Physical Address
304 North Cardinal St.
Dorchester Center, MA 02124
Chef rented a car for a day.
Usually, the cost of the car is Rs 10 per km. However, since Chef has booked the car for the whole day, he needs to pay for at least 300 kms even if the car runs less than 300 kms.
If the car ran X kms, determine the cost Chef needs to pay.
For each test case, output the cost Chef needs to pay.
Input: 5
800
3
299
301
300
Output: 8000
3000
3000
3010
3000
Test case 1: The car runs for 800 kms. Thus, he needs to pay 800⋅10=8000 rupees.
Test case 2: The car runs for 3 kms. However, since Chef booked the car for whole day, he needs to pay for at least 300 kms. Thus, he needs to pay 300⋅10=3000 rupees.
Test case 3: The car runs for 299 kms. However, since Chef booked the car for whole day, he needs to pay for at least 300 kms. Thus, he needs to pay 300⋅10=3000 rupees.
Test case 4: The car runs for 301 kms. Thus, he needs to pay 301⋅10=3010 rupees.
Test case 5: The car runs for 300 kms. Thus, he needs to pay 300⋅10=3000 rupees.
#include <iostream>
using namespace std;
int main() {
int t,n;
int mcost=3000;
int cpkm=10;
cin>>t;
for(int i=0;i<t;i++){
cin>>n;
if(n<=300){
cout<<mcost<<endl;
}
else{
cout<<cpkm*n<<endl;
}
}
return 0;
}
T = int(input())
for i in range(T):
x = int(input())
if (x <=300):
x = 300
a = x*10
print(a)
else:
a = x*10
print(a)
import java.util.*;
import java.lang.*;
import java.io.*;
class Codechef
{
public static void main (String[] args) throws java.lang.Exception
{
Scanner sc=new Scanner(System.in);
int t=sc.nextInt();
while(t-->0)
{
int drive=sc.nextInt();
if(drive<=300)
{
System.out.println("3000");
}else{
int cost_to_pay=drive*10;
System.out.println(cost_to_pay);
}
}
}
}
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