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# Find a string Hacker Rank Solution – Queslers

## Problem: Find a string Hacker Rank Solution

In this challenge, the user enters a string and a substring. You have to print the number of times that the substring occurs in the given string. String traversal will take place from left to right, not from right to left.

NOTE: String letters are case-sensitive.

#### Input Format

The first line of input contains the original string. The next line contains the substring.

#### Constraints

1 <= len(string) <= 200

Each character in the string is an ascii character.

#### Output Format

Output the integer number indicating the total number of occurrences of the substring in the original string.

Sample Input

```ABCDCDC
CDC```

Sample Output

`2`

#### Concept

There are a couple of new concepts:

In Python, the length of a string is found by the function len(s), where s is the string.

To traverse through the length of a string, use a for loop:

```for i in range(0, len(s)):
print (s[i])```

A range function is used to loop over some length:

`range (0, 5)`

Here, the range loops over 0 to 45 is excluded.

### Find a string Hacker Rank Solution in Python 2

```a,b=(raw_input() for i in range(2))
cnt=0
for i in range(len(a)-len(b)+1):
if a[i:i+len(b)]==b:
cnt+=1
print cnt```

### Find a string Hacker Rank Solution in Python 3

```def count_substring(string, sub_string):
count = 0
for i in range(0, len(string)-len(sub_string)+1):
l = i
for j in range(0, len(sub_string)):
if string[l] == sub_string[j]:
l +=1
if j == len(sub_string)-1:
count = count + 1
else:
continue
else:
break

return count```

### Find a string Hacker Rank Solution in pypy

```# Enter your code here. Read input from STDIN. Print output to STDOUT
s=raw_input()
d=len(s)
ss=raw_input()
dd=len(ss)
c=0

for i in range(d-dd+1):

if s[i:i+dd] == ss:
c+=1
print c```

### Find a string Hacker Rank Solution in pypy3

```#def count_substrings(string, sub_string):
string=str(input())
sub_string=str(input())
#print(string)
#print(sub_string)
count=0
for i in range(0,len(string)):
str_i=string[i:i+len(sub_string)]
#print(str_i)
if str_i ==sub_string:
count=count+1
print(count)
#return ```
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This Problem is intended for audiences of all experiences who are interested in learning about Data Science in a business context; there are no prerequisites.

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