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What is the maximum number of squares of size 2×2 that can be fit in a right angled isosceles triangle of base B.
One side of the square must be parallel to the base of the isosceles triangle.
Base is the shortest side of the triangle
First line contains T, the number of test cases.
Each of the following T lines contains 1 integer B.
Output exactly T lines, each line containing the required answer.
1 ≤ T ≤ 103
1 ≤ B ≤ 104
Input:
11
1
2
3
4
5
6
7
8
9
10
11
Output:
0
0
0
1
1
3
3
6
6
10
10
#include<bits/stdc++.h>
using namespace std;
int numberOfSquares(int base)
{
base = (base - 2);
base = floor(base / 2);
return base * (base + 1)/2;
}
int main()
{
int t;
cin>>t;
while(t--){
int base;
cin>>base;
cout << numberOfSquares(base)<<endl;
}
return 0;
}
# cook your dish here
for _ in range(int(input())):
n = int(input())//2
print(n*(n-1)//2)
/* package codechef; // don't place package name! */
import java.util.*;
import java.lang.*;
import java.io.*;
/* Name of the class has to be "Main" only if the class is public. */
class Codechef
{
public static void main (String[] args) throws java.lang.Exception
{
// your code goes here
Scanner sc=new Scanner(System.in);
int t=sc.nextInt();
while(t-->0){
int B=sc.nextInt();
if(B<3){
System.out.println("0");
}else{
System.out.println(((((B/2)*(B/2))-(B/2))/2));
}
}
}
}
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