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# Bulls and Cows LeetCode Solution

## Problem – Bulls and Cows LeetCode Solution

You are playing the Bulls and Cows game with your friend.

You write down a secret number and ask your friend to guess what the number is. When your friend makes a guess, you provide a hint with the following info:

• The number of “bulls”, which are digits in the guess that are in the correct position.
• The number of “cows”, which are digits in the guess that are in your secret number but are located in the wrong position. Specifically, the non-bull digits in the guess that could be rearranged such that they become bulls.

Given the secret number `secret` and your friend’s guess `guess`, return the hint for your friend’s guess.

The hint should be formatted as `"xAyB"`, where `x` is the number of bulls and `y` is the number of cows. Note that both `secret` and `guess` may contain duplicate digits.

Example 1:

``````Input: secret = "1807", guess = "7810"
Output: "1A3B"
Explanation: Bulls are connected with a '|' and cows are underlined:
"1807"
|
"7810"``````

Example 2:

``````Input: secret = "1123", guess = "0111"
Output: "1A1B"
Explanation: Bulls are connected with a '|' and cows are underlined:
"1123"        "1123"
|      or     |
"0111"        "0111"
Note that only one of the two unmatched 1s is counted as a cow since the non-bull digits can only be rearranged to allow one 1 to be a bull.
``````

Constraints:

• `1 <= secret.length, guess.length <= 1000`
• `secret.length == guess.length`
• `secret` and `guess` consist of digits only.

## Bulls and Cows LeetCode Solution in Java

``````public String getHint(String secret, String guess) {
int bulls = 0;
int cows = 0;
int[] numbers = new int[10];
for (int i = 0; i<secret.length(); i++) {
if (secret.charAt(i) == guess.charAt(i)) bulls++;
else {
if (numbers[secret.charAt(i)-'0']++ < 0) cows++;
if (numbers[guess.charAt(i)-'0']-- > 0) cows++;
}
}
return bulls + "A" + cows + "B";
}
``````

## Bulls and Cows LeetCode Solution in C++

``````class Solution {
public:
// only contains digits
string getHint(string secret, string guess) {
int aCnt = 0;
int bCnt = 0;
vector<int> sVec(10, 0); // 0 ~ 9 for secret
vector<int> gVec(10, 0); // 0 ~ 9 for guess
if (secret.size() != guess.size() || secret.empty()) { return "0A0B"; }
for (int i = 0; i < secret.size(); ++i) {
char c1 = secret[i]; char c2 = guess[i];
if (c1 == c2) {
++aCnt;
} else {
++sVec[c1-'0'];
++gVec[c2-'0'];
}
}
// count b
for (int i = 0; i < sVec.size(); ++i) {
bCnt += min(sVec[i], gVec[i]);
}
}
};
``````

## Bulls and Cows LeetCode Solution in Python

``````    s, g = Counter(secret), Counter(guess)
a = sum(i == j for i, j in zip(secret, guess))
return '%sA%sB' % (a, sum((s & g).values()) - a)
``````
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