Count the Notebooks CodeChef Solution

Problem – Count the Notebooks CodeChef Solution

You know that 1 kg of pulp can be used to make 1000 pages and 1 notebook consists of 100 pages.

Suppose a notebook factory receives N kg of pulp, how many notebooks can be made from that?

Input Format

• First line will contain T, the number of test cases. Then the test cases follow.
• Each test case contains a single integer N – the weight of the pulp the factory has (in kgs).

Output Format

For each test case, output the number of notebooks that can be made using N kgs of pulp.

Constraints

• 1≤T≤100
• 1≤N≤100

Sample 1:

Input: 3
1
100
50
Output: 10
1000
500

Explanation:

Test case-1: 1 kg of pulp can be used to make 1000 pages which can be used to make 10 notebooks.

Test case-2: 100 kg of pulp can be used to make 100000 pages which can be used to make 1000 notebooks.

Test case-3: 50 kg of pulp can be used to make 50000 pages which can be used to make 500 notebooks.

Count the Notebooks CodeChef Solution in C++17

#include <iostream>
using namespace std;

int main() {
    int t;
    cin>>t;
    while(t--){
        int n;
        cin>>n;
        cout<<n*10<<endl;
    }
	// your code goes here
	return 0;
}

Count the Notebooks CodeChef Solution in Pyth 3

# cook your dish here
t=int(input())
for i in range(t):
    n = int(input())
    print(n*10)

Count the Notebooks CodeChef Solution in Java

/* package codechef; // don't place package name! */

import java.util.*;
import java.lang.*;
import java.io.*;

/* Name of the class has to be "Main" only if the class is public. */
class Codechef
{
	public static void main (String[] args) throws java.lang.Exception
	{
		Scanner sc=new Scanner(System.in);
		int T=sc.nextInt();
		for(int i=0;i<T;i++){
		    int N=sc.nextInt();
		    int Y=(N*1000)/100;
		    System.out.println(Y);
		}
	}
}

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