Test Case 3: It is not possible to divide the 2 balls into 2 boxes such that no two boxes contain the same number of balls.

Test Case 4: We can divide 1 ball into 1 box.

Balls and Boxes CodeChef Solution in C++17

#include <iostream>
using namespace std;

int main() {
	// your code goes here
	long long int t,n,k,sum;
	cin>>t;
	while(t--)
	{
	    cin>>n>>k;
	    sum=(k*(k+1)/2);
	    if(sum<=n)
	    {
	       cout<<"YES"<<endl;
	    }
	    else
	    {
	         cout<<"NO"<<endl;
	        
	    }
	}
	return 0;
}

Balls and Boxes CodeChef Solution in Java

/* package codechef; // don't place package name! */

import java.util.*;
import java.lang.*;
import java.io.*;

/* Name of the class has to be "Main" only if the class is public. */
class Codechef
{
	public static void main (String[] args) throws java.lang.Exception
	{
		Scanner in = new Scanner(System.in);
		int t = in.nextInt();
		while(t-- > 0)
		{
		    int n = in.nextInt();
		    int k = in.nextInt();
		    
		    if(n >= ((k*(k+1))/2))
		        System.out.println("Yes");
		    else
		        System.out.println("No");
		}
	}
}

Balls and Boxes CodeChef Solution in Pyth 3

# cook your dish here
t = int(input())
for _ in range(t):
    n,k = map(int,input().split())
    if n >= k*(k+1)/2:
        print("YES")
    else:
        print("NO")

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