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You are given an array prices
where prices[i]
is the price of a given stock on the ith
day.
Find the maximum profit you can achieve. You may complete as many transactions as you like (i.e., buy one and sell one share of the stock multiple times) with the following restrictions:
Note: You may not engage in multiple transactions simultaneously (i.e., you must sell the stock before you buy again).
Example 1:
Input: prices = [1,2,3,0,2]
Output: 3
Explanation: transactions = [buy, sell, cooldown, buy, sell]
Example 2:
Input: prices = [1]
Output: 0
Constraints:
1 <= prices.length <= 5000
0 <= prices[i] <= 1000
public int maxProfit(int[] prices) {
int sell = 0, prev_sell = 0, buy = Integer.MIN_VALUE, prev_buy;
for (int price : prices) {
prev_buy = buy;
buy = Math.max(prev_sell - price, prev_buy);
prev_sell = sell;
sell = Math.max(prev_buy + price, prev_sell);
}
return sell;
}
int maxProfit(vector<int> &prices) {
int buy(INT_MIN), sell(0), prev_sell(0), prev_buy;
for (int price : prices) {
prev_buy = buy;
buy = max(prev_sell - price, buy);
prev_sell = sell;
sell = max(prev_buy + price, sell);
}
return sell;
}
def maxProfit(self, prices):
if len(prices) < 2:
return 0
sell, buy, prev_sell, prev_buy = 0, -prices[0], 0, 0
for price in prices:
prev_buy = buy
buy = max(prev_sell - price, prev_buy)
prev_sell = sell
sell = max(prev_buy + price, prev_sell)
return sell
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This Problem is intended for audiences of all experiences who are interested in learning about Data Science in a business context; there are no prerequisites.
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