Chef and Happiness CodeChef Solution

Problem -Chef and Happiness CodeChef Solution

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Chef and Happiness CodeChef Solution in C++14

#include <iostream>
#include<bits/stdc++.h>
using namespace std;

int main() {
	int T;
	cin >> T;
	while(T--){
	    set<int> s;
	    map<int,int> m;
	    int n;
	    cin >> n;
	    int arr[n];
	    int z=0;
	    for(int i=0;i<n;i++){
	        cin >> arr[i];
	    
	       s.insert(arr[i]);
	        
	    }
	    for(auto i:s){
	        if(i<=n){
	        m[arr[(i-1)]]++;
	        }
	    }
	    for(auto i:m){
	        if(i.second>=2){
	            z=1;
	            break;
	        }
	    }
	    if(z==0) cout << "Poor Chef" << endl;
	    else cout << "Truly Happy" << endl;
	    
	    
	}
}

Chef and Happiness CodeChef Solution in PYTH 3


for t in range(int(input())):
    n = int(input())
    l = [int(k) for k in input().split()]
    arr =[]
    for i in range(n):
        arr.append([])
    ans="Poor Chef"
    for i in range(n):
        arr[l[i]-1].append(i+1);
    for i in range(n):
        ctr =0
        for j in arr[i]:
            if(len(arr[j-1])>0):
                ctr=ctr+1
        if(ctr>=2):
            ans="Truly Happy"
            break;
    print(ans)

Chef and Happiness CodeChef Solution in C

#include<stdio.h>
#include<stdlib.h>
#include<string.h>

int main()
{
	int tag,n,*A,*Aa,i,j,k;
	
	
	int lenth[100000];

	scanf("%d",&tag);

	while(tag >0)
	{
		int max=0;
		int flg=1;
		int count=0;
		int vg=0;

		scanf("%d",&n);
		A = (int*)malloc(sizeof(int)*n);
		Aa = (int*)malloc(sizeof(int)*n);
        	j=max;

		memset(lenth,0,sizeof(int)*100000);

		for(i=0; i<n; ++i)
		{
			scanf("%d",A+i);
			if(A[i]>max) max=A[i];
			    ++lenth[A[i]];
		}
		for(i=1; i<=max; ++i)
			lenth[i]+=lenth[i-1];

		for(i=n-1; i>=0; --i)
		{
			Aa[lenth[A[i]]-1]=i;
			--lenth[A[i]];
		}
		
		memset(lenth,0,sizeof(int)*100000);
		//using lenth again...//
		
		for(i=0;i<n; ++i)
			++lenth[A[i]];
		
		for(i=0;i<n-1; ++i)
		{
			if(i==0 || A[Aa[i]]!=A[Aa[i-1]])
			{
				if(lenth[Aa[i]+1]>0)
				    count = 1;
				else
				    count = 0;
			}
			if(A[Aa[i+1]]==A[Aa[i]] && lenth[Aa[i+1]+1]>0)
			    ++count;
			    
			if(count>=2)
			{
				printf("Truly Happy\n");
				flg=0;
				break;
			}
		}
		// if chef is really poor  ...//
		if(flg)
		printf("Poor Chef\n");

	   tag -= 1;
	}
	return 0;
}

Chef and Happiness CodeChef Solution in JAVA

/* package codechef; // don't place package name! */

import java.util.*;
import java.lang.*;
import java.io.*;

/* Name of the class has to be "Main" only if the class is public. */
class Codechef
{
	public static void main (String[] args) throws java.lang.Exception
	{
		// your code goes here
		Scanner sc = new Scanner(System.in);
        int t = sc.nextInt();
        while(t-->0) {
            int n = sc.nextInt();
            HashSet<Integer> set = new HashSet<>();
            HashMap<Integer, Integer> map = new HashMap<>();
            int[] arr = new int[n];
            for (int i = 0; i < n; i++)
                arr[i] = sc.nextInt();
            for (int i = 0; i < n; i++)
                set.add(arr[i]);
            int c=0;
            for (int i = 0; i < n; i++) {
                if(!map.containsKey(arr[i]))
                    map.put(arr[i],i+1);
                else{
                    if(set.contains(map.get(arr[i])) && set.contains(i+1)){
                        c=1; break;
                    }
                    else if(set.contains(i+1))
                        map.replace(arr[i],i+1);
                }
            }
            if(c==1) System.out.println("Truly Happy");
            else
                System.out.println("Poor Chef");
        }
	}
}

Chef and Happiness CodeChef Solution in PYPY 3

# cook your dish here
import math
import sys

def solve(A,n):
    d = {}
    d1 = {}
    
    for i in range(n):
        if A[i] not in d and A[A[i]-1] in d1:
            
            return True
        else:
            d[A[i]] = d.get(A[i],0)+1 
            d1[A[A[i]-1]] = d1.get(A[A[i]-1],0)+1
            
            
    return False



     

try:
    T = int(input())
    for l in range(T):
        
        n = int(input())
        path = [int(i) for i in input().strip().split(" ")]
        if solve(path,n):
            print("Truly Happy")
        else:
            print("Poor Chef")
            
                        
        
            
        
except EOFError:
    pass

            
        

Chef and Happiness CodeChef Solution in PYTH

t = int(raw_input())
for i in range(t):
	N = int(raw_input())
	st = raw_input().split()
	A = []
	S = set()
	for k in range(1,N+1):
		n = int(st[k-1])
		A.append([n,k])
		S.add(n)
	# endfor k
	A.sort()
	A.append([10**6,0])
	valid = False
	p = 0
	while (not valid) and (p < N):
		tot = 0
		n = A[p][0]
		if A[p][1] in S:
			tot += 1
		# endif
		while A[p+1][0] == n:
			p += 1
			if A[p][1] in S:
				tot += 1
			# endif
		# endwhile
		if tot > 1:
			valid = True
		else:
			p += 1
			tot = 0
			n = A[p][0]
			if A[p][1] in S:
				tot += 1
			# endif
		# endif
	# endwhile
	if valid:
		print 'Truly Happy'
	else:
		print 'Poor Chef'
	# endif
# endfor i

Chef and Happiness CodeChef Solution in C#

using System;
using System.Collections.Generic;
using System.Linq;

public class Program
{
	public static void Main()
	{
		int testCases = Convert.ToInt16(Console.ReadLine());

		for (int i = 0; i < testCases; i++)
		{
			bool wins = IsHappy();
			Console.WriteLine(wins ? "Truly Happy" : "Poor Chef");
		}
	}

	public static bool IsHappy()
	{
		int sequenceLen = int.Parse(Console.ReadLine());
		var sequence = Console.ReadLine().Split(' ').Select(int.Parse).ToList();
		var hSet = new HashSet<int>(sequence);
		var hSet1 = new HashSet<int>();

		for (int i = 1; i <= sequenceLen; i++)
		{
			if (hSet.Contains(i))
			{
				if (hSet1.Contains(sequence[i - 1]))
				{
					return true;
				}
				else {
					hSet1.Add(sequence[i - 1]);
				}
				
			}
			
		}

		return false;
	}
}

Chef and Happiness CodeChef Solution in NODEJS

process.stdin.resume();
process.stdin.setEncoding('utf8');

// your code goes here
var readline = require('readline');
var rl = readline.createInterface({
  input: process.stdin,
  output: process.stdout,
  terminal: false
});
let lines=[];
rl.on('line', function(line){
    //console.log(line.split(" "));
    lines.push(line.split(" ").map(Number));
})
rl.on('close', function(){
    //console.log(lines);
    let q=lines[0]
    for(let i=0;i<q;i++){
        //console.log(doit(lines[2*i+1]));
        console.log(doit(lines[2*i+2]));
        //console.log()
    }
})
function doit(line){
    //console.log(line);
    let res={};
    let result="Poor Chef";
    line.forEach(ind=>{
        let val=line[ind-1];

        if (res[val] && !res[val][ind])
        {
            result="Truly Happy"
            
        }
        if (!res[val]) res[val]={};
        res[val][ind]=1;
        //console.log("  ",ind, val,res);
    })
    return result;
}

Chef and Happiness CodeChef Solution in GO

package main

import (
	"bufio"
	"fmt"
	"os"
	"strconv"
)

var scanner *bufio.Scanner

func init() {
	scanner = bufio.NewScanner(bufio.NewReader(os.Stdin))
	scanner.Split(bufio.ScanWords)
}

func next() string {
	scanner.Scan()
	return scanner.Text()
}

func nextInt() int {
	num, err := strconv.Atoi(next())
	if err != nil {
		panic(err)
	}
	return num
}

func main() {
	T := nextInt()
	for caseNum := 1; caseNum <= T; caseNum++ {
		N := nextInt()
		data := make([]int, N+1)
		for i := 1; i <= N; i++ {
			data[i] = nextInt()
		}

		referrers := make([]map[int]bool, N+1)
		for i := range referrers {
			referrers[i] = make(map[int]bool)
		}
		for i := 1; i <= N; i++ {
			referrers[data[data[i]]][data[i]] = true
		}
		happy := false
		for _, ed := range referrers {
			if len(ed) > 1 {
				happy = true
				break
			}
		}
		if happy {
			fmt.Println("Truly Happy")
		} else {
			fmt.Println("Poor Chef")
		}
	}
}
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