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# Chairs Requirement CodeChef Solution

## Problem – Chairs Requirement CodeChef Solution

Chef’s coding class is very famous in Chefland.

This year X students joined his class and each student will require one chair to sit on. Chef already has Y chairs in his class. Determine the minimum number of new chairs Chef must buy so that every student is able to get one chair to sit on.

#### Input Format

• The first line contains a single integer T — the number of test cases. Then the test cases follow.
• The first and only line of each test case contains two integers X and Y — the number of students in the class and the number of chairs Chef already has.

#### Output Format

For each test case, output the minimum number of extra chairs Chef must buy so that every student gets one chair.

#### Constraints

• 1 \leq T \leq 10001≤T≤1000
• 0 \leq X, Y \leq 1000≤X,Y≤100

#### Sample 1:

Input: 4
20 14
41 41
35 0
50 100
Output: 6
0
35
0


#### Explanation:

• Test case 1: There are 20 students in the class and Chef has 14 chairs already. Therefore Chef must buy 6 more chairs.
• Test case 2: There are 41 students in the class and Chef already has exactly 41 chairs. Therefore Chef does not need to buy any more chairs.
• Test case 3: There are 35 students in the class and Chef has no chairs initially. Therefore Chef must buy 35 chairs.

### Chairs Requirement CodeChef Solution in Python3

n=int(input())
for i in range(n):
x,y=map(int,input().split())
if x>y:
print(x-y)
else:
print("0")

### Chairs Requirement CodeChef Solution in C++17

#include <bits/stdc++.h>
using namespace std;
int n,x,y;
int main (){
cin>>n;
while (n--){
cin>>x>>y;
if (x<=y) cout<<0<<endl;
else cout<<x-y<<endl;
}
return 0;
}


### Chairs Requirement CodeChef Solution in Java

import java.util.*;
import java.lang.*;
import java.io.*;

class Codechef
{
public static void main (String[] args) throws java.lang.Exception
{
Scanner sc = new Scanner(System.in);
int t = sc.nextInt();

for (int i = 1; i <= t; i++) {
int x = sc.nextInt();
int y = sc.nextInt();
if (x > y)
System.out.println(x - y);
else System.out.println("0");
}
}
}

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