Physical Address
304 North Cardinal St.
Dorchester Center, MA 02124
Given an integer n
, return the number of trailing zeroes in n!
.
Note that n! = n * (n - 1) * (n - 2) * ... * 3 * 2 * 1
.
Example 1:
Input: n = 3
Output: 0
Explanation: 3! = 6, no trailing zero.
Example 2:
Input: n = 5
Output: 1
Explanation: 5! = 120, one trailing zero.
Example 3:
Input: n = 0
Output: 0
Constraints:
0 <= n <= 104
Follow up: Could you write a solution that works in logarithmic time complexity?
return n == 0 ? 0 : n / 5 + trailingZeroes(n / 5);
return n == 0 ? 0 : n / 5 + trailingZeroes(n / 5);
return 0 if n == 0 else n / 5 + self.trailingZeroes(n / 5)
In our experience, we suggest you solve this Factorial Trailing Zeroes LeetCode Solution and gain some new skills from Professionals completely free and we assure you will be worth it.
If you are stuck anywhere between any coding problem, just visit Queslers to get the Factorial Trailing Zeroes LeetCode Solution
I hope this Factorial Trailing Zeroes LeetCode Solution would be useful for you to learn something new from this problem. If it helped you then don’t forget to bookmark our site for more Coding Solutions.
This Problem is intended for audiences of all experiences who are interested in learning about Data Science in a business context; there are no prerequisites.
Keep Learning!
More Coding Solutions >>