Bytelandian Robots CodeChef Solution

Problem -Bytelandian Robots CodeChef Solution

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Bytelandian Robots CodeChef Solution in C++17

#include <bits/stdc++.h>

#pragma optimization_level 3
#pragma GCC optimize("Ofast,no-stack-protector,unroll-loops,fast-math,O3")
#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx")
#pragma GCC optimize("Ofast")//Comment optimisations for interactive problems (use endl)
#pragma GCC target("avx,avx2,fma")
#pragma GCC optimization ("unroll-loops")

using namespace std;

struct PairHash {inline std::size_t operator()(const std::pair<int, int> &v) const { return v.first * 31 + v.second; }};

// speed
#define Code ios_base::sync_with_stdio(false);
#define By ios::sync_with_stdio(0);
#define Sumfi cout.tie(NULL);

// alias
using ll = long long;
using ld = long double;
using ull = unsigned long long;

// constants
const ld PI = 3.14159265358979323846;  /* pi */
const ll INF = 1e18;
const ld EPS = 1e-9;
const ll MAX_N = 202020;
const ll mod = 7051954;

// typedef
typedef pair<ll, ll> pll;
typedef vector<pll> vpll;
typedef array<ll,3> all3;
typedef array<ll,5> all5;
typedef vector<all3> vall3;
typedef vector<all5> vall5;
typedef vector<ld> vld;
typedef vector<ll> vll;
typedef vector<vll> vvll;
typedef vector<int> vi;
typedef deque<ll> dqll;
typedef deque<pll> dqpll;
typedef pair<string, string> pss;
typedef vector<pss> vpss;
typedef vector<string> vs;
typedef vector<vs> vvs;
typedef unordered_set<ll> usll;
typedef unordered_set<pll, PairHash> uspll;
typedef unordered_map<ll, ll> umll;
typedef unordered_map<pll, ll, PairHash> umpll;

// macros
#define rep(i,m,n) for(ll i=m;i<n;i++)
#define rrep(i,m,n) for(ll i=n;i>=m;i--)
#define all(a) begin(a), end(a)
#define rall(a) rbegin(a), rend(a)
#define ZERO(a) memset(a,0,sizeof(a))
#define MINUS(a) memset(a,0xff,sizeof(a))
#define INF(a) memset(a,0x3f3f3f3f3f3f3f3fLL,sizeof(a))
#define ASCEND(a) iota(all(a),0)
#define sz(x) ll((x).size())
#define BIT(a,i) (a & (1ll<<i))
#define BITSHIFT(a,i,n) (((a<<i) & ((1ll<<n) - 1)) | (a>>(n-i)))
#define pyes cout<<"Yes\n";
#define pno cout<<"No\n";
#define endl "\n"
#define pneg1 cout<<"-1\n";
#define ppossible cout<<"Possible\n";
#define pimpossible cout<<"Impossible\n";
#define TC(x) cout<<"Case #"<<x<<": ";
#define X first
#define Y second

// utility functions
template <typename T>
void print(T &&t)  { cout << t << "\n"; }
template<typename T>
void printv(vector<T>v){ll n=v.size();rep(i,0,n){cout<<v[i];if(i+1!=n)cout<<' ';}cout<<endl;}
template<typename T>
void printvln(vector<T>v){ll n=v.size();rep(i,0,n)cout<<v[i]<<endl;}
void fileIO(string in = "input.txt", string out = "output.txt") {freopen(in.c_str(),"r",stdin); freopen(out.c_str(),"w",stdout);}
void readf() {freopen("", "rt", stdin);}
template<typename T>
void readv(vector<T>& v){rep(i,0,sz(v)) cin>>v[i];}
template<typename T, typename U>
void readp(pair<T,U>& A) {cin>>A.first>>A.second;}
template<typename T, typename U>
void readvp(vector<pair<T,U>>& A) {rep(i,0,sz(A)) readp(A[i]); }
void readvall3(vall3& A) {rep(i,0,sz(A)) cin>>A[i][0]>>A[i][1]>>A[i][2];}
void readvall5(vall5& A) {rep(i,0,sz(A)) cin>>A[i][0]>>A[i][1]>>A[i][2]>>A[i][3]>>A[i][4];}
void readvvll(vvll& A) {rep(i,0,sz(A)) readv(A[i]);}

struct Combination {
    vll fac, inv;
    ll n, MOD;

    ll modpow(ll n, ll x, ll MOD = mod) { if(!x) return 1; ll res = modpow(n,x>>1,MOD); res = (res * res) % MOD; if(x&1) res = (res * n) % MOD; return res; }

    Combination(ll _n, ll MOD = mod): n(_n + 1), MOD(MOD) {
        inv = fac = vll(n,1);
        rep(i,1,n) fac[i] = fac[i-1] * i % MOD;
        inv[n - 1] = modpow(fac[n - 1], MOD - 2, MOD);
        rrep(i,1,n - 2) inv[i] = inv[i + 1] * (i + 1) % MOD;
    }

    ll fact(ll n) {return fac[n];}
    ll nCr(ll n, ll r) {
        if(n < r or n < 0 or r < 0) return 0;
        return fac[n] * inv[r] % MOD * inv[n-r] % MOD;
    }
};

struct Matrix {
    ll r,c;
    vvll matrix;
    Matrix(ll r, ll c, ll v = 0): r(r), c(c), matrix(vvll(r,vll(c,v))) {}

    Matrix operator*(const Matrix& B) const {
        Matrix res(r, B.c);
        rep(i,0,r) rep(j,0,B.c) rep(k,0,B.r) {
                    res.matrix[i][j] = (res.matrix[i][j] + matrix[i][k] * B.matrix[k][j] % mod) % mod;
                }
        return res;
    }

    Matrix copy() {
        Matrix copy(r,c);
        copy.matrix = matrix;
        return copy;
    }

    Matrix pow(ll n) {
        assert(r == c);
        Matrix res(r,r);
        Matrix now = copy();
        rep(i,0,r) res.matrix[i][i] = 1;
        while(n) {
            if(n & 1) res = res * now;
            now = now * now;
            n /= 2;
        }
        return res;
    }
};

// geometry data structures
template <typename T>
struct Point {
    T y,x;
    Point(T y, T x) : y(y), x(x) {}
    Point(pair<T,T> p) : y(p.first), x(p.second) {}
    Point() {}
    void input() {cin>>y>>x;}
    friend ostream& operator<<(ostream& os, const Point<T>& p) { os<<p.y<<' '<<p.x<<'\n'; return os;}
    Point<T> operator+(Point<T>& p) {return Point<T>(y + p.y, x + p.x);}
    Point<T> operator-(Point<T>& p) {return Point<T>(y - p.y, x - p.x);}
    Point<T> operator*(ll n) {return Point<T>(y*n,x*n); }
    Point<T> operator/(ll n) {return Point<T>(y/n,x/n); }
    bool operator<(const Point &other) const {if (x == other.x) return y < other.y;return x < other.x;}
    Point<T> rotate(Point<T> center, ld angle) {
        ld si = sin(angle * PI / 180.), co = cos(angle * PI / 180.);
        ld y = this->y - center.y;
        ld x = this->x - center.x;

        return Point<T>(y * co - x * si + center.y, y * si + x * co + center.x);
    }
    ld distance(Point<T> other) {
        T dy = abs(this->y - other.y);
        T dx = abs(this->x - other.x);
        return sqrt(dy * dy + dx * dx);
    }

    T norm() { return x * x + y * y; }
};

template<typename T>
struct Line {
    Point<T> A, B;
    Line(Point<T> A, Point<T> B) : A(A), B(B) {}
    Line() {}

    void input() {
        A = Point<T>();
        B = Point<T>();
        A.input();
        B.input();
    }

    T ccw(Point<T> &a, Point<T> &b, Point<T> &c) {
        T res = a.x * b.y + b.x * c.y + c.x * a.y;
        res -= (a.x * c.y + b.x * a.y + c.x * b.y);
        return res;
    }

    bool isIntersect(Line<T> o) {
        T p1p2 = ccw(A,B,o.A) * ccw(A,B,o.B);
        T p3p4 = ccw(o.A,o.B,A) * ccw(o.A,o.B,B);
        if (p1p2 == 0 && p3p4 == 0) {
            pair<T,T> p1(A.y, A.x), p2(B.y,B.x), p3(o.A.y, o.A.x), p4(o.B.y, o.B.x);
            if (p1 > p2) swap(p2, p1);
            if (p3 > p4) swap(p3, p4);
            return p3 <= p2 && p1 <= p4;
        }
        return p1p2 <= 0 && p3p4 <= 0;
    }

    pair<bool,Point<ld>> intersection(Line<T> o) {
        if(!this->intersection(o)) return {false, {}};
        ld det = 1. * (o.B.y-o.A.y)*(B.x-A.x) - 1.*(o.B.x-o.A.x)*(B.y-A.y);
        ld t = ((o.B.x-o.A.x)*(A.y-o.A.y) - (o.B.y-o.A.y)*(A.x-o.A.x)) / det;
        return {true, {A.y + 1. * t * (B.y - A.y), B.x + 1. * t * (B.x - A.x)}};
    }

    //@formula for : y = ax + b
    //@return {a,b};
    pair<ld, ld> formula() {
        T y1 = A.y, y2 = B.y;
        T x1 = A.x, x2 = B.x;
        if(y1 == y2) return {1e9, 0};
        if(x1 == x2) return {0, 1e9};
        ld a = 1. * (y2 - y1) / (x2 - x1);
        ld b = -x1 * a + y1;
        return {a, b};
    }
};

template<typename T>
struct Circle {
    Point<T> center;
    T radius;
    Circle(T y, T x, T radius) : center(Point<T>(y,x)), radius(radius) {}
    Circle(Point<T> center, T radius) : center(center), radius(radius) {}
    Circle() {}

    void input() {
        center = Point<T>();
        center.input();
        cin>>radius;
    }

    bool circumference(Point<T> p) {
        return (center.x - p.x) * (center.x - p.x) + (center.y - p.y) * (center.y - p.y) == radius * radius;
    }

    bool intersect(Circle<T> c) {
        T d = (center.x - c.center.x) * (center.x - c.center.x) + (center.y - c.center.y) * (center.y - c.center.y);
        return (radius - c.radius) * (radius - c.radius) <= d and d <= (radius + c.radius) * (radius + c.radius);
    }

    bool include(Circle<T> c) {
        T d = (center.x - c.center.x) * (center.x - c.center.x) + (center.y - c.center.y) * (center.y - c.center.y);
        return d <= radius * radius;
    }
};

ll __gcd(ll x, ll y) { return !y ? x : __gcd(y, x % y); }
all3 __exgcd(ll x, ll y) { if(!y) return {x,1,0}; auto [g,x1,y1] = __exgcd(y, x % y); return {g, y1, x1 - (x/y) * y1}; }
ll __lcm(ll x, ll y) { return x / __gcd(x,y) * y; }
ll modpow(ll n, ll x, ll MOD = mod) { n%=MOD; if(!x) return 1; ll res = modpow(n,x>>1,MOD); res = (res * res) % MOD; if(x&1) res = (res * n) % MOD; return res; }

ll dp[555][555];

ll solve(string s, ll l, ll a, ll b) {
    ll p = count(all(s),'+'), m = sz(s) - p;
    if(b - a > p or a - b > m) return 0;
    ZERO(dp);
    ll n = sz(s);
    rep(i,0,n + 1) dp[i][m] = 1;
    rep(i,1,n + 1) {
        rep(j,0,n + 1) {
            if(a + j - m < 0 or a + j - m > l) dp[i][j] = 0;
            else {
                ll now = i - 1;
                while(now >= 0 and s[now] != '+') now -= 1;
                if(now >= 0 and j - 1 >= 0) dp[i][j] = (dp[i][j] + dp[now][j-1]) % mod;
                now = i - 1;
                while(now >= 0 and s[now] != '-') now -= 1;
                if(now >= 0 and j + 1 <= n) dp[i][j] = (dp[i][j] + dp[now][j+1]) % mod;
            }
        }
    }
    return dp[n][b-a+m];
}

int main() {
    Code By Sumfi
    cout.precision(12);
    ll tc = 1;
    cin>>tc;
    rep(i,1,tc+1) {
        ll n,l,a,b;
        cin>>n>>l>>a>>b;
        string s;
        cin>>s;
        print(solve(s,l,a,b));
    }
    return 0;
}

Bytelandian Robots CodeChef Solution in C++14

#include <bits/stdc++.h>
using namespace std;

static const int MODULO = 1000000007;
typedef long long int long64;

class IInputReader
{
	public:
		virtual void Get(vector<long64> &vec, int count) = 0;
		virtual istream* Get() = 0;
};

class ConsoleReader : public IInputReader
{
    public:
	    void Get(vector<long64> &vec, int count);
	    virtual istream* Get();
};

void ConsoleReader::Get(vector<long64>& vec, int count)
{
	vec.clear();
	for(auto i = 0; i < count; ++i)
	{
		long64 val;
		cin >> val;
		vec.push_back(val);
	}
};

istream* ConsoleReader::Get()
{
	return &cin;
}

static long64 FastPow(long64 a, int b, int mod)
{
	long64 res = 1;
	while (b != 0)
	{
		if ((b & 1) == 1)
		{
			res = (res * a) % mod;
		}
		a = (a * a) % mod;
		b >>= 1;
	}

	return res;
}

static long64 ModularMultiplicativeInverse(long64 a, int mod)
{
	return FastPow(a, mod - 2, mod);
}

static long64 CnK(int n, int k, int mod, long64* f)
{
	if (k > n)
	{
		return 0;
	}

	return (f[n] * ModularMultiplicativeInverse((f[k] * f[n - k]) % mod, mod)) % mod;
}


static long64 GreatestCommonDivisor(long64 a, long64 b)
{
	if (a == 0)
	{
		return b;
	}
	return GreatestCommonDivisor(b % a, a);
}

static vector<long64> SieveOfEratosthenes(int n)
{
	vector<long64> res;
	vector<bool> prime(n + 1, true);

	for (int p = 2; p * p <= n; p++)
	{
		if (prime[p])
		{
			for (int i = p * p; i <= n; i += p)
			{
				prime[i] = false;
			}
		}
	}

	for (int i = 2; i <= n; i++)
	{
		if (prime[i])
		{
			res.push_back(i);
		}
	}

	return res;
}


int main() {

    auto readerPtr = make_unique<ConsoleReader>();
	auto& reader = *(readerPtr.get());
	auto& in_stream = *(reader.Get());

	int tests;
	in_stream >> tests;

	for (auto t = 0; t < tests; t++)
	{
		int n, l, a, b;
		in_stream >> n >> l >> a >> b;
		string s;
		in_stream >> s;

		int p = 0;
		int m = 0;

		for (const auto& c : s)
		{
			if (c == '+')
			{
				p++;
			}
			else
			{
				m++;
			}
		}

		if (b - a > 0 && b - a > p)
		{
			cout << 0 << endl;
			continue;
		}

		if (a - b > 0 && a - b > m)
		{
			cout << 0 << endl;
			continue;
		}

		constexpr int mod = 7051954;
		vector<vector<long64>> dp(n + 1, vector<long64>(m + p + 1, 0));

		for (auto i = 0; i <= n; i++)
		{
			dp[i][m] = 1;
		}

		for (auto i = 1; i <= n; i++)
		{
			for (auto j = 0; j <= m + p; j++)
			{
				if (a + j - m < 0 || a + j - m > l)
				{
					dp[i][j] = 0;
					continue;
				}


				int curr = i - 1;
				while (curr >= 0 && s[curr] != '+')
				{
					curr--;
				}

				if (curr >= 0 && j - 1 >= 0)
				{
					dp[i][j] += dp[curr][j - 1];
					dp[i][j] %= mod;
				}

				curr = i - 1;
				while (curr >= 0 && s[curr] != '-')
				{
					curr--;
				}

				if (curr >= 0 && j + 1 <= m + p)
				{
					dp[i][j] += dp[curr][j + 1];
					dp[i][j] %= mod;
				}
			}
		}

		cout << dp[n][b - a + m] << endl;
	}

	readerPtr.release();
	return 0;
}

Bytelandian Robots CodeChef Solution in C

#include <stdio.h>
#include <string.h>
#define siz 500

int x[siz+1][1001], y[siz+1];
char z[siz+1];

int main()
{
int fall, n, l, a, b, c, i, j, k, s, q, r;
for(scanf("%d",&fall); fall--;)
	{
	if(scanf("%d %d %d %d %s",&n,&l,&a,&b,z)&&(a-b>siz||b-a>siz))
		{
		puts("0");
		continue;
		}
	for(i=-!!(c=strlen(z)); ++i<c; y[i+1]=(z[i]=='+')?1:-1);
	q=(a<siz)?(siz-a):0;
	r=(l-a<siz)?(siz+l-a):1000;
	for(i=x[0][siz]=1; i<=n; i++)
		for(j=0; j<i; j++)
			{
			for(k=j+1; k<i; k++)
				if(y[k]==((y[i]==1)?1:-1))
					break;
			if(k!=i)
				continue;
			for(k=q-(y[i]==1); ++k<=r-(y[i]==1); x[i][k+((y[i]==1)?1:-1)]+=x[j][k]%7051954);
			}
	for(i=s=0; i<=n; s=(s+x[i++][b-a+siz])%7051954);
	for(printf("%d\n",s+(i=0)); i<=n; i++)
		for(j=0; j<1001; x[i][j++]=0);
	}
return 0;
}

Bytelandian Robots CodeChef Solution in JAVA

import java.util.*;

public class Main
{
	static Scanner sc = new Scanner(System.in);
	
	public static void main(String[] args)
	{
		int T = sc.nextInt();
		while(T-->0)
		{
			solveCase();
		}
	}
	
	private static void solveCase()
	{
		n = sc.nextInt(); L = sc.nextInt();
		a = sc.nextInt(); b = sc.nextInt();
		String mcq = sc.next();
		
		nextPlus = new int[n];
		nextMinus = new int[n];
		int plus = -1, minus = -1;
		for(int i=n-1;i>=0;i--)
		{
			if(mcq.charAt(i)=='+')
				plus = i;
			else
				minus = i;
			nextPlus[i] = plus;
			nextMinus[i] = minus;
		}
		//A.apr(nextPlus);
		//A.apr(nextMinus);
		
		for(int i=0;i<n;i++)
			for(int j=0;j<=2*n;j++)
				memo[i][j] = -1;
		System.out.println(solve(0,0));
	}
	static final int MAX = 500, MOD = 7051954;
	static int n, L, a, b;
	static int[][] memo = new int[MAX][2*MAX+1];
	static int[] nextPlus, nextMinus;
	static int solve(int index, int disp)
	{
		if(index>=n)
			return a+disp==b ? 1 : 0;
		if(a+disp<0 || a+disp>L)
			return 0;
		if(memo[index][disp+n]==-1)
		{
			int res = 0;
			if(a+disp==b)
				res++;
			if(nextPlus[index]!=-1)
				res += solve(nextPlus[index]+1, disp+1);
			if(nextMinus[index]!=-1)
				res += solve(nextMinus[index]+1, disp-1);
			res %= MOD;
			//A.spr(index+":"+disp+"->"+res);
			memo[index][disp+n] = res;
		}
		return memo[index][disp+n];
	}
}

Bytelandian Robots CodeChef Solution in C#

using System;
class Program {
	const int M = 7051954;
	static void Main(string[] args) {
		int n = Int32.Parse(Console.ReadLine());
		for (int i = 0; i < n; i++) {
			string[] sdt = Console.ReadLine().Split(' ');
			int N = Int32.Parse(sdt[0]), L = Int32.Parse(sdt[1]),
				A = Int32.Parse(sdt[2]), B = Int32.Parse(sdt[3]);

			string mcs = Console.ReadLine();
			if (A > N) {
				int d = A-N;
				A -= d;
				B -= d;
				L -= d;
			}
			if (B-A > N || A-B > N) {
				Console.WriteLine(0);
				continue;
			}

			int[][] ct = new int[1001][];
			int[][] ct2 = new int[1001][];
			for (int j = 0; j < 1001; j++) {
				ct[j] = new int[4];
				ct2[j] = new int[4];
			}
			ct[A][0] = 1;
			int min = A, max = A;
			for (int j = 0; j < N; j++) {
				if (mcs[j] == '-') {
					if (min > 0) min--;
					for (int k = min; k < max; k++) {
						ct2[k][0] = (ct[k+1][0]+ct[k+1][1])%M;
						ct2[k][1] = 0;
						ct2[k][2] = (ct[k][2]+ct[k][0])%M;
						ct2[k][3] = (ct[k][3]+ct[k][1])%M;
					}
					ct2[max][0] = 0;
					ct2[max][1] = 0;
					ct2[max][2] = (ct[max][2]+ct[max][0])%M;
					ct2[max][3] = (ct[max][3]+ct[max][1])%M;
				} else {
					if (max < L) max++;
					for (int k = min+1; k <= max; k++) {
						ct2[k][0] = (ct[k-1][0]+ct[k-1][2])%M;
						ct2[k][1] = (ct[k][1]+ct[k][0])%M;
						ct2[k][2] = 0;
						ct2[k][3] = (ct[k][3]+ct[k][2])%M;
					}
					ct2[min][0] = 0;
					ct2[min][1] = (ct[min][1]+ct[min][0])%M;
					ct2[min][2] = 0;
					ct2[min][3] = (ct[min][3]+ct[min][2])%M;
				}
				int[][] swp = ct;
				ct = ct2;
				ct2 = swp;
			}
			Console.WriteLine((ct[B][0]+ct[B][1]+ct[B][2]+ct[B][3])%M);
		}
	}
}

Bytelandian Robots CodeChef Solution in GO

package main

import (
	"bufio"
	"bytes"
	"fmt"
	"os"
)

func main() {
	reader := bufio.NewReader(os.Stdin)

	tc := readNum(reader)
	var buf bytes.Buffer
	for tc > 0 {
		tc--
		first := readNNums(reader, 4)
		second := readString(reader)
		res := solve(first[0], first[1], first[2], first[3], second)
		buf.WriteString(fmt.Sprintln(fmt.Sprintf("%d", res)))
	}
	fmt.Print(buf.String())
}

func readUint64(bytes []byte, from int, val *uint64) int {
	i := from

	var tmp uint64
	for i < len(bytes) && bytes[i] >= '0' && bytes[i] <= '9' {
		tmp = tmp*10 + uint64(bytes[i]-'0')
		i++
	}
	*val = tmp

	return i
}

func readInt(bytes []byte, from int, val *int) int {
	i := from
	sign := 1
	if bytes[i] == '-' {
		sign = -1
		i++
	}
	tmp := 0
	for i < len(bytes) && bytes[i] >= '0' && bytes[i] <= '9' {
		tmp = tmp*10 + int(bytes[i]-'0')
		i++
	}
	*val = tmp * sign
	return i
}

func readString(reader *bufio.Reader) string {
	s, _ := reader.ReadString('\n')
	for i := 0; i < len(s); i++ {
		if s[i] == '\n' || s[i] == '\r' {
			return s[:i]
		}
	}
	return s
}

func readNum(reader *bufio.Reader) (a int) {
	bs, _ := reader.ReadBytes('\n')
	readInt(bs, 0, &a)
	return
}

func readTwoNums(reader *bufio.Reader) (a int, b int) {
	res := readNNums(reader, 2)
	a, b = res[0], res[1]
	return
}

func readThreeNums(reader *bufio.Reader) (a int, b int, c int) {
	res := readNNums(reader, 3)
	a, b, c = res[0], res[1], res[2]
	return
}

func readNNums(reader *bufio.Reader, n int) []int {
	res := make([]int, n)
	x := 0
	bs, _ := reader.ReadBytes('\n')
	for i := 0; i < n; i++ {
		for x < len(bs) && (bs[x] < '0' || bs[x] > '9') && bs[x] != '-' {
			x++
		}
		x = readInt(bs, x, &res[i])
	}
	return res
}

const MOD = 7051954

const MAX_D = 502

func modAdd(a, b int) int {
	a += b
	if a >= MOD {
		a -= MOD
	}
	return a
}

func solve(N, L, A, B int, mcq string) int {
	var left, right int
	for i := 0; i < N; i++ {
		if mcq[i] == '+' {
			right++
		} else {
			left--
		}
	}

	right = min(L-A, right)
	left = max(-A, left)
	if B-A > right || B-A < left {
		return 0
	}

	size := right - left + 1
	dp := make([][]int, size)
	for i := 0; i < size; i++ {
		dp[i] = make([]int, N+1)
	}
	dp[-left][0] = 1

	plus := NewQueue(N)
	minus := NewQueue(N)

	plus.Push(0)
	minus.Push(0)

	for i := 1; i <= N; i++ {
		if mcq[i-1] == '+' {
			for plus.Size() > 0 {
				j := plus.Pop()
				for k := 0; k < size-1; k++ {
					dp[k+1][i] = modAdd(dp[k+1][i], dp[k][j])
				}
			}
		} else {
			for minus.Size() > 0 {
				j := minus.Pop()
				for k := 1; k < size; k++ {
					dp[k-1][i] = modAdd(dp[k-1][i], dp[k][j])
				}
			}
		}
		plus.Push(i)
		minus.Push(i)
	}

	var ans int

	for i := 0; i <= N; i++ {
		ans = modAdd(ans, dp[B-A-left][i])
	}
	return ans
}

type Queue struct {
	arr []int
	pos int
}

func NewQueue(n int) *Queue {
	q := new(Queue)
	q.arr = make([]int, n)
	q.pos = 0
	return q
}

func (q Queue) Size() int {
	return q.pos
}

func (q *Queue) Pop() int {
	res := q.arr[q.pos-1]
	q.pos--
	return res
}

func (q *Queue) Push(v int) {
	q.arr[q.pos] = v
	q.pos++
}

func min(a, b int) int {
	if a <= b {
		return a
	}
	return b
}

func max(a, b int) int {
	if a >= b {
		return a
	}
	return b
}

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