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# Count Prefixes of a Given String LeetCode Solution

## Problem – Count Prefixes of a Given String LeetCode Solution

You are given a string array `words` and a string `s`, where `words[i]` and `s` comprise only of lowercase English letters.

Return the number of strings in `words` that are a prefix of `s`.

prefix of a string is a substring that occurs at the beginning of the string. A substring is a contiguous sequence of characters within a string.

Example 1:

``````Input: words = ["a","b","c","ab","bc","abc"], s = "abc"
Output: 3
Explanation:
The strings in words which are a prefix of s = "abc" are:
"a", "ab", and "abc".
Thus the number of strings in words which are a prefix of s is 3.
``````

Example 2:

``````Input: words = ["a","a"], s = "aa"
Output: 2
Explanation:
Both of the strings are a prefix of s.
Note that the same string can occur multiple times in words, and it should be counted each time.
``````

Constraints:

• `1 <= words.length <= 1000`
• `1 <= words[i].length, s.length <= 10`
• `words[i]` and `s` consist of lowercase English letters only.

### Count Prefixes of a Given String LeetCode Solution in Java

``````    public int countPrefixes(String[] words, String s) {
int res = 0;
for (String w : words)
if (s.startsWith(w))
res++;
return res;
}
``````

### Count Prefixes of a Given String LeetCode Solution in C++

``````    int countPrefixes(vector<string>& words, string s) {
int res = 0;
for (auto& w : words)
res += s.find(w) < 1;
return res;
}
``````

### Count Prefixes of a Given String LeetCode Solution in Python

``````    def countPrefixes(self, words, s):
return sum(map(s.startswith, words))
``````
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