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# Convert Sorted Array to Binary Search Tree LeetCode Solution

## Problem – Convert Sorted Array to Binary Search Tree

Given an integer array `nums` where the elements are sorted in ascending order, convert it to a height-balanced binary search tree.

height-balanced binary tree is a binary tree in which the depth of the two subtrees of every node never differs by more than one.

Example 1:

``````Input: nums = [-10,-3,0,5,9]
Output: [0,-3,9,-10,null,5]
Explanation: [0,-10,5,null,-3,null,9] is also accepted:
``````

Example 2:

``````Input: nums = [1,3]
Output: [3,1]
Explanation: [1,null,3] and [3,1] are both height-balanced BSTs.``````

Constraints:

• `1 <= nums.length <= 104`
• `-104 <= nums[i] <= 104`
• `nums` is sorted in a strictly increasing order.

### Convert Sorted Array to Binary Search Tree LeetCode Solution in Java

``````public TreeNode sortedArrayToBST(int[] num) {
if (num.length == 0) {
return null;
}
TreeNode head = helper(num, 0, num.length - 1);
}

public TreeNode helper(int[] num, int low, int high) {
if (low > high) { // Done
return null;
}
int mid = (low + high) / 2;
TreeNode node = new TreeNode(num[mid]);
node.left = helper(num, low, mid - 1);
node.right = helper(num, mid + 1, high);
return node;
}
``````

### Convert Sorted Array to Binary Search Tree LeetCode Solution in Python

``````# Definition for a  binary tree node
# class TreeNode:
#     def __init__(self, x):
#         self.val = x
#         self.left = None
#         self.right = None

class Solution:
# @param num, a list of integers
# @return a tree node
# 12:37
def sortedArrayToBST(self, num):
if not num:
return None

mid = len(num) // 2

root = TreeNode(num[mid])
root.left = self.sortedArrayToBST(num[:mid])
root.right = self.sortedArrayToBST(num[mid+1:])

return root``````

### Convert Sorted Array to Binary Search Tree LeetCode Solution in C++

``````class Solution {
public:
TreeNode *sortedArrayToBST(vector<int> &num) {
if(num.size() == 0) return NULL;
if(num.size() == 1)
{
return new TreeNode(num[0]);
}

int middle = num.size()/2;
TreeNode* root = new TreeNode(num[middle]);

vector<int> leftInts(num.begin(), num.begin()+middle);
vector<int> rightInts(num.begin()+middle+1, num.end());

root->left = sortedArrayToBST(leftInts);
root->right = sortedArrayToBST(rightInts);

return root;
}
};
``````
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