304 North Cardinal St.
Dorchester Center, MA 02124

# Equal LIS CodeChef Solution

## Equal LIS CodeChef Solution in C++17

/*ॐ Arpit Blagan ॐ*/
#include<bits/stdc++.h>
using namespace std;
#define all(arr) arr.begin(),arr.end()
#define rep(i,s,e) for(int i=s;i<e;i++)
#define lli long long int
#define ll long long
const ll INF=1e18;
const int mod=1e9+7;
int main(){
ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);
int t;cin>>t;
while(t--){
int n;cin>>n;
if(n==2){cout<<"NO\n";}
else{	cout<<"YES\n";
int mid=n/2;
vector<int>ans;
for(int i=1;i<=mid;i++){ans.push_back(i);}
for(int i=n;i>mid;i--){ans.push_back(i);}
if(n%2==0){swap(ans[0],ans[1]);}
for(auto it:ans){cout<<it<<" ";}cout<<"\n";
}
}
return 0;
}

## Equal LIS CodeChef Solution in C++14

#include <bits/stdc++.h>

#pragma optimization_level 3
#pragma GCC optimize("Ofast,no-stack-protector,unroll-loops,fast-math,O3")
#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx")
#pragma GCC optimize("Ofast")//Comment optimisations for interactive problems (use endl)
#pragma GCC target("avx,avx2,fma")
#pragma GCC optimization ("unroll-loops")

using namespace std;

struct PairHash {inline std::size_t operator()(const std::pair<int, int> &v) const { return v.first * 31 + v.second; }};

// speed
#define Code ios_base::sync_with_stdio(false);
#define By ios::sync_with_stdio(0);
#define Sumfi cout.tie(NULL);

// alias
using ll = long long;
using ld = long double;
using ull = unsigned long long;

// constants
const ld PI = 3.14159265358979323846;  /* pi */
const ll INF = 1e18;
const ld EPS = 1e-9;
const ll MAX_N = 101010;
const ll mod = 998244353;

// typedef
typedef pair<ll, ll> pll;
typedef vector<pll> vpll;
typedef array<ll,3> all3;
typedef array<ll,5> all5;
typedef vector<all3> vall3;
typedef vector<all5> vall5;
typedef vector<ld> vld;
typedef vector<ll> vll;
typedef vector<vll> vvll;
typedef vector<int> vi;
typedef deque<ll> dqll;
typedef deque<pll> dqpll;
typedef pair<string, string> pss;
typedef vector<pss> vpss;
typedef vector<string> vs;
typedef vector<vs> vvs;
typedef unordered_set<ll> usll;
typedef unordered_set<pll, PairHash> uspll;
typedef unordered_map<ll, ll> umll;
typedef unordered_map<pll, ll, PairHash> umpll;

// macros
#define rep(i,m,n) for(ll i=m;i<n;i++)
#define rrep(i,m,n) for(ll i=n;i>=m;i--)
#define all(a) begin(a), end(a)
#define rall(a) rbegin(a), rend(a)
#define ZERO(a) memset(a,0,sizeof(a))
#define MINUS(a) memset(a,0xff,sizeof(a))
#define INF(a) memset(a,0x3f3f3f3f3f3f3f3fLL,sizeof(a))
#define ASCEND(a) iota(all(a),0)
#define sz(x) ll((x).size())
#define BIT(a,i) (a & (1ll<<i))
#define BITSHIFT(a,i,n) (((a<<i) & ((1ll<<n) - 1)) | (a>>(n-i)))
#define pyes cout<<"YES\n";
#define pno cout<<"NO\n";
#define endl "\n"
#define pneg1 cout<<"-1\n";
#define ppossible cout<<"Possible\n";
#define pimpossible cout<<"Impossible\n";
#define TC(x) cout<<"Case #"<<x<<": ";
#define X first
#define Y second

// utility functions
template <typename T>
void print(T &&t)  { cout << t << "\n"; }
template<typename T>
void printv(vector<T>v){ll n=v.size();rep(i,0,n){cout<<v[i];if(i+1!=n)cout<<' ';}cout<<endl;}
template<typename T>
void printvln(vector<T>v){ll n=v.size();rep(i,0,n)cout<<v[i]<<endl;}
void fileIO(string in = "input.txt", string out = "output.txt") {freopen(in.c_str(),"r",stdin); freopen(out.c_str(),"w",stdout);}
template<typename T>
template<typename T, typename U>
template<typename T, typename U>

struct Combination {
vll fac, inv;
ll n, MOD;

ll modpow(ll n, ll x, ll MOD = mod) { if(!x) return 1; ll res = modpow(n,x>>1,MOD); res = (res * res) % MOD; if(x&1) res = (res * n) % MOD; return res; }

Combination(ll _n, ll MOD = mod): n(_n + 1), MOD(MOD) {
inv = fac = vll(n,1);
rep(i,1,n) fac[i] = fac[i-1] * i % MOD;
inv[n - 1] = modpow(fac[n - 1], MOD - 2, MOD);
rrep(i,1,n - 2) inv[i] = inv[i + 1] * (i + 1) % MOD;
}

ll fact(ll n) {return fac[n];}
ll nCr(ll n, ll r) {
if(n < r or n < 0 or r < 0) return 0;
return fac[n] * inv[r] % MOD * inv[n-r] % MOD;
}
};

struct Matrix {
ll r,c;
vvll matrix;
Matrix(ll r, ll c, ll v = 0): r(r), c(c), matrix(vvll(r,vll(c,v))) {}

Matrix operator*(const Matrix& B) const {
Matrix res(r, B.c);
rep(i,0,r) rep(j,0,B.c) rep(k,0,B.r) {
res.matrix[i][j] = (res.matrix[i][j] + matrix[i][k] * B.matrix[k][j] % mod) % mod;
}
return res;
}

Matrix copy() {
Matrix copy(r,c);
copy.matrix = matrix;
return copy;
}

Matrix pow(ll n) {
assert(r == c);
Matrix res(r,r);
Matrix now = copy();
rep(i,0,r) res.matrix[i][i] = 1;
while(n) {
if(n & 1) res = res * now;
now = now * now;
n /= 2;
}
return res;
}
};

// geometry data structures
template <typename T>
struct Point {
T y,x;
Point(T y, T x) : y(y), x(x) {}
Point(pair<T,T> p) : y(p.first), x(p.second) {}
Point() {}
void input() {cin>>y>>x;}
friend ostream& operator<<(ostream& os, const Point<T>& p) { os<<p.y<<' '<<p.x<<'\n'; return os;}
Point<T> operator+(Point<T>& p) {return Point<T>(y + p.y, x + p.x);}
Point<T> operator-(Point<T>& p) {return Point<T>(y - p.y, x - p.x);}
Point<T> operator*(ll n) {return Point<T>(y*n,x*n); }
Point<T> operator/(ll n) {return Point<T>(y/n,x/n); }
bool operator<(const Point &other) const {if (x == other.x) return y < other.y;return x < other.x;}
Point<T> rotate(Point<T> center, ld angle) {
ld si = sin(angle * PI / 180.), co = cos(angle * PI / 180.);
ld y = this->y - center.y;
ld x = this->x - center.x;

return Point<T>(y * co - x * si + center.y, y * si + x * co + center.x);
}
ld distance(Point<T> other) {
T dy = abs(this->y - other.y);
T dx = abs(this->x - other.x);
return sqrt(dy * dy + dx * dx);
}

T norm() { return x * x + y * y; }
};

template<typename T>
struct Line {
Point<T> A, B;
Line(Point<T> A, Point<T> B) : A(A), B(B) {}
Line() {}

void input() {
A = Point<T>();
B = Point<T>();
A.input();
B.input();
}

T ccw(Point<T> &a, Point<T> &b, Point<T> &c) {
T res = a.x * b.y + b.x * c.y + c.x * a.y;
res -= (a.x * c.y + b.x * a.y + c.x * b.y);
return res;
}

bool isIntersect(Line<T> o) {
T p1p2 = ccw(A,B,o.A) * ccw(A,B,o.B);
T p3p4 = ccw(o.A,o.B,A) * ccw(o.A,o.B,B);
if (p1p2 == 0 && p3p4 == 0) {
pair<T,T> p1(A.y, A.x), p2(B.y,B.x), p3(o.A.y, o.A.x), p4(o.B.y, o.B.x);
if (p1 > p2) swap(p2, p1);
if (p3 > p4) swap(p3, p4);
return p3 <= p2 && p1 <= p4;
}
return p1p2 <= 0 && p3p4 <= 0;
}

pair<bool,Point<ld>> intersection(Line<T> o) {
if(!this->intersection(o)) return {false, {}};
ld det = 1. * (o.B.y-o.A.y)*(B.x-A.x) - 1.*(o.B.x-o.A.x)*(B.y-A.y);
ld t = ((o.B.x-o.A.x)*(A.y-o.A.y) - (o.B.y-o.A.y)*(A.x-o.A.x)) / det;
return {true, {A.y + 1. * t * (B.y - A.y), B.x + 1. * t * (B.x - A.x)}};
}

//@formula for : y = ax + b
//@return {a,b};
pair<ld, ld> formula() {
T y1 = A.y, y2 = B.y;
T x1 = A.x, x2 = B.x;
if(y1 == y2) return {1e9, 0};
if(x1 == x2) return {0, 1e9};
ld a = 1. * (y2 - y1) / (x2 - x1);
ld b = -x1 * a + y1;
return {a, b};
}
};

template<typename T>
struct Circle {
Point<T> center;
Circle() {}

void input() {
center = Point<T>();
center.input();
}

bool circumference(Point<T> p) {
return (center.x - p.x) * (center.x - p.x) + (center.y - p.y) * (center.y - p.y) == radius * radius;
}

bool intersect(Circle<T> c) {
T d = (center.x - c.center.x) * (center.x - c.center.x) + (center.y - c.center.y) * (center.y - c.center.y);
}

bool include(Circle<T> c) {
T d = (center.x - c.center.x) * (center.x - c.center.x) + (center.y - c.center.y) * (center.y - c.center.y);
}
};

ll __gcd(ll x, ll y) { return !y ? x : __gcd(y, x % y); }
all3 __exgcd(ll x, ll y) { if(!y) return {x,1,0}; auto [g,x1,y1] = __exgcd(y, x % y); return {g, y1, x1 - (x/y) * y1}; }
ll __lcm(ll x, ll y) { return x / __gcd(x,y) * y; }
ll modpow(ll n, ll x, ll MOD = mod) { n%=MOD; if(!x) return 1; ll res = modpow(n,x>>1,MOD); res = (res * res) % MOD; if(x&1) res = (res * n) % MOD; return res; }

vll solve(ll n) {
if(n == 1) return {1};
if(n == 2) return {};
if(n & 1) {
dqll res{n};
n -= 1;
while(n) {
res.push_back(n);
res.push_front(n-1);
n -= 2;
}
return vll(all(res));
}
vll res;
for(ll i = 3; i < n; i += 2) res.push_back(i);
res.push_back(1);
for(ll i = n; i >= 2; i -= 2) res.push_back(i);
return res;
}
int main() {
Code By Sumfi
cout.precision(12);
ll tc = 1;
cin>>tc;
rep(i,1,tc+1) {
ll n;
cin>>n;
auto res = solve(n);
if(sz(res)) {
pyes
printv(res);
} else pno
}
return 0;
}

## Equal LIS CodeChef Solution in PYTH 3

for _ in range(int(input())):
n=int(input())
if(n%2):
print("Yes")
for i in range(1,n//2+1):
print(i,end=" ")
for i in range(n,(n//2),-1):
print(i,end=" ")
print()
elif(n!=2):
print("Yes")
print(n//2,end=" ")
for i in range(1,n//2):
print(i,end=" ")
for i in range(n,n//2,-1):
print(i,end=" ")
print()
else:
print("No")

## Equal LIS CodeChef Solution in C

#include <stdio.h>

void solve()
{
int k,i,m,l;
scanf("%d",&k);
if(k==2)
printf("NO\n");
else if(k%2==0)
{
l=k;
m=1;
printf("YES\n%d ",(k/2)+1);
for(i=2;i<=k;i++)
{
if(i%2==0)
{
printf("%d ",m);
m++;
}
else
{
printf("%d ",l);
l--;
}
}
printf("\n");
}
else
{
m=1;
l=k;
printf("YES\n");
for(i=1;i<=k;i++)
{
if(i%2!=0)
{
printf("%d ",m);
m++;
}
else
{
printf("%d ",l);
l--;
}
}
printf("\n");

}

}

int main()
{
int t;
scanf("%d",&t);
while(t--)
{
solve();
}
return 0;
}

## Equal LIS CodeChef Solution in JAVA

/* package codechef; // don't place package name! */

import java.util.*;
import java.lang.*;
import java.io.*;

/* Name of the class has to be "Main" only if the class is public. */
class Codechef
{
public static void main (String[] args) throws java.lang.Exception
{
Scanner sc=new Scanner(System.in);
int t=sc.nextInt();
for(int tt=0;tt<t;tt++){
int n=sc.nextInt();

if(n==2){
System.out.println("NO");
}
else if(n%2==1){
System.out.println("YES");
for(int i=1;i<(n+1)/2;i++){
System.out.print(i+" ");
}
for(int i=n;i>=(n+1)/2;i--){
System.out.print(i+" ");
}
}
else if(n>2){
System.out.println("YES");
int[] a=new int[n];
for(int i=0;i<n/2;i++){
a[i]=i+1;
}
for(int i=n/2;i<n;i++){
a[i]=n-i+n/2;
}
a[0]=2;
a[1]=1;
for(int i:a){
System.out.print(i+" ");
}
System.out.println();
}
}
}
}

## Equal LIS CodeChef Solution in PYPY 3

def solve():
n= int(input())
if(n%2==0):
if(n==2):
print("NO")
else :
print("YES")
print(2, end =" ")
print(1, end =" ")
for i in range (2, n//2 +1, 1):
print(i*2, end =" ")
for i in range(n-1, 2, -2):
print(i, end =" ")
print()
else :
print("YES")
for i in range (1, (n+1)//2, 1):
print(2*i, end =" ")
for i in range (n, 0, -2):
print(i, end =" ")
print()

def main ():
t=int(input())
while(t>0):
t=t-1
solve()
# 	n,k = [int(x) for x in input().split()]
# 	arr = [int(x) for x in input().split()]
# 	Flipped( n,k ,arr)

if __name__ == "__main__": main ()

## Equal LIS CodeChef Solution in C#

using System;
using System.Collections.Generic;
using System.Globalization;
using System.Linq;
using System.Text;
using System.Text.RegularExpressions;

namespace Codeforces
{
public class Program
{
private static int _mod = (int)1e9 + 7;

static void Main(string[] args)
{
//Precompute();
for (int i = 0; i < t; i++)
Solve();
}

public static List<int> _nums { get; set; }

public static void Solve()
{
int n = GetInt();
List<int> ans = new List<int>();
if(n<=2)
{
Console.WriteLine("NO");
return;
}
else if(n%2 == 0)
{
ans.AddRange(Enumerable.Range(n / 2 + 1, n / 2).Reverse());
int a = ans[0];
int b = ans[1];
ans[0] = b;
ans[1] = a;
}
else
{
ans.AddRange(Enumerable.Range(1, (n + 1) / 2));
}

#if DEBUG
#endif
Console.WriteLine("YES\n" + string.Join(" ",ans));
}

public static int DoubleIt(int n)
{
int b = 0;
for(int i=15; i>=0; i--)
{
b *= 4;
if ((n & (1 << i)) != 0)
b += 3;
}
return b;
}

public static int GetInt() => int.Parse(Console.ReadLine());
public static long GetLong() => long.Parse(Console.ReadLine());

public static int[] GetIntArray() => Console.ReadLine().Trim().Split(' ').Select(int.Parse).ToArray();
public static long[] GetLongArray() => Console.ReadLine().Trim().Split(' ').Select(long.Parse).ToArray();
public static double[] GetDoublesArray() => Console.ReadLine().Trim().Split(' ').Select(d => Convert.ToDouble(d, CultureInfo.InvariantCulture)).ToArray();

public static long Gcd(long a, long b) => b == 0 ? a : Gcd(b, a % b);
public static long Gcd(long[] a) => a.Aggregate(a[0], (x, y) => Gcd(x, y));
public static long Lcm(long a, long b) => a * b / Gcd(a, b);
public static long Lcm(IEnumerable<int> a) => a.Aggregate(1L, (x, y) => Lcm(x, y));
public static void Swap(ref long a, ref long b)
{
long t = a;
a = b;
b = t;
}

public static void Swap(ref int a, ref int b)
{
int t = a;
a = b;
b = t;
}

public static void OutputSequence(IEnumerable<long> x) => Console.WriteLine(\$" >>  " + string.Join(", ", x));

public static string Rev(string s) => string.Concat(s.ToArray().Reverse());

public static Dictionary<char, long> Frequencies(char[] a)
{
var ans = new Dictionary<char, long>();
foreach (char k in a)
{
if (ans.ContainsKey(k))
ans[k]++;
else
ans[k] = 1;
}
return ans;
}
}
}

## Equal LIS CodeChef Solution in GO

package main

import (
"bufio"
"bytes"
"fmt"
"os"
)

func main() {

var buf bytes.Buffer
for tc > 0 {
tc--
res := solve(n)
if len(res) == 0 {
buf.WriteString("NO\n")
continue
}
buf.WriteString("YES\n")
for i := 0; i < n; i++ {
buf.WriteString(fmt.Sprintf("%d ", res[i]))
}
buf.WriteByte('\n')
}
fmt.Println(buf.String())
}

func readInt(bytes []byte, from int, val *int) int {
i := from
sign := 1
if bytes[i] == '-' {
sign = -1
i++
}
tmp := 0
for i < len(bytes) && bytes[i] >= '0' && bytes[i] <= '9' {
tmp = tmp*10 + int(bytes[i]-'0')
i++
}
*val = tmp * sign
return i
}

for i := 0; i < len(s); i++ {
if s[i] == '\n' {
return s[:i]
}
}
return s
}

return
}

a, b = res[0], res[1]
return
}

a, b, c = res[0], res[1], res[2]
return
}

res := make([]int, n)
x := 0
for i := 0; i < n; i++ {
for x < len(bs) && (bs[x] < '0' || bs[x] > '9') && bs[x] != '-' {
x++
}
}
return res
}

func readUint64(bytes []byte, from int, val *uint64) int {
i := from

var tmp uint64
for i < len(bytes) && bytes[i] >= '0' && bytes[i] <= '9' {
tmp = tmp*10 + uint64(bytes[i]-'0')
i++
}
*val = tmp

return i
}

func solve(n int) []int {
if n == 2 {
return nil
}
// else 始终可以  1, n, 2, n - 1, 3, n - 2, x
res := make([]int, n)
var a, b int
if n%2 == 0 {
res[0] = 2
res[1] = 1
a, b = n, 3
for i := 2; i < n; i += 2 {
res[i] = a
a--
if i+1 < n {
res[i+1] = b
b++
}
}
} else {
a, b = 1, n
for i := 0; i < n; i += 2 {
res[i] = a
a++
if i+1 < n {
res[i+1] = b
b--
}
}

}

return res
}
##### Equal LIS CodeChef Solution Review:

In our experience, we suggest you solve this Equal LIS CodeChef Solution and gain some new skills from Professionals completely free and we assure you will be worth it.

If you are stuck anywhere between any coding problem, just visit Queslers to get the Equal LIS CodeChef Solution.

Find on CodeChef

##### Conclusion:

I hope this Equal LIS CodeChef Solution would be useful for you to learn something new from this problem. If it helped you then don’t forget to bookmark our site for more Coding Solutions.

This Problem is intended for audiences of all experiences who are interested in learning about Programming Language in a business context; there are no prerequisites.

Keep Learning!