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# Fibonacci Number LeetCode Solution – Queslers

## Problem – Fibonacci Number LeetCode Solution

The Fibonacci numbers, commonly denoted `F(n)` form a sequence, called the Fibonacci sequence, such that each number is the sum of the two preceding ones, starting from `0` and `1`. That is,

``````F(0) = 0, F(1) = 1
F(n) = F(n - 1) + F(n - 2), for n > 1.
``````

Given `n`, calculate `F(n)`.

Example 1:

``````Input: n = 2
Output: 1
Explanation: F(2) = F(1) + F(0) = 1 + 0 = 1.``````

Example 2:

``````Input: n = 3
Output: 2
Explanation: F(3) = F(2) + F(1) = 1 + 1 = 2.``````

Example 3:

``````Input: n = 4
Output: 3
Explanation: F(4) = F(3) + F(2) = 2 + 1 = 3.``````

Constraints:

• `0 <= n <= 30`

### Fibonacci Number LeetCode Solution in Java

``````class Solution
{
public int fib(int N)
{
if(N <= 1)
return N;

int a = 0, b = 1;

while(N-- > 1)
{
int sum = a + b;
a = b;
b = sum;
}
return b;
}
}
``````

### Fibonacci Number LeetCode Solution in Python

``````def fib(N):
if N == 0: return 0
if N == 1: return 1
return fib(N-1) + fib(N-2)
``````

### Fibonacci Number LeetCode Solution in C++

``````    int fib(int N) {
if(N == 0)  return 0;
if(N == 1)  return 1;
return fib(N-1) + fib(N-2);
}
``````
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