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Equal LIS CodeChef Solution
Problem -Equal LIS CodeChef Solution
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Equal LIS CodeChef Solution in C++17
/*ॐ Arpit Blagan ॐ*/
#include<bits/stdc++.h>
using namespace std;
#define all(arr) arr.begin(),arr.end()
#define rep(i,s,e) for(int i=s;i<e;i++)
#define lli long long int
#define ll long long
const ll INF=1e18;
const int mod=1e9+7;
int main(){
ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);
int t;cin>>t;
while(t--){
int n;cin>>n;
if(n==2){cout<<"NO\n";}
else{ cout<<"YES\n";
int mid=n/2;
vector<int>ans;
for(int i=1;i<=mid;i++){ans.push_back(i);}
for(int i=n;i>mid;i--){ans.push_back(i);}
if(n%2==0){swap(ans[0],ans[1]);}
for(auto it:ans){cout<<it<<" ";}cout<<"\n";
}
}
return 0;
}Equal LIS CodeChef Solution in C++14
#include <bits/stdc++.h>
#pragma optimization_level 3
#pragma GCC optimize("Ofast,no-stack-protector,unroll-loops,fast-math,O3")
#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx")
#pragma GCC optimize("Ofast")//Comment optimisations for interactive problems (use endl)
#pragma GCC target("avx,avx2,fma")
#pragma GCC optimization ("unroll-loops")
using namespace std;
struct PairHash {inline std::size_t operator()(const std::pair<int, int> &v) const { return v.first * 31 + v.second; }};
// speed
#define Code ios_base::sync_with_stdio(false);
#define By ios::sync_with_stdio(0);
#define Sumfi cout.tie(NULL);
// alias
using ll = long long;
using ld = long double;
using ull = unsigned long long;
// constants
const ld PI = 3.14159265358979323846; /* pi */
const ll INF = 1e18;
const ld EPS = 1e-9;
const ll MAX_N = 101010;
const ll mod = 998244353;
// typedef
typedef pair<ll, ll> pll;
typedef vector<pll> vpll;
typedef array<ll,3> all3;
typedef array<ll,5> all5;
typedef vector<all3> vall3;
typedef vector<all5> vall5;
typedef vector<ld> vld;
typedef vector<ll> vll;
typedef vector<vll> vvll;
typedef vector<int> vi;
typedef deque<ll> dqll;
typedef deque<pll> dqpll;
typedef pair<string, string> pss;
typedef vector<pss> vpss;
typedef vector<string> vs;
typedef vector<vs> vvs;
typedef unordered_set<ll> usll;
typedef unordered_set<pll, PairHash> uspll;
typedef unordered_map<ll, ll> umll;
typedef unordered_map<pll, ll, PairHash> umpll;
// macros
#define rep(i,m,n) for(ll i=m;i<n;i++)
#define rrep(i,m,n) for(ll i=n;i>=m;i--)
#define all(a) begin(a), end(a)
#define rall(a) rbegin(a), rend(a)
#define ZERO(a) memset(a,0,sizeof(a))
#define MINUS(a) memset(a,0xff,sizeof(a))
#define INF(a) memset(a,0x3f3f3f3f3f3f3f3fLL,sizeof(a))
#define ASCEND(a) iota(all(a),0)
#define sz(x) ll((x).size())
#define BIT(a,i) (a & (1ll<<i))
#define BITSHIFT(a,i,n) (((a<<i) & ((1ll<<n) - 1)) | (a>>(n-i)))
#define pyes cout<<"YES\n";
#define pno cout<<"NO\n";
#define endl "\n"
#define pneg1 cout<<"-1\n";
#define ppossible cout<<"Possible\n";
#define pimpossible cout<<"Impossible\n";
#define TC(x) cout<<"Case #"<<x<<": ";
#define X first
#define Y second
// utility functions
template <typename T>
void print(T &&t) { cout << t << "\n"; }
template<typename T>
void printv(vector<T>v){ll n=v.size();rep(i,0,n){cout<<v[i];if(i+1!=n)cout<<' ';}cout<<endl;}
template<typename T>
void printvln(vector<T>v){ll n=v.size();rep(i,0,n)cout<<v[i]<<endl;}
void fileIO(string in = "input.txt", string out = "output.txt") {freopen(in.c_str(),"r",stdin); freopen(out.c_str(),"w",stdout);}
void readf() {freopen("", "rt", stdin);}
template<typename T>
void readv(vector<T>& v){rep(i,0,sz(v)) cin>>v[i];}
template<typename T, typename U>
void readp(pair<T,U>& A) {cin>>A.first>>A.second;}
template<typename T, typename U>
void readvp(vector<pair<T,U>>& A) {rep(i,0,sz(A)) readp(A[i]); }
void readvall3(vall3& A) {rep(i,0,sz(A)) cin>>A[i][0]>>A[i][1]>>A[i][2];}
void readvall5(vall5& A) {rep(i,0,sz(A)) cin>>A[i][0]>>A[i][1]>>A[i][2]>>A[i][3]>>A[i][4];}
void readvvll(vvll& A) {rep(i,0,sz(A)) readv(A[i]);}
struct Combination {
vll fac, inv;
ll n, MOD;
ll modpow(ll n, ll x, ll MOD = mod) { if(!x) return 1; ll res = modpow(n,x>>1,MOD); res = (res * res) % MOD; if(x&1) res = (res * n) % MOD; return res; }
Combination(ll _n, ll MOD = mod): n(_n + 1), MOD(MOD) {
inv = fac = vll(n,1);
rep(i,1,n) fac[i] = fac[i-1] * i % MOD;
inv[n - 1] = modpow(fac[n - 1], MOD - 2, MOD);
rrep(i,1,n - 2) inv[i] = inv[i + 1] * (i + 1) % MOD;
}
ll fact(ll n) {return fac[n];}
ll nCr(ll n, ll r) {
if(n < r or n < 0 or r < 0) return 0;
return fac[n] * inv[r] % MOD * inv[n-r] % MOD;
}
};
struct Matrix {
ll r,c;
vvll matrix;
Matrix(ll r, ll c, ll v = 0): r(r), c(c), matrix(vvll(r,vll(c,v))) {}
Matrix operator*(const Matrix& B) const {
Matrix res(r, B.c);
rep(i,0,r) rep(j,0,B.c) rep(k,0,B.r) {
res.matrix[i][j] = (res.matrix[i][j] + matrix[i][k] * B.matrix[k][j] % mod) % mod;
}
return res;
}
Matrix copy() {
Matrix copy(r,c);
copy.matrix = matrix;
return copy;
}
Matrix pow(ll n) {
assert(r == c);
Matrix res(r,r);
Matrix now = copy();
rep(i,0,r) res.matrix[i][i] = 1;
while(n) {
if(n & 1) res = res * now;
now = now * now;
n /= 2;
}
return res;
}
};
// geometry data structures
template <typename T>
struct Point {
T y,x;
Point(T y, T x) : y(y), x(x) {}
Point(pair<T,T> p) : y(p.first), x(p.second) {}
Point() {}
void input() {cin>>y>>x;}
friend ostream& operator<<(ostream& os, const Point<T>& p) { os<<p.y<<' '<<p.x<<'\n'; return os;}
Point<T> operator+(Point<T>& p) {return Point<T>(y + p.y, x + p.x);}
Point<T> operator-(Point<T>& p) {return Point<T>(y - p.y, x - p.x);}
Point<T> operator*(ll n) {return Point<T>(y*n,x*n); }
Point<T> operator/(ll n) {return Point<T>(y/n,x/n); }
bool operator<(const Point &other) const {if (x == other.x) return y < other.y;return x < other.x;}
Point<T> rotate(Point<T> center, ld angle) {
ld si = sin(angle * PI / 180.), co = cos(angle * PI / 180.);
ld y = this->y - center.y;
ld x = this->x - center.x;
return Point<T>(y * co - x * si + center.y, y * si + x * co + center.x);
}
ld distance(Point<T> other) {
T dy = abs(this->y - other.y);
T dx = abs(this->x - other.x);
return sqrt(dy * dy + dx * dx);
}
T norm() { return x * x + y * y; }
};
template<typename T>
struct Line {
Point<T> A, B;
Line(Point<T> A, Point<T> B) : A(A), B(B) {}
Line() {}
void input() {
A = Point<T>();
B = Point<T>();
A.input();
B.input();
}
T ccw(Point<T> &a, Point<T> &b, Point<T> &c) {
T res = a.x * b.y + b.x * c.y + c.x * a.y;
res -= (a.x * c.y + b.x * a.y + c.x * b.y);
return res;
}
bool isIntersect(Line<T> o) {
T p1p2 = ccw(A,B,o.A) * ccw(A,B,o.B);
T p3p4 = ccw(o.A,o.B,A) * ccw(o.A,o.B,B);
if (p1p2 == 0 && p3p4 == 0) {
pair<T,T> p1(A.y, A.x), p2(B.y,B.x), p3(o.A.y, o.A.x), p4(o.B.y, o.B.x);
if (p1 > p2) swap(p2, p1);
if (p3 > p4) swap(p3, p4);
return p3 <= p2 && p1 <= p4;
}
return p1p2 <= 0 && p3p4 <= 0;
}
pair<bool,Point<ld>> intersection(Line<T> o) {
if(!this->intersection(o)) return {false, {}};
ld det = 1. * (o.B.y-o.A.y)*(B.x-A.x) - 1.*(o.B.x-o.A.x)*(B.y-A.y);
ld t = ((o.B.x-o.A.x)*(A.y-o.A.y) - (o.B.y-o.A.y)*(A.x-o.A.x)) / det;
return {true, {A.y + 1. * t * (B.y - A.y), B.x + 1. * t * (B.x - A.x)}};
}
//@formula for : y = ax + b
//@return {a,b};
pair<ld, ld> formula() {
T y1 = A.y, y2 = B.y;
T x1 = A.x, x2 = B.x;
if(y1 == y2) return {1e9, 0};
if(x1 == x2) return {0, 1e9};
ld a = 1. * (y2 - y1) / (x2 - x1);
ld b = -x1 * a + y1;
return {a, b};
}
};
template<typename T>
struct Circle {
Point<T> center;
T radius;
Circle(T y, T x, T radius) : center(Point<T>(y,x)), radius(radius) {}
Circle(Point<T> center, T radius) : center(center), radius(radius) {}
Circle() {}
void input() {
center = Point<T>();
center.input();
cin>>radius;
}
bool circumference(Point<T> p) {
return (center.x - p.x) * (center.x - p.x) + (center.y - p.y) * (center.y - p.y) == radius * radius;
}
bool intersect(Circle<T> c) {
T d = (center.x - c.center.x) * (center.x - c.center.x) + (center.y - c.center.y) * (center.y - c.center.y);
return (radius - c.radius) * (radius - c.radius) <= d and d <= (radius + c.radius) * (radius + c.radius);
}
bool include(Circle<T> c) {
T d = (center.x - c.center.x) * (center.x - c.center.x) + (center.y - c.center.y) * (center.y - c.center.y);
return d <= radius * radius;
}
};
ll __gcd(ll x, ll y) { return !y ? x : __gcd(y, x % y); }
all3 __exgcd(ll x, ll y) { if(!y) return {x,1,0}; auto [g,x1,y1] = __exgcd(y, x % y); return {g, y1, x1 - (x/y) * y1}; }
ll __lcm(ll x, ll y) { return x / __gcd(x,y) * y; }
ll modpow(ll n, ll x, ll MOD = mod) { n%=MOD; if(!x) return 1; ll res = modpow(n,x>>1,MOD); res = (res * res) % MOD; if(x&1) res = (res * n) % MOD; return res; }
vll solve(ll n) {
if(n == 1) return {1};
if(n == 2) return {};
if(n & 1) {
dqll res{n};
n -= 1;
while(n) {
res.push_back(n);
res.push_front(n-1);
n -= 2;
}
return vll(all(res));
}
vll res;
for(ll i = 3; i < n; i += 2) res.push_back(i);
res.push_back(1);
for(ll i = n; i >= 2; i -= 2) res.push_back(i);
return res;
}
int main() {
Code By Sumfi
cout.precision(12);
ll tc = 1;
cin>>tc;
rep(i,1,tc+1) {
ll n;
cin>>n;
auto res = solve(n);
if(sz(res)) {
pyes
printv(res);
} else pno
}
return 0;
}Equal LIS CodeChef Solution in PYTH 3
# cook your dish here
# cook your dish here
for _ in range(int(input())):
n=int(input())
if(n%2):
print("Yes")
for i in range(1,n//2+1):
print(i,end=" ")
for i in range(n,(n//2),-1):
print(i,end=" ")
print()
elif(n!=2):
print("Yes")
print(n//2,end=" ")
for i in range(1,n//2):
print(i,end=" ")
for i in range(n,n//2,-1):
print(i,end=" ")
print()
else:
print("No")Equal LIS CodeChef Solution in C
#include <stdio.h>
void solve()
{
int k,i,m,l;
scanf("%d",&k);
if(k==2)
printf("NO\n");
else if(k%2==0)
{
l=k;
m=1;
printf("YES\n%d ",(k/2)+1);
for(i=2;i<=k;i++)
{
if(i%2==0)
{
printf("%d ",m);
m++;
}
else
{
printf("%d ",l);
l--;
}
}
printf("\n");
}
else
{
m=1;
l=k;
printf("YES\n");
for(i=1;i<=k;i++)
{
if(i%2!=0)
{
printf("%d ",m);
m++;
}
else
{
printf("%d ",l);
l--;
}
}
printf("\n");
}
}
int main()
{
int t;
scanf("%d",&t);
while(t--)
{
solve();
}
return 0;
}Equal LIS CodeChef Solution in JAVA
/* package codechef; // don't place package name! */
import java.util.*;
import java.lang.*;
import java.io.*;
/* Name of the class has to be "Main" only if the class is public. */
class Codechef
{
public static void main (String[] args) throws java.lang.Exception
{
Scanner sc=new Scanner(System.in);
int t=sc.nextInt();
for(int tt=0;tt<t;tt++){
int n=sc.nextInt();
if(n==2){
System.out.println("NO");
}
else if(n%2==1){
System.out.println("YES");
for(int i=1;i<(n+1)/2;i++){
System.out.print(i+" ");
}
for(int i=n;i>=(n+1)/2;i--){
System.out.print(i+" ");
}
}
else if(n>2){
System.out.println("YES");
int[] a=new int[n];
for(int i=0;i<n/2;i++){
a[i]=i+1;
}
for(int i=n/2;i<n;i++){
a[i]=n-i+n/2;
}
a[0]=2;
a[1]=1;
for(int i:a){
System.out.print(i+" ");
}
System.out.println();
}
}
}
}
Equal LIS CodeChef Solution in PYPY 3
def solve():
n= int(input())
if(n%2==0):
if(n==2):
print("NO")
else :
print("YES")
print(2, end =" ")
print(1, end =" ")
for i in range (2, n//2 +1, 1):
print(i*2, end =" ")
for i in range(n-1, 2, -2):
print(i, end =" ")
print()
else :
print("YES")
for i in range (1, (n+1)//2, 1):
print(2*i, end =" ")
for i in range (n, 0, -2):
print(i, end =" ")
print()
def main ():
t=int(input())
while(t>0):
t=t-1
solve()
# n,k = [int(x) for x in input().split()]
# arr = [int(x) for x in input().split()]
# Flipped( n,k ,arr)
if __name__ == "__main__": main ()Equal LIS CodeChef Solution in C#
using System;
using System.Collections.Generic;
using System.Globalization;
using System.Linq;
using System.Text;
using System.Text.RegularExpressions;
namespace Codeforces
{
public class Program
{
private static int _mod = (int)1e9 + 7;
static void Main(string[] args)
{
//Precompute();
int t = int.Parse(Console.ReadLine());
for (int i = 0; i < t; i++)
Solve();
}
public static List<int> _nums { get; set; }
public static void Solve()
{
int n = GetInt();
List<int> ans = new List<int>();
if(n<=2)
{
Console.WriteLine("NO");
return;
}
else if(n%2 == 0)
{
ans.AddRange(Enumerable.Range(n / 2 + 1, n / 2).Reverse());
ans.AddRange(Enumerable.Range(1, n / 2));
int a = ans[0];
int b = ans[1];
ans[0] = b;
ans[1] = a;
}
else
{
ans.AddRange(Enumerable.Range((n+1)/2+1, n / 2).Reverse());
ans.AddRange(Enumerable.Range(1, (n + 1) / 2));
}
#if DEBUG
Console.Write("Answer is -----------> ");
#endif
Console.WriteLine("YES\n" + string.Join(" ",ans));
}
public static int DoubleIt(int n)
{
int b = 0;
for(int i=15; i>=0; i--)
{
b *= 4;
if ((n & (1 << i)) != 0)
b += 3;
}
return b;
}
public static int GetInt() => int.Parse(Console.ReadLine());
public static long GetLong() => long.Parse(Console.ReadLine());
public static int[] GetIntArray() => Console.ReadLine().Trim().Split(' ').Select(int.Parse).ToArray();
public static long[] GetLongArray() => Console.ReadLine().Trim().Split(' ').Select(long.Parse).ToArray();
public static double[] GetDoublesArray() => Console.ReadLine().Trim().Split(' ').Select(d => Convert.ToDouble(d, CultureInfo.InvariantCulture)).ToArray();
public static long Gcd(long a, long b) => b == 0 ? a : Gcd(b, a % b);
public static long Gcd(long[] a) => a.Aggregate(a[0], (x, y) => Gcd(x, y));
public static long Lcm(long a, long b) => a * b / Gcd(a, b);
public static long Lcm(IEnumerable<int> a) => a.Aggregate(1L, (x, y) => Lcm(x, y));
public static void Swap(ref long a, ref long b)
{
long t = a;
a = b;
b = t;
}
public static void Swap(ref int a, ref int b)
{
int t = a;
a = b;
b = t;
}
public static void OutputSequence(IEnumerable<long> x) => Console.WriteLine($" >> " + string.Join(", ", x));
public static string Rev(string s) => string.Concat(s.ToArray().Reverse());
public static Dictionary<char, long> Frequencies(char[] a)
{
var ans = new Dictionary<char, long>();
foreach (char k in a)
{
if (ans.ContainsKey(k))
ans[k]++;
else
ans[k] = 1;
}
return ans;
}
}
}Equal LIS CodeChef Solution in GO
package main
import (
"bufio"
"bytes"
"fmt"
"os"
)
func main() {
reader := bufio.NewReader(os.Stdin)
tc := readNum(reader)
var buf bytes.Buffer
for tc > 0 {
tc--
n := readNum(reader)
res := solve(n)
if len(res) == 0 {
buf.WriteString("NO\n")
continue
}
buf.WriteString("YES\n")
for i := 0; i < n; i++ {
buf.WriteString(fmt.Sprintf("%d ", res[i]))
}
buf.WriteByte('\n')
}
fmt.Println(buf.String())
}
func readInt(bytes []byte, from int, val *int) int {
i := from
sign := 1
if bytes[i] == '-' {
sign = -1
i++
}
tmp := 0
for i < len(bytes) && bytes[i] >= '0' && bytes[i] <= '9' {
tmp = tmp*10 + int(bytes[i]-'0')
i++
}
*val = tmp * sign
return i
}
func readString(reader *bufio.Reader) string {
s, _ := reader.ReadString('\n')
for i := 0; i < len(s); i++ {
if s[i] == '\n' {
return s[:i]
}
}
return s
}
func readNum(reader *bufio.Reader) (a int) {
bs, _ := reader.ReadBytes('\n')
readInt(bs, 0, &a)
return
}
func readTwoNums(reader *bufio.Reader) (a int, b int) {
res := readNNums(reader, 2)
a, b = res[0], res[1]
return
}
func readThreeNums(reader *bufio.Reader) (a int, b int, c int) {
res := readNNums(reader, 3)
a, b, c = res[0], res[1], res[2]
return
}
func readNNums(reader *bufio.Reader, n int) []int {
res := make([]int, n)
x := 0
bs, _ := reader.ReadBytes('\n')
for i := 0; i < n; i++ {
for x < len(bs) && (bs[x] < '0' || bs[x] > '9') && bs[x] != '-' {
x++
}
x = readInt(bs, x, &res[i])
}
return res
}
func readUint64(bytes []byte, from int, val *uint64) int {
i := from
var tmp uint64
for i < len(bytes) && bytes[i] >= '0' && bytes[i] <= '9' {
tmp = tmp*10 + uint64(bytes[i]-'0')
i++
}
*val = tmp
return i
}
func solve(n int) []int {
if n == 2 {
return nil
}
// else 始终可以 1, n, 2, n - 1, 3, n - 2, x
res := make([]int, n)
var a, b int
if n%2 == 0 {
res[0] = 2
res[1] = 1
a, b = n, 3
for i := 2; i < n; i += 2 {
res[i] = a
a--
if i+1 < n {
res[i+1] = b
b++
}
}
} else {
a, b = 1, n
for i := 0; i < n; i += 2 {
res[i] = a
a++
if i+1 < n {
res[i+1] = b
b--
}
}
}
return res
}Equal LIS CodeChef Solution Review:
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