First Letter to Appear Twice LeetCode Solution

Problem – First Letter to Appear Twice LeetCode Solution

Given a string s consisting of lowercase English letters, return the first letter to appear twice.

Note:

• A letter a appears twice before another letter b if the second occurrence of a is before the second occurrence of b.
• s will contain at least one letter that appears twice.

Example 1:

Input: s = "abccbaacz"
Output: "c"
Explanation:
The letter 'a' appears on the indexes 0, 5 and 6.
The letter 'b' appears on the indexes 1 and 4.
The letter 'c' appears on the indexes 2, 3 and 7.
The letter 'z' appears on the index 8.
The letter 'c' is the first letter to appear twice, because out of all the letters the index of its second occurrence is the smallest.

Example 2:

Input: s = "abcdd"
Output: "d"
Explanation:
The only letter that appears twice is 'd' so we return 'd'.

Constraints:

• 2 <= s.length <= 100
• s consists of lowercase English letters.
• s has at least one repeated letter.

First Letter to Appear Twice LeetCode Solution in C++

char repeatedCharacter(string s) {
    int cnt[26]{};
    for(char ch:s) if(++cnt[ch-'a']==2) return ch;
    return 0;
}

First Letter to Appear Twice LeetCode Solution in Java

public char repeatedCharacter(String s) {
    int cnt[]= new int[26];
    for(char ch:s.toCharArray()) if(++cnt[ch-'a']==2) return ch;
    return 'a';
}

First Letter to Appear Twice LeetCode Solution in Python

class Solution:
    def repeatedCharacter(self, s: str) -> str:
        occurences = defaultdict(int)
        for char in s:
            occurences[char] += 1
            if occurences[char] == 2:
                return char

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