## Problem – Count the Notebooks CodeChef Solution

You know that 1 kg of pulp can be used to make 1000 pages and 1 notebook consists of 100 pages.

Suppose a notebook factory receives *N* kg of pulp, how many notebooks can be made from that?

### Input Format

- First line will contain
*T*, the number of test cases. Then the test cases follow. - Each test case contains a single integer
*N* – the weight of the pulp the factory has (in kgs).

### Output Format

For each test case, output the number of notebooks that can be made using *N* kgs of pulp.

### Constraints

### Sample 1:

**Input**: 3
1
100
50
**Output**: 10
1000
500

### Explanation:

**Test case-1:** 1 kg of pulp can be used to make 1000 pages which can be used to make 10 notebooks.

**Test case-2:** 100 kg of pulp can be used to make 100000 pages which can be used to make 1000 notebooks.

**Test case-3:** 50 kg of pulp can be used to make 50000 pages which can be used to make 500 notebooks.

## Count the Notebooks CodeChef Solution in C++17

```
#include <iostream>
using namespace std;
int main() {
int t;
cin>>t;
while(t--){
int n;
cin>>n;
cout<<n*10<<endl;
}
// your code goes here
return 0;
}
```

## Count the Notebooks CodeChef Solution in Pyth 3

```
# cook your dish here
t=int(input())
for i in range(t):
n = int(input())
print(n*10)
```

## Count the Notebooks CodeChef Solution in Java

```
/* package codechef; // don't place package name! */
import java.util.*;
import java.lang.*;
import java.io.*;
/* Name of the class has to be "Main" only if the class is public. */
class Codechef
{
public static void main (String[] args) throws java.lang.Exception
{
Scanner sc=new Scanner(System.in);
int T=sc.nextInt();
for(int i=0;i<T;i++){
int N=sc.nextInt();
int Y=(N*1000)/100;
System.out.println(Y);
}
}
}
```

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