Digital clock CodeChef Solution

Problem -Digital clock CodeChef Solution

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Digital clock CodeChef Solution in C++14

#include <iostream>
using namespace std;

int main() {
	// your code goes here
	long long t;
	cin>>t;
	while(t--){
	    long long h,m;
	    cin>>h>>m;
	    long long c=0;
	    for(int i=0; i<h; i++){
	        for(int j=0; j<m; j++){
	            if((i*11==j && i!=0) || (i==j*11 && j!=0) || (i==j && i<10) || (i==j && i%11==0)){
	                c++;
	            }
	        }
	    }
	    cout<<c<<endl;
	}
	return 0;
}

Digital clock CodeChef Solution in PYTH 3

import sys
input = sys.stdin.readline
def inp():
    return(int(input()))
def inlt():
    return(list(map(int,input().split())))
def insr():
    return(input().strip())
def invr():
    return(map(int,input().split()))
def outp(n):
    sys.stdout.write(str(n) + "\n")
def outlt(lst):
    # outputs lst elements on a sigle line
    sys.stdout.write(" ".join(map(str,lst)) + "\n")
def outplt(lst):
    # outputs lst elements on seperate lines
    sys.stdout.write("\n".join(map(str,lst)))
def outpltlt(lst):
    # outputs lst of lst elements seperateed by space on seperate lines
    sys.stdout.write("\n".join(map(str,(" ".join(map(str, a)) for a in lst))))
 
# ----------------------------------------------

ans = []
for _ in range(inp()):
    H, M = inlt()
    an = 1
    for i in range(1,10):
        if i < H and i < M: an += 1
        if i < H and 11*i < M: an += 1
        if 11*i < H and i < M: an += 1
        if 11*i < H and 11*i < M: an += 1
    ans.append(an)
outplt(ans)

Digital clock CodeChef Solution in C

#include <stdio.h>

int main ()
{
    int T;
    
    scanf("%d", &T );
    
    while (T--)
    
    {
        int H, M;
        
        scanf( "%d%d", &H, &M );
        

        int  nt = 1;
        

        if ( H >= 11 )
        {
           
           
            for ( int i = 1; i <= 9 ; i++ )
            {
                if ( i <= M - 1 ) 
                
                {
                    nt++;
                }
                if ( 11 * i <= M - 1 ) 
                
                {
                     nt++;
                }
            }

           
           
            for ( int i = 1; 11*i <= H - 1; i++ )
            {
                if ( i <= M - 1 ) 
                
                {
                     nt++;
                }
                if ( 11 * i <= M - 1 ) 
                
                {
                     nt++;
                }
            }
        }
        else 
        
        {
            for ( int i = 1; i <= H - 1 ; i++ )
            {
                if ( i <= M - 1 ) 
                
                {
                     nt++;
                }
                if ( 11 * i <= M - 1 ) 
                
                {
                     nt++;
                }
            }
        }

        printf( "%d\n", nt );
    }
}

Digital clock CodeChef Solution in JAVA

/* package codechef; // don't place package name! */

import java.util.*;
import java.lang.*;
import java.io.*;

/* Name of the class has to be "Main" only if the class is public. */
class Codechef
{
	public static void main (String[] args) throws java.lang.Exception
	{
		BufferedReader reader=new BufferedReader(new InputStreamReader(System.in));
		BufferedWriter writer=new BufferedWriter(new OutputStreamWriter(System.out));
		int tt=Integer.parseInt(reader.readLine().trim());
		while(tt-->0){
		    int[] input=parseInt(reader.readLine());
		    int h=input[0], m=input[1];
		    int count=0;
		    for(int i=0;i<h;i++){
		        for(int j=0;j<m;j++){
		            String s=i+""+j;
		            boolean invalid=false;
		            for(char c: s.toCharArray()){
		                if(c!=s.charAt(0)){
		                    invalid=true;
		                }
		            }
		            if(!invalid){
		                count++;
		            }
		        }
		    }
		    writer.write(count+"\n");
		}
		writer.flush();
	}
	
    
    private static int[] parseInt(String str) {
        String[] parts=str.split("\\s+");
        int[] ans=new int[parts.length];
        for(int i=0;i<ans.length;i++){
            ans[i]=Integer.parseInt(parts[i]);
        }
        return ans;
    }

    private static long[] parseLong(String str) {
        String[] parts=str.split("\\s+");
        long[] ans=new long[parts.length];
        for(int i=0;i<ans.length;i++){
            ans[i]=Long.parseLong(parts[i]);
        }
        return ans;
    }
}

Digital clock CodeChef Solution in PYPY 3

t=int(input())
for j in range(t):
    h,m=map(int,input().split())
    count=0
    hour=''
    min=''
    for i in range(h):
        hour=str(i)
        for j in range(m):
            min=str(j)
            temp=hour+min
            if(len(set(temp))==1):
                count+=1
    print(count)

Digital clock CodeChef Solution in PYTH

for _ in xrange(input()):
    h,m = map(int, raw_input().split())
    H = h-1; M = m-1
    print min(M, H, 9)+1 + min(H, M//11) + min(M, H//11) + min(H//11, M//11)

Digital clock CodeChef Solution in C#

using System;

public class Test
{
	public static void Main()
	{
		var T = int.Parse(Console.ReadLine());
		
		while (T-- > 0)
		{
		    var numbers = Array.ConvertAll(Console.ReadLine().Split(), int.Parse);
		    
		    var h = numbers[0];
		    var m = numbers[1];
		    
		    var count = 0;
		    for (int i=0;i<h;i++){
		        
		        //Console.WriteLine(string.Format("-- i:{0}", i));
		        var hourtext = i.ToString();
		        
		        //Console.WriteLine(string.Format("HourText:{0}", hourtext));
		        
		        if (hourtext.Length == 2)
		        {
		            if (hourtext[0] != hourtext[1])
		            {
		                continue;
		                
		            }
		        }
		        
		        var onedig = i;
		        var twodigtest = string.Format("{0}{1}", i, i);
		        
		        if (hourtext.Length == 2)
		        {
		            onedig = int.Parse(hourtext[0].ToString());
		            twodigtest = i.ToString();
		        }
		        
		        var twodig = int.Parse(twodigtest);
		        
		        
		        
		        if (onedig < m)
		        {
		            //Console.WriteLine(string.Format("{0}:{1}", i, onedig));
		            count++;
		        }
		        
		        if (twodig< m & i>0)
		        {
		            //Console.WriteLine(string.Format("{0}:{1}", i, twodigtest));
		            count++;
		        }
		        
		        
		    }
		    
		    Console.WriteLine(count);
		}
	}
}

Digital clock CodeChef Solution in NODEJS

process.stdin.resume();
process.stdin.setEncoding('utf8');

// your code goes here

// your code goes here
var lineone = false;
var readline = require('readline');
var rl = readline.createInterface({
  input: process.stdin,
  output: process.stdout,
  terminal: false
});

var f=(h,m,i=10,a=1,c=(n,v,t=v,s=0)=>eval(`for(;t<n;t=''+t+v|0)s++;s`))=>eval(`for(;--i;)a+=c(h,i)*c(m,i);a`)

//console.log(f.toString().length)
rl.on('line', function(line){
    if (!lineone) {
        lineone = line;
    } else {
        param = line.split(' ').map(p => parseInt(p));
        console.log(f(param[0], param[1]));
    }
})

//console.log(f.toString().length);
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