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Bob and Alice are having a lockout match between them. There are three problems in the contest worth A, B, and C points respectively. Only the first player to solve a problem gets points for that problem. It is impossible for Bob and Alice to solve a problem at the same time. Chef wants to know if there is any chance of a draw if Bob and Alice manage to solve all 3 problems. A draw occurs when both players end with equal number of points.
For each testcase, output YES if the match can end in a draw, and NO otherwise.
You may print each character of the string in uppercase or lowercase (for example, the strings “yEs”, “yes”, “Yes” and “YES” will all be treated as identical).
Subtask #1 (100 points): original constraints
Input:
3
2 5 2
4 2 2
3 5 5
Output:
NO
YES
NO
In the first and third test cases, it is impossible for Bob and Alice to solve the problems so that they have the same number of points at the end.
In the second case, it is possible for Bob to solve the first problem, and Alice to solve the last two problems, in which case they will both have 4 points and the game will end in a draw.
#include <iostream>
using namespace std;
int main() {
// your code goes here
int t;cin>>t;
while(t--){
int a,b,c;
cin>>a>>b>>c;
if(a+b==c||b+c==a||a+c==b) cout<<"YES"<<endl;
else cout<<"NO"<<endl;
}
return 0;
}
# cook your dish here
for i in range(int(input())):
a,b,c=map(int,input().split())
if b+c == a or a+b == c or a+c == b:
print("YES")
else:
print("NO")
/* package codechef; // don't place package name! */
import java.util.*;
import java.lang.*;
import java.io.*;
/* Name of the class has to be "Main" only if the class is public. */
class Codechef
{
public static void main (String[] args) throws java.lang.Exception
{
// your code goes here
Scanner in=new Scanner(System.in);
int te=in.nextInt();
while(te-->0){
int a=in.nextInt();
int b=in.nextInt();
int c=in.nextInt();
if(a+b==c || b+c==a || a+c==b)
System.out.println("YES");
else
System.out.println("NO");
}
}
}
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