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College Life 4 CodeChef Solution
Problem -College Life 4 CodeChef Solution
“This website is dedicated for CodeChef solution where we will publish right solution of all your favourite CodeChef problems along with detailed explanatory of different competitive programming concepts and languages.
College Life 4 CodeChef Solution in C++17
“#include <bits/stdc++.h>
using namespace std;
#define ll long long
#define vc vector
#define p(x) pair<x,x>
#define ff first
#define ss second
int main() {
// your code goes here
int t;cin>>t;
while(t--) {
ll n,e,h,a,b,c;cin>>n>>e>>h>>a>>b>>c;
ll ans = LLONG_MAX;
for(ll i=0;i<=min(n,min(e,h));i++) {
ll res = n - i;
if(a <= b) {
ll y = (e-i)/2;
if(y >= res) y = res;
// y = min(y,res);
res -= y;
ll cost = res*b + y*a + i*c;
if((h-i)/3 >= res) ans = min(ans,cost);
}else {
ll y = (h-i)/3;
if(y >= res) y = res;
res -= y;
ll cost = res*a + y*b + i*c;
if((e-i)/2 >= res) ans = min(ans,cost);
}
}
if(ans == LLONG_MAX) ans = -1;
cout << ans << endl;
}
return 0;
}College Life 4 CodeChef Solution in C++14
“#include <bits/stdc++.h>
#pragma optimization_level 3
#pragma GCC optimize("Ofast,no-stack-protector,unroll-loops,fast-math,O3")
#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx")
#pragma GCC optimize("Ofast")//Comment optimisations for interactive problems (use endl)
#pragma GCC target("avx,avx2,fma")
#pragma GCC optimization ("unroll-loops")
using namespace std;
struct PairHash {inline std::size_t operator()(const std::pair<int, int> &v) const { return v.first * 31 + v.second; }};
// speed
#define Code ios_base::sync_with_stdio(false);
#define By ios::sync_with_stdio(0);
#define Sumfi cout.tie(NULL);
// alias
using ll = long long;
using ld = long double;
using ull = unsigned long long;
// constants
const ld PI = 3.14159265358979323846; /* pi */
const ll INF = 1e18;
const ld EPS = 1e-9;
const ll MAX_N = 1e6;
const ll mod = 1e4;
// typedef
typedef pair<ll, ll> pll;
typedef pair<ld, ld> pld;
typedef vector<pll> vpll;
typedef array<ll,3> all3;
typedef array<ll,5> all5;
typedef vector<all3> vall3;
typedef vector<all5> vall5;
typedef vector<ld> vld;
typedef vector<ll> vll;
typedef vector<vll> vvll;
typedef vector<int> vi;
typedef deque<ll> dqll;
typedef deque<pll> dqpll;
typedef pair<string, string> pss;
typedef vector<pss> vpss;
typedef vector<string> vs;
typedef vector<vs> vvs;
typedef unordered_set<ll> usll;
typedef unordered_set<pll, PairHash> uspll;
typedef unordered_map<ll, ll> umll;
typedef unordered_map<pll, ll, PairHash> umpll;
// macros
#define rep(i,m,n) for(ll i=m;i<n;i++)
#define rrep(i,m,n) for(ll i=n;i>=m;i--)
#define all(a) begin(a), end(a)
#define rall(a) rbegin(a), rend(a)
#define ZERO(a) memset(a,0,sizeof(a))
#define MINUS(a) memset(a,0xff,sizeof(a))
#define INF(a) memset(a,0x3f3f3f3f3f3f3f3fLL,sizeof(a))
#define ASCEND(a) iota(all(a),0)
#define sz(x) ll((x).size())
#define BIT(a,i) (a & (1ll<<i))
#define BITSHIFT(a,i,n) (((a<<i) & ((1ll<<n) - 1)) | (a>>(n-i)))
#define pyes cout<<"YES\n";
#define pno cout<<"NO\n";
#define endl "\n"
#define pneg1 cout<<"-1\n";
#define ppossible cout<<"Possible\n";
#define pimpossible cout<<"Impossible\n";
#define TC(x) cout<<"Case #"<<x<<": ";
#define X first
#define Y second
// utility functions
template <typename T>
void print(T &&t) { cout << t << "\n"; }
template<typename T>
void printv(vector<T>v){ll n=v.size();rep(i,0,n){cout<<v[i];if(i+1!=n)cout<<' ';}cout<<endl;}
template<typename T>
void printvln(vector<T>v){ll n=v.size();rep(i,0,n)cout<<v[i]<<endl;}
void fileIO(string in = "input.txt", string out = "output.txt") {freopen(in.c_str(),"r",stdin); freopen(out.c_str(),"w",stdout);}
void readf() {freopen("", "rt", stdin);}
template<typename T>
void readv(vector<T>& v){rep(i,0,sz(v)) cin>>v[i];}
template<typename T, typename U>
void readp(pair<T,U>& A) {cin>>A.first>>A.second;}
template<typename T, typename U>
void readvp(vector<pair<T,U>>& A) {rep(i,0,sz(A)) readp(A[i]); }
void readvall3(vall3& A) {rep(i,0,sz(A)) cin>>A[i][0]>>A[i][1]>>A[i][2];}
void readvall5(vall5& A) {rep(i,0,sz(A)) cin>>A[i][0]>>A[i][1]>>A[i][2]>>A[i][3]>>A[i][4];}
void readvvll(vvll& A) {rep(i,0,sz(A)) readv(A[i]);}
struct Combination {
vll fac, inv;
ll n, MOD;
ll modpow(ll n, ll x, ll MOD = mod) { if(!x) return 1; ll res = modpow(n,x>>1,MOD); res = (res * res) % MOD; if(x&1) res = (res * n) % MOD; return res; }
Combination(ll _n, ll MOD = mod): n(_n + 1), MOD(MOD) {
inv = fac = vll(n,1);
rep(i,1,n) fac[i] = fac[i-1] * i % MOD;
inv[n - 1] = modpow(fac[n - 1], MOD - 2, MOD);
rrep(i,1,n - 2) inv[i] = inv[i + 1] * (i + 1) % MOD;
}
ll fact(ll n) {return fac[n];}
ll nCr(ll n, ll r) {
if(n < r or n < 0 or r < 0) return 0;
return fac[n] * inv[r] % MOD * inv[n-r] % MOD;
}
};
struct Matrix {
ll r,c;
vvll matrix;
Matrix(ll r, ll c, ll v = 0): r(r), c(c), matrix(vvll(r,vll(c,v))) {}
Matrix operator*(const Matrix& B) const {
Matrix res(r, B.c);
rep(i,0,r) rep(j,0,B.c) rep(k,0,B.r) {
res.matrix[i][j] = (res.matrix[i][j] + matrix[i][k] * B.matrix[k][j] % mod) % mod;
}
return res;
}
Matrix copy() {
Matrix copy(r,c);
copy.matrix = matrix;
return copy;
}
Matrix pow(ll n) {
assert(r == c);
Matrix res(r,r);
Matrix now = copy();
rep(i,0,r) res.matrix[i][i] = 1;
while(n) {
if(n & 1) res = res * now;
now = now * now;
n /= 2;
}
return res;
}
};
// geometry data structures
template <typename T>
struct Point {
T y,x;
Point(T y, T x) : y(y), x(x) {}
Point(pair<T,T> p) : y(p.first), x(p.second) {}
Point() {}
void input() {cin>>y>>x;}
friend ostream& operator<<(ostream& os, const Point<T>& p) { os<<p.y<<' '<<p.x<<'\n'; return os;}
Point<T> operator+(Point<T>& p) {return Point<T>(y + p.y, x + p.x);}
Point<T> operator-(Point<T>& p) {return Point<T>(y - p.y, x - p.x);}
Point<T> operator*(ll n) {return Point<T>(y*n,x*n); }
Point<T> operator/(ll n) {return Point<T>(y/n,x/n); }
bool operator<(const Point &other) const {if (x == other.x) return y < other.y;return x < other.x;}
Point<T> rotate(Point<T> center, ld angle) {
ld si = sin(angle * PI / 180.), co = cos(angle * PI / 180.);
ld y = this->y - center.y;
ld x = this->x - center.x;
return Point<T>(y * co - x * si + center.y, y * si + x * co + center.x);
}
ld distance(Point<T> other) {
T dy = abs(this->y - other.y);
T dx = abs(this->x - other.x);
return sqrt(dy * dy + dx * dx);
}
T norm() { return x * x + y * y; }
};
template<typename T>
struct Line {
Point<T> A, B;
Line(Point<T> A, Point<T> B) : A(A), B(B) {}
Line() {}
void input() {
A = Point<T>();
B = Point<T>();
A.input();
B.input();
}
T ccw(Point<T> &a, Point<T> &b, Point<T> &c) {
T res = a.x * b.y + b.x * c.y + c.x * a.y;
res -= (a.x * c.y + b.x * a.y + c.x * b.y);
return res;
}
bool isIntersect(Line<T> o) {
T p1p2 = ccw(A,B,o.A) * ccw(A,B,o.B);
T p3p4 = ccw(o.A,o.B,A) * ccw(o.A,o.B,B);
if (p1p2 == 0 && p3p4 == 0) {
pair<T,T> p1(A.y, A.x), p2(B.y,B.x), p3(o.A.y, o.A.x), p4(o.B.y, o.B.x);
if (p1 > p2) swap(p2, p1);
if (p3 > p4) swap(p3, p4);
return p3 <= p2 && p1 <= p4;
}
return p1p2 <= 0 && p3p4 <= 0;
}
pair<bool,Point<ld>> intersection(Line<T> o) {
if(!this->intersection(o)) return {false, {}};
ld det = 1. * (o.B.y-o.A.y)*(B.x-A.x) - 1.*(o.B.x-o.A.x)*(B.y-A.y);
ld t = ((o.B.x-o.A.x)*(A.y-o.A.y) - (o.B.y-o.A.y)*(A.x-o.A.x)) / det;
return {true, {A.y + 1. * t * (B.y - A.y), B.x + 1. * t * (B.x - A.x)}};
}
//@formula for : y = ax + b
//@return {a,b};
pair<ld, ld> formula() {
T y1 = A.y, y2 = B.y;
T x1 = A.x, x2 = B.x;
if(y1 == y2) return {1e9, 0};
if(x1 == x2) return {0, 1e9};
ld a = 1. * (y2 - y1) / (x2 - x1);
ld b = -x1 * a + y1;
return {a, b};
}
};
template<typename T>
struct Circle {
Point<T> center;
T radius;
Circle(T y, T x, T radius) : center(Point<T>(y,x)), radius(radius) {}
Circle(Point<T> center, T radius) : center(center), radius(radius) {}
Circle() {}
void input() {
center = Point<T>();
center.input();
cin>>radius;
}
bool circumference(Point<T> p) {
return (center.x - p.x) * (center.x - p.x) + (center.y - p.y) * (center.y - p.y) == radius * radius;
}
bool intersect(Circle<T> c) {
T d = (center.x - c.center.x) * (center.x - c.center.x) + (center.y - c.center.y) * (center.y - c.center.y);
return (radius - c.radius) * (radius - c.radius) <= d and d <= (radius + c.radius) * (radius + c.radius);
}
bool include(Circle<T> c) {
T d = (center.x - c.center.x) * (center.x - c.center.x) + (center.y - c.center.y) * (center.y - c.center.y);
return d <= radius * radius;
}
};
ll __gcd(ll x, ll y) { return !y ? x : __gcd(y, x % y); }
all3 __exgcd(ll x, ll y) { if(!y) return {x,1,0}; auto [g,x1,y1] = __exgcd(y, x % y); return {g, y1, x1 - (x/y) * y1}; }
ll __lcm(ll x, ll y) { return x / __gcd(x,y) * y; }
ll modpow(ll n, ll x, ll MOD = mod) { n%=MOD; if(!x) return 1; ll res = modpow(n,x>>1,MOD); res = (res * res) % MOD; if(x&1) res = (res * n) % MOD; return res; }
ll solve(ll n, ll x, ll y, ll a, ll b, ll c) {
ll res = INF;
rep(i,0,min({n,x,y}) + 1) {
ll now = n - i;
if(a <= b) {
ll rem = min((x-i) / 2, now);
now -= rem;
ll cost = now * b + rem * a + i * c;
if((y - i) / 3 >= now) res = min(res, cost);
} else {
ll rem = min((y-i)/3,now);
now -= rem;
ll cost = now * a + rem * b + i * c;
if((x - i) / 2 >= now) res = min(res, cost);
}
}
return res == INF ? -1 : res;
}
int main() {
Code By Sumfi
cout.precision(12);
ll tc = 1;
cin>>tc;
rep(i,1,tc+1) {
ll n,x,y,a,b,c;
cin>>n>>x>>y>>a>>b>>c;
print(solve(n,x,y,a,b,c));
}
return 0;
}College Life 4 CodeChef Solution in PYTH 3
“# cook your dish here
# cook your dish here
from math import inf
for __ in range(int(input())):
n, e, h, a, b, c = map(int, input().split())
min_cost = inf
for chocolate_cake in range(min(n, min(e, h)) + 1):
total_cost = chocolate_cake * c
remaining = n - chocolate_cake
egg = max(0, e - chocolate_cake)
choco_bar = max(0, h - chocolate_cake)
if a < b:
total_cost += min(egg // 2, remaining) * a
remaining -= min(egg // 2, remaining)
total_cost += min(choco_bar // 3, remaining) * b
remaining -= min(choco_bar // 3, remaining)
else:
total_cost += min(choco_bar // 3, remaining) * b
remaining -= min(choco_bar // 3, remaining)
total_cost += min(egg // 2, remaining) * a
remaining -= min(egg // 2, remaining)
if not remaining:
min_cost = min(min_cost, total_cost)
if min_cost == inf:
print(-1)
else:
print(min_cost)College Life 4 CodeChef Solution in C
“#include <stdio.h>
int min( int a, int b){
if(a>b){
return b;
}else{return a;}
}
int main(void) {
long long int t;
scanf("%lld",&t);
while(t--){
long long int n,e,h,a,b,c,cost=0,fin=1e18,reqo,reqm,maxo,maxm;
scanf("%lld %lld %lld %lld %lld %lld",&n,&e,&h,&a,&b,&c);
for(int k=0; k<=n; k++){
if(e<k || h<k){
continue;
}else{
maxo=(e-k)/2;
maxm=(h-k)/3;
if((maxo+maxm+k)<n){
continue;
}else{
if(a<b){
reqo=min(maxo,n-k);
reqm=n-reqo-k;
}else{
reqm=min(maxm,n-k);
reqo=n-reqm-k;
}
}
cost=reqo*a+k*c+reqm*b;
if(cost<fin){
fin=cost;
}
}
}
if(fin==1e18){printf("-1\n");}else{printf("%lld\n",fin);}
}
return 0;
}College Life 4 CodeChef Solution in JAVA
“/* package codechef; // don't place package name! */
import java.util.*;
import java.lang.*;
import java.io.*;
class Solution{
public static void main(String[] args){
Scanner sc = new Scanner(System.in);
int t = sc.nextInt();
while(t-- > 0){
int items = sc.nextInt();
int eggs = sc.nextInt();
int chocs = sc.nextInt();
int A = sc.nextInt();
int B = sc.nextInt();
int C = sc.nextInt();
long ans = Long.MAX_VALUE;
for(int c = 0;c<=items;c++){
if(eggs<c || chocs<c) break;
int maxO = (eggs-c)/2;
int maxM = (chocs-c)/3;
int reqO=0;
int reqM=0;
if(c+maxO+maxM < items) continue;
if(A<B){
reqO = Math.min(maxO, items-c);
reqM = (items-c-reqO);
}
else{
reqM = Math.min(maxM, items-c);
reqO = (items-c-reqM);
}
long cost = (long)((long)A*(long)reqO) + (long)((long)B*(long)reqM) + (long)((long)C*(long)c);
ans = Math.min(ans, cost);
}
if(ans == Long.MAX_VALUE){
System.out.println(-1);
}
else System.out.println(ans);
}
}
}College Life 4CodeChef Solution in PYPY 3
“from math import inf
for __ in range(int(input())):
n, e, h, a, b, c = map(int, input().split())
min_cost = inf
for chocolate_cake in range(min(n, min(e, h)) + 1):
total_cost = chocolate_cake * c
remaining = n - chocolate_cake
egg = max(0, e - chocolate_cake)
choco_bar = max(0, h - chocolate_cake)
if a < b:
total_cost += min(egg // 2, remaining) * a
remaining -= min(egg // 2, remaining)
total_cost += min(choco_bar // 3, remaining) * b
remaining -= min(choco_bar // 3, remaining)
else:
total_cost += min(choco_bar // 3, remaining) * b
remaining -= min(choco_bar // 3, remaining)
total_cost += min(egg // 2, remaining) * a
remaining -= min(egg // 2, remaining)
if not remaining:
min_cost = min(min_cost, total_cost)
if min_cost == inf:
print(-1)
else:
print(min_cost)College Life 4 CodeChef Solution in PYTH
“# cook your code here
t = int(raw_input())
while t > 0:
t -= 1
n, eggs, bars, price_ome, price_milk, price_cake = map(int, raw_input().split(' '))
w_eggs, w_bars = 2, 3
if price_ome > price_milk:
price_ome, price_milk = price_milk, price_ome
w_eggs, w_bars = w_bars, w_eggs
eggs, bars = bars, eggs
ans = 10**18
for cake in range(0, n + 1):
if eggs >= cake and bars >= cake:
used_ome = min(n - cake, (eggs - cake) / w_eggs)
used_milk = min(n - cake - used_ome, (bars - cake) / w_bars)
if cake + used_ome + used_milk == n:
ans = min(ans, cake * price_cake + used_ome * price_ome + used_milk * price_milk)
if ans == 10**18:
ans = -1
print(ans)College Life 4 CodeChef Solution in C#
“using System;
public class Test
{
public static void Main()
{
int t = Convert.ToInt32(Console.ReadLine());
while (t-- > 0)
{
String[] tokens = Console.ReadLine().Split(' ');
int num_required = Convert.ToInt32(tokens[0]);
int num_eggs = Convert.ToInt32(tokens[1]);
int num_chocs = Convert.ToInt32(tokens[2]);
long per_omlt = Convert.ToInt32(tokens[3]);
long per_mshk = Convert.ToInt32(tokens[4]);
long per_cake = Convert.ToInt32(tokens[5]);
long cost_min = long.MaxValue;
if (num_eggs + num_chocs >= 2 * num_required)
{
for (int num_cakes = Math.Min(num_required, Math.Min(num_eggs, num_chocs)); num_cakes >= 0; --num_cakes)
{
long cost_so_far = num_cakes * per_cake;
int num_further = num_required - num_cakes;
int eggs_left = num_eggs - num_cakes;
int chocs_left = num_chocs - num_cakes;
if (num_further > 0)
{
int num_omlts = Math.Min(num_further, eggs_left / 2);
int num_mshks = Math.Min(num_further, chocs_left / 3);
if (num_omlts + num_mshks < num_further)
continue;
if (per_omlt <= per_mshk)
num_mshks = num_further - num_omlts;
else
num_omlts = num_further - num_mshks;
cost_so_far += num_omlts * per_omlt + num_mshks * per_mshk;
}
if (cost_so_far < cost_min)
cost_min = cost_so_far;
}
}
if (cost_min == long.MaxValue)
Console.WriteLine("-1");
else
Console.WriteLine(cost_min);
}
}
}College Life 4 CodeChef Solution in GO
“package main
import (
"bufio"
"bytes"
"fmt"
"math"
"os"
)
func main() {
reader := bufio.NewReader(os.Stdin)
tc := readNum(reader)
var buf bytes.Buffer
for tc > 0 {
tc--
line := readNNums(reader, 6)
res := solve(line[0], line[1], line[2], line[3], line[4], line[5])
buf.WriteString(fmt.Sprintf("%d\n", res))
}
fmt.Print(buf.String())
}
func readUint64(bytes []byte, from int, val *uint64) int {
i := from
var tmp uint64
for i < len(bytes) && bytes[i] >= '0' && bytes[i] <= '9' {
tmp = tmp*10 + uint64(bytes[i]-'0')
i++
}
*val = tmp
return i
}
func readInt(bytes []byte, from int, val *int) int {
i := from
sign := 1
if bytes[i] == '-' {
sign = -1
i++
}
tmp := 0
for i < len(bytes) && bytes[i] >= '0' && bytes[i] <= '9' {
tmp = tmp*10 + int(bytes[i]-'0')
i++
}
*val = tmp * sign
return i
}
func readString(reader *bufio.Reader) string {
s, _ := reader.ReadString('\n')
for i := 0; i < len(s); i++ {
if s[i] == '\n' {
return s[:i]
}
}
return s
}
func readNum(reader *bufio.Reader) (a int) {
bs, _ := reader.ReadBytes('\n')
readInt(bs, 0, &a)
return
}
func readTwoNums(reader *bufio.Reader) (a int, b int) {
res := readNNums(reader, 2)
a, b = res[0], res[1]
return
}
func readThreeNums(reader *bufio.Reader) (a int, b int, c int) {
res := readNNums(reader, 3)
a, b, c = res[0], res[1], res[2]
return
}
func readNNums(reader *bufio.Reader, n int) []int {
res := make([]int, n)
x := 0
bs, _ := reader.ReadBytes('\n')
for i := 0; i < n; i++ {
for x < len(bs) && (bs[x] < '0' || bs[x] > '9') && bs[x] != '-' {
x++
}
x = readInt(bs, x, &res[i])
}
return res
}
func solve(N int, E int, H int, A, B, C int) int64 {
// x + y + z = N
// 2 * x + z <= E
// 3 * y + z <= H
// x * A + y * B + z * C
var best int64 = math.MaxInt64
for z := 0; z <= N && z <= E && z <= H; z++ {
x := (E - z) / 2
y := (H - z) / 3
if A <= B {
// more x more better
x = min(N-z, x)
y = min(y, max(0, N-z-x))
if x+y+z == N {
best = min2(best, int64(x)*int64(A)+int64(y)*int64(B)+int64(z)*int64(C))
}
} else {
y = min(N-z, y)
x = min(x, max(0, N-z-y))
if x+y+z == N {
best = min2(best, int64(x)*int64(A)+int64(y)*int64(B)+int64(z)*int64(C))
}
}
}
if best == math.MaxInt64 {
return -1
}
return best
}
func min(a, b int) int {
if a <= b {
return a
}
return b
}
func max(a, b int) int {
if a >= b {
return a
}
return b
}
func min2(a, b int64) int64 {
if a <= b {
return a
}
return b
}College Life 4 CodeChef Solution Review:
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