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Flipping Failure CodeChef Solution

Flipping Failure CodeChef Solution in C++17

``````#include <iostream>
#include <unordered_set>
#include <vector>
#include <queue>
#include <algorithm>
#include <map>
#include <climits>
#include <iomanip>
#include <set>
#include <math.h>
#include <unordered_map>
#define int long long
#define printa(a) for (auto x : a) cout << x << " "; cout << endl;
#define printb(a) for (auto x : a) cout << x.first << " " << x.second << endl;
#define endl "\n"
using namespace std;

void solve(){
string s; cin >> s;
int n = (int)s.size();
int ones = 0;
for(int i = 0; i < n; i++){
if(s[i] == '1'){
ones++;
}
}
int count = 0;
int left = 0;
for(left = 0; left < ones; left++){
if(s[left] == '1') count++;
}
left--;
int mx = count;
int right = n - 1;
while(left >= 0){
if(s[left] == '1') count--;
left--;
if(s[right] == '1') count++;
right--;
mx = max(mx, count);
}
cout << ones - mx << endl;
}

int32_t main(){
cin.tie(0);
ios_base::sync_with_stdio(0);
int t = 1;
cin >> t;
while(t--) solve();
return 0;
}``````

Flipping Failure CodeChef Solution in C++14

``````#include <bits/stdc++.h>
using namespace std;
#define mod 1000000007
#define inf 1e18 + 8
typedef long long ll;
int d4[5] = {-1, 0, 1, 0, -1};
int d8[9] = {-1, 0, 1, 1, 0, -1, 1, -1, -1};

template<class t>
void huehuehue(ll x) { cout << "hue" << x << "\n"; }

int main()
{
ios_base::sync_with_stdio(false);
cin.tie(NULL);
int t = 1;
cin >> t;
while (t--) {

string s;
cin >> s;
int zeroes = 0, n = s.length();
for(int i = 0; i<n; ++i) {
if(s[i] == '0') {
zeroes++;
}
}
int len = 0;
for(int i = 0; i<zeroes; ++i) {
if(s[i] == '0') {
len++;
}
}
int maxLen = len;
// bool flag = true;
for(int i = zeroes; i<n; ++i) {
if(s[i] == '0') {
len++;
}
if(s[i-zeroes] == '0') {
len--;
}
if(len > maxLen) {
// flag = false;
maxLen = len;
}
}
cout << zeroes-maxLen;

cout << "\n";
}
return 0;
}``````

Flipping Failure CodeChef Solution in PYTH 3

``````T=int(input())
for _ in range(T):
s=input()
cnt = 0
ncnt = 0
for i  in range(len(s)):
cnt += (s[i] == '0')
if not cnt :
print("0")
continue
for i in range(cnt):
ncnt += (s[i] == '0')
ans = cnt - ncnt
for i in range(cnt,len(s)):
ncnt -= (s[i - cnt] == '0')
ncnt += (s[i] == '0')
ans = min(ans, cnt - ncnt)

print(ans)

``````

Flipping Failure CodeChef Solution in JAVA

``````/* package codechef; // don't place package name! */

import java.util.*;
import java.lang.*;
import java.io.*;

/* Name of the class has to be "Main" only if the class is public. */
class Codechef
{
Input1 aa;
public void calc() throws Exception {
String s=ns();
int len=s.length();

int ar[]=new int[len+1];

int i;
int count=0;
for(i=1;i<=len;i++){
if(s.charAt(i-1)=='1')
{
ar[i]=1+ar[i-1];
}
else {
ar[i]=ar[i-1];
count+=1;
}
}
int min1=ar[count];

if(len==1 || count==0){
System.out.println(0);
return;
}
for(i=1;i<=len;i++){
if(i>=count && s.charAt(i-1)=='0'){
int y=ar[i]-ar[i-count];
min1=Math.min(min1,y);
}
}
System.out.println(min1);
}
public void run() throws Exception{
aa=new Input1();
int t=ni();

while(t-->0){
calc();
}
}
public static void main (String[] args) throws java.lang.Exception
{
try{
new Codechef().run();
}
catch(Exception ee){

}
}
public int ni() throws Exception
{
return Integer.parseInt(aa.next());
}
public String ns() throws Exception{
return aa.next();
}
class Input1{
StringTokenizer str;
public Input1(){
}
public String next() throws Exception
{
while(str==null || !str.hasMoreTokens())
{
}
return str.nextToken();
}
}
}``````

Flipping Failure CodeChef Solution in PYPY 3

``````from collections import Counter, defaultdict

def solve() -> None:
s = str(input())
n = len(s)
k = s.count("0")
if k == n or k == 0:
print(0)
return
ans = cnt1 = s[:k].count("1")
for i, o in zip(s[k:], s):
cnt1 += (i == '1') - (o == '1')
ans = min(ans, cnt1)

print(ans)

t = int(input())
for _ in range(t):
solve()``````

Flipping Failure CodeChef Solution in GO

``````package main

import (
"bufio"
"bytes"
"fmt"
"os"
)

func main() {

var buf bytes.Buffer
for tc > 0 {
tc--
res := solve(s)
buf.WriteString(fmt.Sprintf("%d\n", res))
}
fmt.Print(buf.String())
}

func readUint64(bytes []byte, from int, val *uint64) int {
i := from

var tmp uint64
for i < len(bytes) && bytes[i] >= '0' && bytes[i] <= '9' {
tmp = tmp*10 + uint64(bytes[i]-'0')
i++
}
*val = tmp

return i
}

func readInt(bytes []byte, from int, val *int) int {
i := from
sign := 1
if bytes[i] == '-' {
sign = -1
i++
}
tmp := 0
for i < len(bytes) && bytes[i] >= '0' && bytes[i] <= '9' {
tmp = tmp*10 + int(bytes[i]-'0')
i++
}
*val = tmp * sign
return i
}

for i := 0; i < len(s); i++ {
if s[i] == '\n' || s[i] == '\r' {
return s[:i]
}
}
return s
}

return
}

a, b = res[0], res[1]
return
}

a, b, c = res[0], res[1], res[2]
return
}

res := make([]int, n)
x := 0
for i := 0; i < n; i++ {
for x < len(bs) && (bs[x] < '0' || bs[x] > '9') && bs[x] != '-' {
x++
}
}
return res
}

func solve(s string) int {
// lexicographically smallest string of s is 0000111

n := len(s)

// if we use type 2 once,
// we have to get string like 11100000111
pref := make([]int, n+1)
for i := 0; i < n; i++ {
pref[i+1] = int(s[i]-'0') + pref[i]
}

z := n - pref[n]

get := func(i int, j int) int {
if j < i {
return 0
}
return pref[j] - pref[i-1]
}
best := pref[z]
for i := z + 1; i <= n; i++ {
best = min(best, get(i-z+1, i))
}

return best
}

func min(a, b int) int {
if a <= b {
return a
}
return b
}``````
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