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# Divide the Tangerine CodeChef Solution

## Divide the Tangerine CodeChef Solution in C++14

``````#include <bits/stdc++.h>

#pragma optimization_level 3
#pragma GCC optimize("Ofast,no-stack-protector,unroll-loops,fast-math,O3")
#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx")
#pragma GCC optimize("Ofast")//Comment optimisations for interactive problems (use endl)
#pragma GCC target("avx,avx2,fma")
#pragma GCC optimization ("unroll-loops")

using namespace std;

struct PairHash {inline std::size_t operator()(const std::pair<int, int> &v) const { return v.first * 31 + v.second; }};

// speed
#define Code ios_base::sync_with_stdio(false);
#define By ios::sync_with_stdio(0);
#define Sumfi cout.tie(NULL);

// alias
using ll = long long;
using ld = long double;
using ull = unsigned long long;

// constants
const ld PI = 3.14159265358979323846;  /* pi */
const ll INF = 1e18;
const ld EPS = 1e-9;
const ll MAX_N = 202020;
const ll mod = 1e9 + 7;

// typedef
typedef pair<ll, ll> pll;
typedef vector<pll> vpll;
typedef array<ll,3> all3;
typedef array<ll,5> all5;
typedef vector<all3> vall3;
typedef vector<all5> vall5;
typedef vector<ld> vld;
typedef vector<ll> vll;
typedef vector<vll> vvll;
typedef vector<int> vi;
typedef deque<ll> dqll;
typedef deque<pll> dqpll;
typedef pair<string, string> pss;
typedef vector<pss> vpss;
typedef vector<string> vs;
typedef vector<vs> vvs;
typedef unordered_set<ll> usll;
typedef unordered_set<pll, PairHash> uspll;
typedef unordered_map<ll, ll> umll;
typedef unordered_map<pll, ll, PairHash> umpll;

// macros
#define rep(i,m,n) for(ll i=m;i<n;i++)
#define rrep(i,m,n) for(ll i=n;i>=m;i--)
#define all(a) begin(a), end(a)
#define rall(a) rbegin(a), rend(a)
#define ZERO(a) memset(a,0,sizeof(a))
#define MINUS(a) memset(a,0xff,sizeof(a))
#define INF(a) memset(a,0x3f3f3f3f3f3f3f3fLL,sizeof(a))
#define ASCEND(a) iota(all(a),0)
#define sz(x) ll((x).size())
#define BIT(a,i) (a & (1ll<<i))
#define BITSHIFT(a,i,n) (((a<<i) & ((1ll<<n) - 1)) | (a>>(n-i)))
#define pyes cout<<"Yes\n";
#define pno cout<<"No\n";
#define endl "\n"
#define pneg1 cout<<"-1\n";
#define ppossible cout<<"Possible\n";
#define pimpossible cout<<"Impossible\n";
#define TC(x) cout<<"Case #"<<x<<": ";
#define X first
#define Y second

// utility functions
template <typename T>
void print(T &&t)  { cout << t << "\n"; }
template<typename T>
void printv(vector<T>v){ll n=v.size();rep(i,0,n){cout<<v[i];if(i+1!=n)cout<<' ';}cout<<endl;}
template<typename T>
void printvln(vector<T>v){ll n=v.size();rep(i,0,n)cout<<v[i]<<endl;}
void fileIO(string in = "input.txt", string out = "output.txt") {freopen(in.c_str(),"r",stdin); freopen(out.c_str(),"w",stdout);}
template<typename T>
template<typename T, typename U>
template<typename T, typename U>

struct Combination {
vll fac, inv;
ll n, MOD;

ll modpow(ll n, ll x, ll MOD = mod) { if(!x) return 1; ll res = modpow(n,x>>1,MOD); res = (res * res) % MOD; if(x&1) res = (res * n) % MOD; return res; }

Combination(ll _n, ll MOD = mod): n(_n + 1), MOD(MOD) {
inv = fac = vll(n,1);
rep(i,1,n) fac[i] = fac[i-1] * i % MOD;
inv[n - 1] = modpow(fac[n - 1], MOD - 2, MOD);
rrep(i,1,n - 2) inv[i] = inv[i + 1] * (i + 1) % MOD;
}

ll fact(ll n) {return fac[n];}
ll nCr(ll n, ll r) {
if(n < r or n < 0 or r < 0) return 0;
return fac[n] * inv[r] % MOD * inv[n-r] % MOD;
}
};

struct Matrix {
ll r,c;
vvll matrix;
Matrix(ll r, ll c, ll v = 0): r(r), c(c), matrix(vvll(r,vll(c,v))) {}

Matrix operator*(const Matrix& B) const {
Matrix res(r, B.c);
rep(i,0,r) rep(j,0,B.c) rep(k,0,B.r) {
res.matrix[i][j] = (res.matrix[i][j] + matrix[i][k] * B.matrix[k][j] % mod) % mod;
}
return res;
}

Matrix copy() {
Matrix copy(r,c);
copy.matrix = matrix;
return copy;
}

Matrix pow(ll n) {
assert(r == c);
Matrix res(r,r);
Matrix now = copy();
rep(i,0,r) res.matrix[i][i] = 1;
while(n) {
if(n & 1) res = res * now;
now = now * now;
n /= 2;
}
return res;
}
};

// geometry data structures
template <typename T>
struct Point {
T y,x;
Point(T y, T x) : y(y), x(x) {}
Point(pair<T,T> p) : y(p.first), x(p.second) {}
Point() {}
void input() {cin>>y>>x;}
friend ostream& operator<<(ostream& os, const Point<T>& p) { os<<p.y<<' '<<p.x<<'\n'; return os;}
Point<T> operator+(Point<T>& p) {return Point<T>(y + p.y, x + p.x);}
Point<T> operator-(Point<T>& p) {return Point<T>(y - p.y, x - p.x);}
Point<T> operator*(ll n) {return Point<T>(y*n,x*n); }
Point<T> operator/(ll n) {return Point<T>(y/n,x/n); }
bool operator<(const Point &other) const {if (x == other.x) return y < other.y;return x < other.x;}
Point<T> rotate(Point<T> center, ld angle) {
ld si = sin(angle * PI / 180.), co = cos(angle * PI / 180.);
ld y = this->y - center.y;
ld x = this->x - center.x;

return Point<T>(y * co - x * si + center.y, y * si + x * co + center.x);
}
ld distance(Point<T> other) {
T dy = abs(this->y - other.y);
T dx = abs(this->x - other.x);
return sqrt(dy * dy + dx * dx);
}

T norm() { return x * x + y * y; }
};

template<typename T>
struct Line {
Point<T> A, B;
Line(Point<T> A, Point<T> B) : A(A), B(B) {}
Line() {}

void input() {
A = Point<T>();
B = Point<T>();
A.input();
B.input();
}

T ccw(Point<T> &a, Point<T> &b, Point<T> &c) {
T res = a.x * b.y + b.x * c.y + c.x * a.y;
res -= (a.x * c.y + b.x * a.y + c.x * b.y);
return res;
}

bool isIntersect(Line<T> o) {
T p1p2 = ccw(A,B,o.A) * ccw(A,B,o.B);
T p3p4 = ccw(o.A,o.B,A) * ccw(o.A,o.B,B);
if (p1p2 == 0 && p3p4 == 0) {
pair<T,T> p1(A.y, A.x), p2(B.y,B.x), p3(o.A.y, o.A.x), p4(o.B.y, o.B.x);
if (p1 > p2) swap(p2, p1);
if (p3 > p4) swap(p3, p4);
return p3 <= p2 && p1 <= p4;
}
return p1p2 <= 0 && p3p4 <= 0;
}

pair<bool,Point<ld>> intersection(Line<T> o) {
if(!this->intersection(o)) return {false, {}};
ld det = 1. * (o.B.y-o.A.y)*(B.x-A.x) - 1.*(o.B.x-o.A.x)*(B.y-A.y);
ld t = ((o.B.x-o.A.x)*(A.y-o.A.y) - (o.B.y-o.A.y)*(A.x-o.A.x)) / det;
return {true, {A.y + 1. * t * (B.y - A.y), B.x + 1. * t * (B.x - A.x)}};
}

//@formula for : y = ax + b
//@return {a,b};
pair<ld, ld> formula() {
T y1 = A.y, y2 = B.y;
T x1 = A.x, x2 = B.x;
if(y1 == y2) return {1e9, 0};
if(x1 == x2) return {0, 1e9};
ld a = 1. * (y2 - y1) / (x2 - x1);
ld b = -x1 * a + y1;
return {a, b};
}
};

template<typename T>
struct Circle {
Point<T> center;
Circle() {}

void input() {
center = Point<T>();
center.input();
}

bool circumference(Point<T> p) {
return (center.x - p.x) * (center.x - p.x) + (center.y - p.y) * (center.y - p.y) == radius * radius;
}

bool intersect(Circle<T> c) {
T d = (center.x - c.center.x) * (center.x - c.center.x) + (center.y - c.center.y) * (center.y - c.center.y);
}

bool include(Circle<T> c) {
T d = (center.x - c.center.x) * (center.x - c.center.x) + (center.y - c.center.y) * (center.y - c.center.y);
}
};

ll __gcd(ll x, ll y) { return !y ? x : __gcd(y, x % y); }
all3 __exgcd(ll x, ll y) { if(!y) return {x,1,0}; auto [g,x1,y1] = __exgcd(y, x % y); return {g, y1, x1 - (x/y) * y1}; }
ll __lcm(ll x, ll y) { return x / __gcd(x,y) * y; }
ll modpow(ll n, ll x, ll MOD = mod) { n%=MOD; if(!x) return 1; ll res = modpow(n,x>>1,MOD); res = (res * res) % MOD; if(x&1) res = (res * n) % MOD; return res; }

bool solve(vpll A, vpll B) {
usll a, b;
rep(i,0,sz(A)) a.insert(A[i].first - 1);
rep(i,0,sz(B)) b.insert(B[i].first - 1);
for(auto& now : b) if(!a.count(now)) return false;
return true;
}
int main() {
Code By Sumfi
cout.precision(12);
ll tc = 1;
cin>>tc;
rep(i,1,tc+1) {
ll n,a,b;
cin>>n>>a>>b;
vpll A(a), B(b);
if(solve(A,B)) pyes else pno
}
return 0;
}``````

## Divide the Tangerine CodeChef Solution in PYTH 3

``````# cook your dish here

def solution(chefsdiv, kidsdiv):
if len(kidsdiv) > len(chefsdiv): return False

chefsdiv.sort()
kidsdiv.sort()

i, j = 0, 0
while i <len(chefsdiv) and j <len(kidsdiv):
if chefsdiv[i][0] == kidsdiv[j][0]:
i += 1
j += 1
elif chefsdiv[i][0] < kidsdiv[j][0]:
i += 1
else:
return False
return j == len(kidsdiv)

t = int(input())
while t:
n, k, p = map(int, input().split())
chefsdiv = []
kidsdiv = []

for _ in range(k):
chefsdiv.append(list(map(int, input().split())))
for _ in range(p):
kidsdiv.append(list(map(int, input().split())))

res = 'Yes' if solution(chefsdiv, kidsdiv) else 'No'
print(res)
t -= 1``````

## Divide the Tangerine CodeChef Solution in C

``````#include<stdio.h>
int main() {

int t,n,i,j,k,p,a[500],b[500];
scanf("%d",&t);
while(t--)
{
scanf("%d %d %d",&n,&k,&p);

for(i=0;i<k;i++){
scanf("%d",&j);
a[i]=j;
scanf("%d",&j);
}
for(i=0;i<p;i++){
scanf("%d",&j);
b[i]=j;
scanf("%d",&j);
}
for(i=0;i<p;i++){
for(j=0;j<k;j++){
if(b[i]==a[j]){
break;
}
}
if(j==k){
printf("No\n");
break;
}
}
if(i==p)
printf("Yes\n");
}
return 0;
}``````

## Divide the Tangerine CodeChef Solution in JAVA

``````/* package codechef; // don't place package name! */

import java.io.*;
import java.util.*;
class tang implements Comparable<tang>
{
int st,end;
public tang(int s,int e)
{
this.st=s;
this.end=e;
}
public int compareTo(tang ob)
{
return Integer.compare(this.st,ob.st);
}
public static void main(String args[])throws IOException
{
int t=sc.nextInt();
for(int z=1;z<=t;z++)
{
int n=sc.nextInt();
int k=sc.nextInt();
int p=sc.nextInt();
List<tang> list=new ArrayList<>();
for(int i=0;i<k;i++)
{
}
Collections.sort(list);
HashSet<Integer> start=new HashSet<>();
HashSet<Integer> end=new HashSet<>();
for(int i=0;i<k;i++)
{
tang ob1=list.get(i);
if(i==0)
{
}
else
{
tang ob2=list.get(i-1);
if(ob1.st-ob2.end == 1)
{
}
else if(ob1.st-ob2.end > 1)
{
}
else
{
if((n-ob2.end+ob1.st) > 1)
{
if(ob2.end==n)
else
if(ob1.st==1)
else
}
else
{
}
}
}
}
int f=0;
for(int i=0;i<p;i++)
{
int a=sc.nextInt();
int b=sc.nextInt();
if(!start.contains(a))
{
f=1;
//break;
}
if(!end.contains(b))
{
f=1;
//break;
}
}

if(f==0)
System.out.println("Yes");
else
System.out.println("No");
}
}
}
final private int BUFFER_SIZE = 1 << 16;
private DataInputStream din;
private byte [] buffer;
din = new DataInputStream (System.in);
buffer = new byte[BUFFER_SIZE];
}

public Reader (String file_name) throws IOException {
din = new DataInputStream (new FileInputStream (file_name));
buffer = new byte[BUFFER_SIZE];
}

public String readLine () throws IOException {
byte [] buf = new byte[1024];
int cnt = 0, c;
while ((c = read ()) != -1) {
if (c == '\n')
break;
buf[cnt++] = (byte) c;
}
return new String (buf, 0, cnt);
}

public int nextInt () throws IOException {
int ret = 0;
while (c <= ' ')
boolean neg = (c == '-');
if (neg)
do {
ret = ret * 10 + c - '0';
} while ((c = read ()) >= '0' && c <= '9');
if (neg)
return -ret;
return ret;
}

public long nextLong () throws IOException {
long ret = 0;
while (c <= ' ')
boolean neg = (c == '-');
if (neg)
do {
ret = ret * 10 + c - '0';
} while ((c = read ()) >= '0' && c <= '9');
if (neg)
return -ret;
return ret;
}

public double nextDouble () throws IOException {
double ret = 0, div = 1;
while (c <= ' ')
boolean neg = (c == '-');
if (neg)
do {
ret = ret * 10 + c - '0';
} while ((c = read ()) >= '0' && c <= '9');
if (c == '.')
while ((c = read ()) >= '0' && c <= '9')
ret += (c - '0') / (div *= 10);
if (neg)
return -ret;
return ret;
}
private void fillBuffer () throws IOException {
buffer[0] = -1;
}

private byte read () throws IOException {
fillBuffer ();
return buffer[bufferPointer++];
}

public void close () throws IOException {
if (din == null)
return;
din.close ();
}
}``````

## Divide the Tangerine CodeChef Solution in PYTH

``````t=int(raw_input())
while t:
flag=0
t-=1
n,k,p=map(int,raw_input().split())
a=[]
while k:
k-=1
x,y=raw_input().split()
a.append(x)
st=set(a)
while p:
p-=1
x,y=raw_input().split()
if x not in st :
flag=1
if flag==1:
print 'No'
else:
print 'Yes' ``````

## Divide the Tangerine CodeChef Solution in C#

``````using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

namespace tangdiv
{
class Program
{
static int[] ptemp = new int[501];
static int[] ftemp = new int[501];

static void merge_sort(int[] a, int[] b, int l, int m, int r)
{
int i, j, k;
int g;
i = l;
j = m + 1;
k = l;

while (i <= m && j <= r)
{
if (a[i] <= a[j])
{ ptemp[k] = a[i]; ftemp[k] = b[i]; k++; i++; }
else
{ ptemp[k] = a[j]; ftemp[k] = b[j]; k++; j++; }
}

while (i <= m)
{ ptemp[k] = a[i]; ftemp[k] = b[i]; k++; i++; }

while (j <= r)
{ ptemp[k] = a[j]; ftemp[k] = b[j]; k++; j++; }

for (g = l; g <= r; g++)
{ a[g] = ptemp[g]; b[g] = ftemp[g]; }
}

static void merge(int[] a, int[] b, int l, int u)
{
int ub, lb, mid;
lb = l;
ub = u;
mid = (lb + ub) / 2;
if (lb < ub)
{
merge(a, b, lb, mid);
merge(a, b, mid + 1, ub);
merge_sort(a, b, lb, mid, ub);
}
}
static void Main(string[] args)
{
int t, n, k, p;
String[] str;
bool flag;
int[] c1 = new int[501];
int[] b1 = new int[501];
int[] c2 = new int[501];
int[] b2 = new int[501];

while (t-- > 0)
{
n = int.Parse(str[0]);
k = int.Parse(str[1]);
p = int.Parse(str[2]);

for (int i = 1; i <= k; i++)
{
c1[i] = int.Parse(str[0]);
c2[i] = int.Parse(str[1]);
}

for (int i = 1; i <= p; i++)
{
b1[i] = int.Parse(str[0]);
b2[i] = int.Parse(str[1]);
}
if (p > k)
{
Console.WriteLine("No");
continue;
}

merge(c1, c2, 1, k);
merge(b1, b2, 1, p);

if (c1[k] > c2[k])
{
if (b1[p] > b2[p])
{
b2[p] += n;
c2[k] += n;
}
else
{
Console.WriteLine("No");
continue;
}
}

int f = p;
int x;
for(x = 1; x <= k; x++){
if(c1[x] >= b1[1])
break;
if(c1[x] < b1[1]){
c1[x] += n;
c2[x] += n;
}
}
if(x > 1)
merge(c1,c2,1,k);
if (c1[k] > c2[k])
{
if (b1[p] > b2[p])
{
b2[p] += n;
c2[k] += n;

}
else
{
Console.WriteLine("No");
continue;
}
}

flag = true;

int j = 1;
for (int i = 1; i <= p; )
{
if (c1[j] < b1[i] || b2[i] < c2[j])
{
flag = false;
break;
}
b1[i] = c2[j]+1;

if (b1[i] > b2[i])
i++;
j++;

}

if (flag)
Console.WriteLine("Yes");
else
Console.WriteLine("No");
}
}
}
}``````

## Divide the Tangerine CodeChef Solution in GO

``````package main

import (
"bufio"
"fmt"
"os"
"sort"
)

func readInt(bytes []byte, from int, val *int) int {
i := from
tmp := 0
for i < len(bytes) && bytes[i] != ' ' {
tmp = tmp*10 + int(bytes[i]-'0')
i++
}
*val = tmp
return i
}

func readNum(scanner *bufio.Scanner) (a int) {
scanner.Scan()
return
}

func readTwoNums(scanner *bufio.Scanner) (a int, b int) {
scanner.Scan()
return
}

func readThreeNums(scanner *bufio.Scanner) (a int, b int, c int) {
scanner.Scan()
return
}

func readNNums(scanner *bufio.Scanner, n int) []int {
res := make([]int, n)
x := -1
scanner.Scan()
for i := 0; i < n; i++ {
}
return res
}

func main() {
scanner := bufio.NewScanner(os.Stdin)

for t > 0 {
A := make([][]int, k)
for i := 0; i < k; i++ {
}

P := make([][]int, p)
for i := 0; i < p; i++ {
}

res := solve(n, k, p, A, P)

if res {
fmt.Println("Yes")
} else {
fmt.Println("No")
}

t--
}
}

func solve(n, k, p int, A [][]int, P [][]int) bool {
if k < p {
return false
}
xs := make(PRS, k)
for i := 0; i < k; i++ {
xs[i] = &PR{A[i][0], A[i][1]}
}

ys := make(PRS, p)
for i := 0; i < p; i++ {
ys[i] = &PR{P[i][0], P[i][1]}
}

sort.Sort(xs)
sort.Sort(ys)

var ii, jj int

for ii < k && jj < p {
if xs[ii].from == ys[jj].from {
break
}
if xs[ii].from < ys[jj].from {
ii++
} else {
jj++
}
}

if ii == k || jj == p {
// can not align
return false
}

if ii > 0 {
zs := make(PRS, k)
copy(zs, xs[ii:])
copy(zs[k-ii:], xs[:ii])
xs = zs
}
if jj > 0 {
zs := make(PRS, p)
copy(zs, ys[jj:])
copy(zs[p-jj:], ys[:jj])
ys = zs
}

for i := 0; i < k; i++ {
if i > 0 {
if xs[i].from < xs[i-1].end {
xs[i].from += n
}
}
if xs[i].end < xs[i].from {
xs[i].end += n
}
}

for i := 0; i < p; i++ {
if i > 0 {
if ys[i].from < ys[i-1].end {
ys[i].from += n
}
}
if ys[i].end < ys[i].from {
ys[i].end += n
}
}

ii, jj = 0, 0
for ii < k && jj < p {
if xs[ii].end > ys[jj].end {
return false
}
if xs[ii].end == ys[jj].end {
jj++
}
ii++
}
return ii == k && jj == p
}

type PR struct {
from, end int
}

type PRS []*PR

func (this PRS) Len() int {
return len(this)
}

func (this PRS) Less(i, j int) bool {
return this[i].from < this[j].from
}

func (this PRS) Swap(i, j int) {
this[i], this[j] = this[j], this[i]
}``````
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##### Conclusion:

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