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In the medieval age, there were 3 kingdoms A, B, and C. The army of these kingdom had NA, NB, and NCsoldiers respectively.
You are given that an army with X soldiers can defeat an army with Y soldiers only if X>Y.
An army is said to be dominant if it can defeat both the other armies combined. For example, kingdom C‘s army will be dominant only if NC>NA+NB.
Determine whether any of the armies is dominant or not.
For each test case, output YES
if any of the armies is dominant. Otherwise, output NO
.
You may print each character of YES
and NO
in uppercase or lowercase (for example, yes
, yEs
, Yes
will be considered identical).
Input: 4
15 5 6
12 13 16
1 1 100
10 10 20
Output: YES
NO
YES
NO
Test case 1: The kingdom A‘s army is dominant since 15>5+6.
Test case 2: We can observe that none of the armies is dominant.
Test case 3: The kingdom C‘s army is dominant since 100>1+1.
Test case 4: We can observe that none of the armies is dominant. Note that the kingdom C‘s army is not dominant since 20≤10+10.
#include <iostream>
using namespace std;
int main() {
int t; cin>>t; while(t--)
{
int a,b,c;
cin>>a>>b>>c;
cout<<(a>b+c || b>a+c || c>a+b ? "YES" : "NO")<<endl;
}
return 0;
}
T = int(input())
for i in range(T):
A,B,C=map(int,input().split())
if A>(B+C) or B>(C+A) or C>(A+B):
print("YES")
else:
print("NO")
import java.util.*;
import java.lang.*;
import java.io.*;
class Codechef
{
public static void main (String[] args) throws java.lang.Exception
{
Scanner sc=new Scanner(System.in);
int t=sc.nextInt();
while(t-- >0)
{
int x=sc.nextInt();
int y=sc.nextInt();
int z=sc.nextInt();
if(x>(y+z)) System.out.println("YES");
else if(y>(x+z)) System.out.println("YES");
else if(z>(x+y)) System.out.println("YES");
else System.out.println("NO");
}
}
}
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