**Physical Address**

304 North Cardinal St.

Dorchester Center, MA 02124

Given an integer `n`

, return *a string array *`answer`

* ( 1-indexed) where*:

`answer[i] == "FizzBuzz"`

if`i`

is divisible by`3`

and`5`

.`answer[i] == "Fizz"`

if`i`

is divisible by`3`

.`answer[i] == "Buzz"`

if`i`

is divisible by`5`

.`answer[i] == i`

(as a string) if none of the above conditions are true.

**Example 1:**

```
Input: n = 3
Output: ["1","2","Fizz"]
```

**Example 2:**

```
Input: n = 5
Output: ["1","2","Fizz","4","Buzz"]
```

**Example 3:**

```
Input: n = 15
Output: ["1","2","Fizz","4","Buzz","Fizz","7","8","Fizz","Buzz","11","Fizz","13","14","FizzBuzz"]
```

**Constraints:**

`1 <= n <= 10`

^{4}

```
public class Solution {
public List<String> fizzBuzz(int n) {
List<String> ret = new ArrayList<String>(n);
for(int i=1,fizz=0,buzz=0;i<=n ;i++){
fizz++;
buzz++;
if(fizz==3 && buzz==5){
ret.add("FizzBuzz");
fizz=0;
buzz=0;
}else if(fizz==3){
ret.add("Fizz");
fizz=0;
}else if(buzz==5){
ret.add("Buzz");
buzz=0;
}else{
ret.add(String.valueOf(i));
}
}
return ret;
}
}
```

```
class Solution {
public:
vector<string> fizzBuzz(int n) {
vector<string> res(n);
for(int i = 1;i <= n; i++) {
res[i - 1] = to_string(i);
}
for(int i = 2;i < n; i += 3) {
res[i] = "Fizz";
}
for(int i = 4;i < n; i += 5) {
res[i] = "Buzz";
}
for(int i = 14;i < n; i += 15) {
res[i] = "FizzBuzz";
}
return res;
}
};
```

```
def fizzBuzz(self, n):
return['FizzBuzz'[i%-3&-4:i%-5&8^12]or`i`for i in range(1,n+1)]
```

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