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# Best Time to Buy and Sell Stock with Cooldown LeetCode Solution

## Problem – Best Time to Buy and Sell Stock with Cooldown

You are given an array `prices` where `prices[i]` is the price of a given stock on the `ith` day.

Find the maximum profit you can achieve. You may complete as many transactions as you like (i.e., buy one and sell one share of the stock multiple times) with the following restrictions:

• After you sell your stock, you cannot buy stock on the next day (i.e., cooldown one day).

Note: You may not engage in multiple transactions simultaneously (i.e., you must sell the stock before you buy again).

Example 1:

``````Input: prices = [1,2,3,0,2]
Output: 3

Example 2:

``````Input: prices = [1]
Output: 0``````

Constraints:

• `1 <= prices.length <= 5000`
• `0 <= prices[i] <= 1000`

### Best Time to Buy and Sell Stock with Cooldown LeetCode Solution in Java

``````public int maxProfit(int[] prices) {
for (int price : prices) {
prev_sell = sell;
sell = Math.max(prev_buy + price, prev_sell);
}
return sell;
}
``````

### Best Time to Buy and Sell Stock with Cooldown LeetCode Solution in C++

``````int maxProfit(vector<int> &prices) {
for (int price : prices) {
prev_sell = sell;
sell = max(prev_buy + price, sell);
}
return sell;
}
``````

### Best Time to Buy and Sell Stock with Cooldown LeetCode Solution in Python

``````def maxProfit(self, prices):
if len(prices) < 2:
return 0
for price in prices:
prev_sell = sell
sell = max(prev_buy + price, prev_sell)
return sell``````
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This Problem is intended for audiences of all experiences who are interested in learning about Data Science in a business context; there are no prerequisites.

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