Collections.Counter() Hacker Rank Solution – Queslers

Problem: Collections.Counter() Hacker Rank Solution

Task :

Raghu is a shoe shop owner. His shop has X number of shoes. He has a list containing the size of each shoe he has in his shop. There are N number of customers who are willing to pay xi amount of money only if they get the shoe of their desired size. Your task is to compute how much money Raghu earned.

Input Format :

The first line contains X, the number of shoes.
The second line contains the space separated list of all the shoe sizes in the shop.
The third line contains N, the number of customers.
The next N lines contain the space separated values of the shoe size desired by the customer and xi, the price of the shoe.

Constraints :

  • 0 <= X <= 10^3
  • 0 <= N <= 10^3
  • 20 <= xi <= 100
  • 2 <= shoe size <= 20

Output Format :

Print the amount of money earned by Raghu.

Sample Input :

10
2 3 4 5 6 8 7 6 5 18
6
6 55
6 45
6 55
4 40
18 60
10 50

Sample Output :

200

Explanation :

Customer 1: Purchased size 6 shoe for $55.
Customer 2: Purchased size 6 shoe for $45.
Customer 3: Size 6 no longer available, so no purchase.
Customer 4: Purchased size 4 shoe for $40.
Customer 5: Purchased size 18 shoe for $60.
Customer 6: Size 10 not available, so no purchase.Total money earned = 55+45+40+60 = $200

Collections.Counter() Hacker Rank Solution in Python 2

from collections import Counter

X = int(input())
sizes = Counter(map(int,raw_input().split()))
N = int(input())
earnings = 0

for i in xrange(N):
    size,x = map(int,raw_input().split())
    if sizes[size]>0:
        sizes[size]-=1
        earnings += x
        
print earnings
    

Collections.Counter() Hacker Rank Solution in Python 3

# Enter your code here. Read input from STDIN. Print output to STDOUT
import collections

numShoes = int(input())
shoes = collections.Counter(map(int, input().split()))
numCust = int(input())

income = 0

for i in range(numCust):
    size, price = map(int, input().split())
    if shoes[size]: 
        income += price
        shoes[size] -= 1

print(income)

Collections.Counter() Hacker Rank Solution in pypy

import collections

numShoes = int(raw_input())
shoes = collections.Counter(map(int, raw_input().split()))
numCust = int(raw_input())

money = 0 

for i in range(numCust):
    size, price = map(int, raw_input().split())
    if shoes[size]:
        money += price
        shoes[size] -= 1
        

print money
       
    

Collections.Counter() Hacker Rank Solution in pypy3

# Enter your code here. Read input from STDIN. Print output to STDOUT
from collections import Counter

num_shoes = int(input())
sizes = [int(i) for i in input().split()] #2 3 4 5 6 8 7 6 5 18
num_cust = int(input())

d = Counter(sizes)

earn = 0
for i in range(num_cust):
#while(input() != null)    
    req_i = [int(j) for j in input().split()]
    req_i_size = req_i[0]
    if req_i_size in d.keys():
        if d[req_i_size] > 0:
            earn += req_i[1]
            d[req_i_size] -= 1
        
print(earn)     
Collections.Counter() Hacker Rank Solution Review:

In our experience, we suggest you solve this Collections.Counter() Hacker Rank Solution and gain some new skills from Professionals completely free and we assure you will be worth it.

Collections.Counter() problem is available on Hacker Rank for Free, if you are stuck anywhere between a compilation, just visit Queslers to get Collections.Counter() Hacker Rank Solution

Conclusion:

I hope this Collections.Counter() Hacker Rank Solution would be useful for you to learn something new from this problem. If it helped you then don’t forget to bookmark our site for more Hacker Rank, Leetcode, Codechef, Codeforce Solution.

This Problem is intended for audiences of all experiences who are interested in learning Programming in a business context; there are no prerequisites.

Keep Learning!

More Hacker Rank Problem & Solutions >>

Staircase Hacker Rank Solution

A Very Big Sum Hacker Rank Solution

Diagonal Difference Hacker Rank Solution

Nested Lists Hacker Rank Solution

Lists Hacker Rank Solution

Leave a Reply

Your email address will not be published.