Divisible by 3 CodeChef Solution

Problem – Divisible by 3 CodeChef Solution

Stack likes the number 3 a lot.

He has two non-negative integers A and B.
In one operation, Stack can do either of the following:

• A:=∣A−B∣ (change A to ∣A−B∣)
• B:=∣A−B∣ (change B to ∣A−B∣)

Note that ∣X∣ denotes absolute value of X. For example ∣−7∣=7 and ∣4∣=4.

Find the minimum number of operations after which at least one integer out of A and B becomes divisible by 3.

Input Format

• The first line of input contains a single integer T, denoting the number of test cases. The description of T test cases follows.
• The only line of each test case contains two integers A and B.

Output Format

For each test case, output in a single line the minimum number of operations after which at least one integer out of A and B becomes divisible by 3.

Constraints

• 1≤T≤10^5
• 0≤A,B≤10^9

Sample 1:

Input:
2
0 343
1 1
Output:
0
1

Explanation:

Test case 1: A=0 is already divisible by 3.

Test case 2: In the only operation, Stack can change A=1 to A=∣A−B∣=∣1−1∣=0. Now A=0 is divisible by 3.

Divisible by 3 CodeChef Solution in C++17

#include <iostream>
#include<cstdlib>
using namespace std;

int main() {
	int t;
	cin>>t;
	while(t--){
	    int a,b;
	    cin>>a>>b;
	    if((a%3==0) || (b%3==0)){
	        cout<<0<<endl;
	    }
	    else if((abs(a-b))%3==0){
	        cout<<1<<endl;
	    }
	    else{
	        cout<<2<<endl;
	    }
	}
	return 0;
}

Divisible by 3 CodeChef Solution in Java

/* package codechef; // don't place package name! */

import java.util.*;
import java.lang.*;
import java.io.*;

/* Name of the class has to be "Main" only if the class is public. */
class Codechef
{
	public static void main (String[] args) throws java.lang.Exception
	{
		// your code goes here
		Scanner sc=new Scanner(System.in);
		int t=sc.nextInt();
		while(t-->0){
		    int a=sc.nextInt();
		    int b=sc.nextInt();
		    int count=0;
		    while(!(a%3==0 || b%3==0)){
	            if(a>b) a=Math.abs(a-b);
	            else b=Math.abs(a-b);
	            count++;
	        }
	        System.out.println(count);
		}
	}
}

Divisible by 3 CodeChef Solution in Pyth 3

# cook your dish here
for i in range(int(input())):
    a,b=map(int,input().split())
    if (a*b)%3==0:
        print(0)
    elif (a-b)%3 == 0:
        print(1)
    else:
        print(2)

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