Course Registration CodeChef Solution

Problem – Course Registration CodeChef Solution

There is a group of N friends who wish to enroll in a course together. The course has a maximum capacity of M students that can register for it. If there are K other students who have already enrolled in the course, determine if it will still be possible for all the N friends to do so or not.

Input Format

  • The first line contains a single integer T – the number of test cases. Then the test cases follow.
  • Each test case consists of a single line containing three integers NM and K – the size of the friend group, the capacity of the course and the number of students already registered for the course.

Output Format

For each test case, output Yes if it will be possible for all the N friends to register for the course. Otherwise output No.

You may print each character of Yes and No in uppercase or lowercase (for example, yesyEsYES will be considered identical).


  • 1≤T≤1000
  • 1≤NM≤100
  • 0≤KM

Sample 1:

Input: 3
2 50 27
5 40 38
100 100 0
Output: Yes


Test Case 1: The 2 friends can enroll in the course as it has enough seats to accommodate them and the 27 other students at the same time.

Test Case 2: The course does not have enough seats to accommodate the 5 friends and the 38 other students at the same time.

Course Registration CodeChef Solution in C++17

using namespace std;
#define int long long int 
int32_t main(){
    int t;
        int n,m,k;

Course Registration CodeChef Solution in Pyth 3

for i in range(int(input())):
    N,M,K = map(int,input().split())
    if (abs(M-K) >= N):

Course Registration CodeChef Solution in Java

import java.util.*;
import java.lang.*;

class Codechef
	public static void main (String[] args) throws java.lang.Exception
			Scanner scn= new Scanner(;    // is a standard input stream  
        int T= scn.nextInt();
       for(int i=0; i<T; i++){
        int N= scn.nextInt();
        int M= scn.nextInt();
        int K= scn.nextInt();
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