**Physical Address**

304 North Cardinal St.

Dorchester Center, MA 02124

Two friends Chef and Chefina are currently on floors *A* and *B* respectively. They hear an announcement that prizes are being distributed on the ground floor and so decide to reach the ground floor as soon as possible.

Chef can climb down *X* floors per minute while Chefina can climb down *Y* floors per minute. Determine who will reach the ground floor first. In case both reach the ground floor together, print `Both`

.

- The first line of input will contain a single integer
*T*, denoting the number of test cases. - The first line of each test case contains four space-separated integers
*A*,*B*,*X*, and*Y*— the current floor of Chef, the current floor of Chefina, speed of Chef and speed of Chefina in floors per minute respectively.

For each test case, output on a new line:

`Chef`

if Chef reaches the ground floor first.`Chefina`

if she reaches the ground floor first.`Both`

if both reach the ground floor at the same time.

You may print each character of the string in uppercase or lowercase. For example, the strings `CHEF`

, `chef`

, `Chef`

, and `chEF`

are all considered the same.

- 1≤
*T*≤2500 - 1≤
*A*,*B*≤100 - 1≤
*X*,*Y*≤10

```
Input:
4
2 2 2 2
4 2 1 5
3 2 4 1
3 2 2 1
Output:
Both
Chefina
Chef
Chef
```

**Test case 1:** Chef is on the second floor and has a speed of 2 floors per minute. Thus, Chef takes 1 minute to reach the ground floor. Chefina is on the second floor and and has a speed of 2 floors per minute. Thus, Chefina takes 1 minute to reach the ground floor. Both Chef and Chefina reach the ground floor at the same time.

**Test case 2:** Chef is on the fourth floor and has a speed of 1 floor per minute. Thus, Chef takes 4 minute to reach the ground floor. Chefina is on the second floor and and has a speed of 5 floors per minute. Thus, Chefina takes 0.4 minutes to reach the ground floor. Chefina reaches the ground floor first.

**Test case 3:** Chef is on the third floor and has a speed of 4 floors per minute. Thus, Chef takes 0.75 minutes to reach the ground floor. Chefina is on the second floor and and has a speed of 1 floor per minute. Thus, Chefina takes 2 minutes to reach the ground floor. Chef reaches the ground floor first.

**Test case 4:** Chef is on the third floor and has a speed of 2 floors per minute. Thus, Chef takes 1.5 minutes to reach the ground floor. Chefina is on the second floor and and has a speed of 1 floor per minute. Thus, Chefina takes 2 minutes to reach the ground floor. Chef reaches the ground floor first.

```
# cook your dish here
t=int(input())
for i in range(t):
a,b,x,y=map(int,input().split())
if((a/x)<(b/y)):
print("Chef")
elif((a/x)>(b/y)):
print("chefina")
else:
print("both")
```

```
#include <iostream>
using namespace std;
int main() {
int t;
cin>>t;
for(int i=1; i<=t; i++)
{
float a, b;
cin>>a>>b;
float x, y;
cin>>x>>y;
float t1 = a / x;
float t2 = b / y;
if(t1<t2) cout<<"Chef"<<endl;
else if(t2<t1) cout<<"Chefina"<<endl;
else cout<<"Both"<<endl;
}
return 0;
}
```

```
/* package codechef; // don't place package name! */
import java.util.*;
import java.lang.*;
import java.io.*;
/* Name of the class has to be "Main" only if the class is public. */
class Codechef
{
public static void main (String[] args) throws java.lang.Exception
{
// your code goes here
Scanner sc=new Scanner(System.in);
int t=sc.nextInt();
for(int i=0;i<t;i++){
float A=sc.nextInt();
float B=sc.nextInt();
float X=sc.nextInt();
float Y=sc.nextInt();
if((A/X)<(B/Y)){
System.out.println("chef");
}else if((A/X)==(B/Y)){
System.out.println("Both");
}else{
System.out.println("chefina");
}
}
}
}
```

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