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In this challenge, the user enters a string and a substring. You have to print the number of times that the substring occurs in the given string. String traversal will take place from left to right, not from right to left.
NOTE: String letters are case-sensitive.
The first line of input contains the original string. The next line contains the substring.
1 <= len(string) <= 200
Each character in the string is an ascii character.
Output the integer number indicating the total number of occurrences of the substring in the original string.
There are a couple of new concepts:
In Python, the length of a string is found by the function len(s), where s is the string.
To traverse through the length of a string, use a for loop:
for i in range(0, len(s)): print (s[i])
A range function is used to loop over some length:
range (0, 5)
Here, the range loops over 0 to 4. 5 is excluded.
a,b=(raw_input() for i in range(2)) cnt=0 for i in range(len(a)-len(b)+1): if a[i:i+len(b)]==b: cnt+=1 print cnt
def count_substring(string, sub_string): count = 0 for i in range(0, len(string)-len(sub_string)+1): l = i for j in range(0, len(sub_string)): if string[l] == sub_string[j]: l +=1 if j == len(sub_string)-1: count = count + 1 else: continue else: break return count
# Enter your code here. Read input from STDIN. Print output to STDOUT s=raw_input() d=len(s) ss=raw_input() dd=len(ss) c=0 for i in range(d-dd+1): if s[i:i+dd] == ss: c+=1 print c
#def count_substrings(string, sub_string): string=str(input()) sub_string=str(input()) #print(string) #print(sub_string) count=0 for i in range(0,len(string)): str_i=string[i:i+len(sub_string)] #print(str_i) if str_i ==sub_string: count=count+1 print(count) #return
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This Problem is intended for audiences of all experiences who are interested in learning about Data Science in a business context; there are no prerequisites.
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