Chef and Gym CodeChef Solution

Problem – Chef and Gym CodeChef Solution

Chef has decided to join a Gym in ChefLand and if possible, also hire a personal trainer at the gym. The monthly cost of the gym is X and personal training will cost him an additional Y per month. Chef’s total budget per month is only Z. Print 1 if Chef can only join the gym, 2 if he can also have a personal trainer, and 0 if he can’t even join the gym.

Note that if Chef wants to hire a personal trainer, he must join the gym — he cannot hire the trainer without joining the gym.

Input Format

  • The first line of input will contain a single integer T, denoting the number of test cases. Then the test cases follow.
  • Each test case consists of a single line of input containing three space-separated integers X,Y,Z.

Output Format

For each test case, output in a single line 2 if Chef can go to the gym and have a trainer, 1 if Chef can only go to the gym, 0 if he can’t even go to the gym.

Constraints

  • 1≤T≤100
  • 1≤X,Y,Z≤100

Sample 1:

Input: 4
1 2 3
10 12 13
23 1 22
23 1 63
Output: 2
1
0
2

Explanation:

Test case 1: Since the total cost of Chef getting a gym membership and a trainer is 1+2=3 which is equal to his budget of 3, Chef can get both a gym membership and a trainer.

Test case 2: Since the total cost of Chef getting a gym membership and a trainer is 10+12=22 which is greater than his budget of 13, he can’t get both a gym membership and a trainer. However, the cost of the gym membership is 10 which is less than his budget of 13, so Chef can get only a gym membership.

Test case 3: Since the cost of Chef getting a gym membership is 23 which is greater than his budget of 22, Chef can’t even get the gym membership.

Test case 4: The same costs as the previous test, but this time Chef has enough money to afford both the membership and a personal trainer.

Chef and Gym CodeChef Solution in Java

import java.util.*;
import java.lang.*;
import java.io.*;

class Codechef
{
	public static void main (String[] args) throws java.lang.Exception
	{
			Scanner scn= new Scanner(System.in);    //System.in is a standard input stream  
        int T= scn.nextInt();
        
       for(int i=0; i<T; i++){
        int X= scn.nextInt();
        int Y= scn.nextInt();
        int Z= scn.nextInt();
       
        if(Z>=X){
            if(Z==X){
                System.out.println(1);
        }   else if(X+Y<=Z){
                System.out.println(2);
        }
             else{
                System.out.println(1);
        }
        }
        else{
            System.out.println(0);
        }
       }
	}
}

Chef and Gym CodeChef Solution in Pyth 3

T = int(input())
for i in range(T):
    X,Y,Z=map(int,input().split())
    if (X+Y)<=Z:
        print("2")
    elif (X+Y)>=Z and X>Z :
        print("0")
    else:
        print("1")

Chef and Gym CodeChef Solution in C++17

#include <iostream>
using namespace std;

int main() {
    int t; cin>>t; while(t--)
    {
        int a,b,c;
        cin>>a>>b>>c;
        cout<<(c>=a+b ? 2 : (c>=a ? 1 : 0))<<endl;
    }
	// your code goes here
	return 0;
}
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