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# Find All Numbers Disappeared in an Array LeetCode Solution

## Problem – Find All Numbers Disappeared in an Array LeetCode Solution

Given an array `nums` of `n` integers where `nums[i]` is in the range `[1, n]`, return an array of all the integers in the range `[1, n]` that do not appear in `nums`.

Example 1:

``````Input: nums = [4,3,2,7,8,2,3,1]
Output: [5,6]
``````

Example 2:

``````Input: nums = [1,1]
Output: [2]``````

Constraints:

• `n == nums.length`
• `1 <= n <= 105`
• `1 <= nums[i] <= n`

### Find All Numbers Disappeared in an Array LeetCode Solution in Python

``````class Solution(object):
def findDisappearedNumbers(self, nums):
"""
:type nums: List[int]
:rtype: List[int]
"""
# For each number i in nums,
# we mark the number that i points as negative.
# Then we filter the list, get all the indexes
# who points to a positive number
for i in xrange(len(nums)):
index = abs(nums[i]) - 1
nums[index] = - abs(nums[index])

return [i + 1 for i in range(len(nums)) if nums[i] > 0]
``````

### Find All Numbers Disappeared in an Array LeetCode Solution in C++

``````class Solution {
public:
vector<int> findDisappearedNumbers(vector<int>& nums) {
int len = nums.size();
for(int i=0; i<len; i++) {
int m = abs(nums[i])-1; // index start from 0
nums[m] = nums[m]>0 ? -nums[m] : nums[m];
}
vector<int> res;
for(int i = 0; i<len; i++) {
if(nums[i] > 0) res.push_back(i+1);
}
return res;
}
};
``````

### Find All Numbers Disappeared in an Array LeetCode Solution in Java

``````public class Solution {
public List<Integer> findDisappearedNumbers(int[] nums) {
for (int i = 0; i < nums.length; i++) {
while (nums[i] != i + 1 && nums[i] != nums[nums[i] - 1]) {
int tmp = nums[i];
nums[i] = nums[tmp - 1];
nums[tmp - 1] = tmp;
}
}
List<Integer> res = new ArrayList<Integer>();
for (int i = 0; i < nums.length; i++) {
if (nums[i] != i + 1) {
}
}
return res;
}
}
``````
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