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## Problem – Expiring Bread CodeChef Solution

Eikooc loves bread. She has N loaves of bread, all of which expire after exactly M days. She can eat upto K loaves of bread in a day. Can she eat all the loaves of bread before they expire?

### Input Format

• The first line contains a single integer T – the number of test cases. Then the test cases follow.
• Each test case consists of a single line containing three integers NM and K – the number of loaves of bread Eikooc has, the number of days after which all the breads will expire and the number of loaves of bread Eikooc can eat in a day.

### Output Format

For each test case, output `Yes` if it will be possible for Eikooc to eat all the loaves of bread before they expire. Otherwise output `No`.

You may print each character of `Yes` and `No` in uppercase or lowercase (for example, `yes``yEs``YES` will be considered identical).

• 1≤T≤1000
• 1≤N,M,K≤100

### Sample 1:

``````Input: 3
100 100 1
9 2 5
19 6 3
Output: Yes
Yes
No``````

### Explanation:

Test case 1: Eikooc can eat one loaf of bread per day for 100 days. Thus none of the bread expires.

Test case 2: Eikooc can eat 5 loaves of the first day and 4 loaves on the second day. Thus none of the bread expires.

Test case 3: There is no way Eikooc can consume all the loaves of bread before it expires.

### Expiring Bread CodeChef Solution in Java

``````import java.util.*;
import java.lang.*;
import java.io.*;

class Codechef
{
public static void main (String[] args) throws java.lang.Exception
{
Scanner sc = new Scanner(System.in);

int t = sc.nextInt();

while(t-->0){
int a=sc.nextInt();
int b=sc.nextInt();
int c=sc.nextInt();
if(a<=b*c)
System.out.println("yes");
else
System.out.println("no");

}
}
}
``````

### Expiring Bread CodeChef Solution in C++14

``````#include <iostream>
using namespace std;

int main() {
int t;
cin>>t;
while(t--){
int n, m, k;
cin>>n>>m>>k;
if((m*k)>=n){
cout<<"Yes"<<endl;
}
else{
cout<<"No"<<endl;
}
}
return 0;
}
``````

### Expiring Bread CodeChef Solution in Pyth 3

``````t=int(input())
for i in range(t):
a,b,c=map(int,input().split())
if b*c>=a:
print("YES")
else:
print("NO")
``````
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