Chef gives Party CodeChef Solution

Problem – Chef gives Party CodeChef Solution

Chef wants to give a burger party to all his N friends i.e. he wants to buy one burger for each of his friends.

The cost of each burger is X rupees while Chef has a total of K rupees.

Determine whether he has enough money to buy a burger for each of his friends or not.

Input Format

• The first line contains a single integer T – the number of test cases. Then the test cases follow.
• The first and only line of each test case contains the three integers N, X, and K – the number of Chef’s friends, the cost of each burger, and the total money Chef has, respectively.

Output Format

For each test case, output YES if the Chef can give a party to all his N friends. Otherwise, output NO.

You may print each character of YES and NO in uppercase or lowercase (for example, yes, yEs, Yes will be considered identical).

Constraints

• 1≤T≤1000
• 1≤N,X≤100
• 1≤K≤10000

Sample 1:

Input: 4
5 10 70
5 10 40
10 40 400
14 14 150
Output: YES
NO
YES
NO

Explanation:

• Test case 1: Chef has 5 friends. The cost of buying a burger for each of them will be 10×5=50 while Chef has 70 rupees. Therefore, he can buy a burger for all of them.
• Test case 2: Chef has 5 friends. The cost of buying a burger for each of them will be 10×5=50 while Chef has 40 rupees. Therefore, he can not buy a burger for all of them.
• Test case 3: Chef has 10 friends. The cost of buying a burger for each of them will be 40×10=400 and Chef has 400 rupees. Therefore, he can buy a burger for all of them.
• Test case 4: Chef has 14 friends. The cost of buying a burger for each of them will be 14×14=196 while Chef has 150 rupees. Therefore, he can not buy a burger for all of them.

Chef gives Party CodeChef Solution in C++17

#include <iostream>
using namespace std;

int main() {
	int t;
	cin>>t;
	while(t--)
	{
	    int N,X,K,H;
	    cin>>N>>X>>K;
	    H=N*X;
	    if(H<=K)
	    {
	        cout<<"YES"<<endl;
	    }
	    else
	    {
	        cout<<"NO"<<endl;
	    }
	}
	return 0;
}

Chef gives Party CodeChef Solution in Java

import java.util.*;
import java.lang.*;
import java.io.*;

class Codechef
{
	public static void main (String[] args) throws java.lang.Exception
	{
		Scanner sc = new Scanner(System.in);
		int t = sc.nextInt();
		
		for (int i=0;i<t ;i++ )
		{
		    int a = sc.nextInt();
		     int b = sc.nextInt();
		      int c = sc.nextInt();
		      
		      if (a*b<=c)
		      {
		          System.out.println("YES");
		      }
		      else if(a*b>=c)
		      {
		          System.out.println("NO");
		      }
		}
	}
}

Chef gives Party CodeChef Solution in Pyth 3

t=int(input())
for i in range(t):
    n,x,k=map(int,input().split(" "))
    if k>=n*x:
        print("yes")
    else:
        print("no")

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