Full Speed Python Educative Quiz Answers

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Python is one of the most popular coding languages today; it’s categorized as a vital benchmark of computer science knowledge in industry interviews. This highly interactive course is an accelerated introduction to Python. It is intended for users who are already familiar with the fundamentals of programming and aims to teach the Python programming language using a practical approach. It not only covers the basic Python syntax but also teaches methods specific to Python3. With most companies already switching from Python2 to Python3, this version of Python is the future.

Before moving on to more complex and powerful tools, we’ll examine the fundamentals of the language. You can also experiment with the code provided and, therefore, gain a higher understanding of how things work. This course is perfect for anyone who works as a Python developer and wants to recognize its full potential. Happy learning!

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Challenge 1: Check Parity of a Number

Answer:

def checkParity(n):
  result = (n % 2) ## Update result according to the parity
  return result

Challenge 2: Find Values Within a Range

Answer:

def inRange(x, y):
  return (x < 1/3 < y)

Challenge 3: String Transformation

Answer:

def getStr(s):
  s=s[:1] + s[0] + s[1:]# Transform the string 
  s=s[:1] + s[0] + s[1:]
  s=s[:3] + s[3] + s[3:]
  s=s[:3] + s[3] + s[3:]
  s=s[:6] + s[6] + s[6:]
  s=s[:6] + s[6] + s[6:]
  # Update the length of string
  strlen = len(s)
  return [s, strlen]

Challenge 4: Find Index of a Specific Value in a String

Answer:

def findOccurence(s):
  a = s.find("b") # find first occurrence of "b" in the string 
  b = s.find("ccc") # find first occurence  of "ccc" in the string
  return [a, b]

Challenge 5: Lowercase to Uppercase

Answer:

def changeCase(s):
  a=s.upper()    ### convert string to "AAA BBB CCC"
  b=s.lower()    ### convert string to "aaa bbb ccc"
  return [a, b]

Quiz 1: Basic Data Types

Q1. What is the output of the following code

print("Hello World" + "Hello World" + "Hello World" * 2)

• Hello WorldHello WorldHello WorldHello World
• Hello WorldHello WorldHello World
• Hello WorldHello WorldHello WorldHello WorldHello World
• Hello WorldHello WorldHello World

Q2. How can you calculate the length of a string str in python?

• str.length()
• len.str()
• len(str)
• str.len()

Challenge 6: Sublist of a List

Answer:

def getSubList():
  l = [1, 4, 9, 10, 23]
  l1 = l[0:3]
  l2 = l[3:]
  return [l1, l2]

Challenge 7: Appending Value to the End of a List

Answer:

def AppendtoList():
  l = [1, 4, 9, 10, 23] 
  l.append(90)
  return l

Challenge 8: Averaging Values in a List

Answer:

def getAverage():
  l1 = [1, 4, 9, 10, 23]
  avg = sum(l1) / len(l1)  
  return avg

Challenge 9: Remove Sublist From List

Answer:

def removeList():
  l1 = [1, 4, 9, 10, 23]
  l2 = [4, 9]
  l1.remove(l2[0])
  l1.remove(l2[1])
  return l1

l1 = removeList()
print(l1)

Challenge 10: List of Squares

Answer:

def getSquare():
  l1 = [x*x for x in range(1, 11)]
  return l1

Challenge 11: List of Cubes

Answer:

def getCube():
  l1 = [x*x*x for x in range(1, 21)]
  return l1

Challenge 12: Lists of Even and Odd Numbers

Answer:

def ListofEvenOdds():
  l1 = []
  l2 = []  
  l1 = [x for x in range(0,21) if (x%2==0)]
  l2 = [x for x in range(0,21) if (x%2!=0)]
  return[l1, l2]

print(ListofEvenOdds())

Challenge 13: Sum of Squares of Even Numbers

Answer:

def evenSquareSum():
  even = [ x * x for x in range(0,21) if x % 2 == 0]
  return sum(even)

Challenge 14: Even Squares Not Divisible By Three

Answer:

def getSquare():
  l1 = [x * x for x in range(0, 21, 2) if x % 3 != 0]
  return l1

Quiz 2: Lists

Q1. What should be the output of the following code?

print([5,6,7] + [8,9,10])

• [13,15,17]
• [5,6,7,8,9,10]

Q2. Given the list. How can you add an item “baseball” in the list?

list = [“basketball”, “cricket”, “badminton”]

• list.append(“baseball”)
• list.insert(“baseball”)

Q3. What is the output of the following code?

S = [x**2 for x in range(10)]
print(S)

• [0, 1, 4, 9, 16, 25, 36, 49, 64, 81]
• [0, 2, 4, 8, 16, 32, 64, 128, 256, 512]

Q4. What is the output of the following code?

list = [n**2 for n in range(10) if n % 2 == 0]
print(list)

• [0, 4, 8, 16, 32]
• [0, 4, 16, 36, 64]

Challenge 15: Greatest Common Divisor

Answer:

import math 
def findGCD(a, b): ## Alter the declaration to get the function to take two input arguments
  return math.gcd(a, b)

Challenge 16: Calculate Sine, Cosine, and Tangent of User Input

Answer:

import math
def calculateSinCosTan(x):
  sine = math.sin(x)
  cos = math.cos(x)
  tan = math.tan(x)
  return [sine, cos, tan]

Challenge 17: Compute & Return Maximum

Answer:

def findMaximum(x,y):
  max2 = max(x, y) #create a variable max2 
  return max2 #returns the maximum of two numbers x and y

Challenge 18: Check If a Number Is Divisible by Another

Answer:

def isDivisble(x, y):
  if  x % y == 0:
    return True
  else :
    return False

Challenge 19: Compute nth Fibonacci Number

Answer:

def fibonacci(n):
  if n <= 1:
       return n
  else:
       return(fibonacci(n-1) + fibonacci(n-2))

Challenge 20: Compute Sum of First ‘n’ Natural Numbers

Answer:

def sum_N_Numbers (n):
  if n <= 1:
    return n
  else:
    return n + sum_N_Numbers (n-1)

Quiz 3: Modules and Functions

Q1. What is the output of the following function?

def function(fruit = "Orange"):
  print("I like " + fruit)

function("Banana")
function("Peach")
function()
function("Mango") 

• Option 1

I like Banana
I like Peach
I like Orange
I like Mango

• Option 2

I like Banana
I like Peach
I like Peach
I like Mango

• Option 3

I like Banana
I like Peach
I like Mango

Q2. What is the output of the following function?

def function(x):
  return 5 +x

print(function(2))
print(function(4))
print(function(6)) 

• Option 1

7
9
11

• Option 2

5
5
5

Q3. What is the output of the following code?

def recursion(k):
  if(k>0):
    result = k+recursion(k-1)
  else:
    result = 0
  return result

print(recursion(2))

• 1
• 3

Challenge 21: Sum Elements of a List

Answer:

def sumList(l):
    sum = 0
    for x in l:
        sum += x
    return sum

Challenge 22: Find Maximum in a List (Challenge 1)

Answer:

def findMaximum(list):
    maximum = list[0]
    for number in list:
      if number > maximum:
          maximum = number
    return maximum

Challenge 23: Find Maximum in a List (Challenge 2)

Answer:

def findMaximumValueIndex(list):
    maximum = list[0]
    index = 0
    for i, value in enumerate(list):
        if value > maximum:
          maximum = value 
          index = i
    return [index, maximum]

Challenge 24: Reverse a List

Answer:

def reverse(list):
    length = len(list)
    s = length

    new_list = [None]*length

    for item in list:
        s = s - 1
        new_list[s] = item
    return new_list

Challenge 25: Check If List Is Sorted

Answer:

def isSorted(list):
  flag = 0
  i = 1
  while i < len(list): 
      if(list[i] < list[i - 1]): # compare with the previous element
          flag = 1
      i += 1
      
  if (not flag) : 
      return True 
  else : 
      return False 

Challenge 26: Find Duplicates in a List

Answer:

def hasDuplicates(list):
  flag = 0
  for i in range (len(list)):
     for j in range (i + 1, len(list)):
         if (list[i] == list[j]):
             flag = 1
  if (flag == 1): 
     return True
  else:
     return False

Challenge 27: Print Even/Odd Numbers in Descending Order

Answer:

def printEvenOdd(n):
  while(n>0):
    if (n%2==0):
      print ("Even number:",n)
    else:
      print ("Odd number:",n)
    n=n-1 

Quiz 4: Iteration & Loops

Q1. What is the output of the following code?

for a in "Python":
  print (a)

• Python
• P
  y
  t
  h
  o
  n

Q2. What is the output of the following code?

Languages = ["Python", "Java", "R"]
for x in Languages:
  if x == "Java":
    break
  print(x) 

• Python Java R
• Python Java
• Python

Q3. What is the output of the following code?

i = 1
while i < 7:
  print(i)
  if (i == 3):
    break
  i += 1

• Option 1

1
2
3

• Option 2

1
2
3
4
5
6

Q4. What is the output of the following code?

i = 1
while i <= 7:
  i += 1
  if (i == 3):
    continue
  print(i)

• Option 1

1
2
3

• Option 2

2
4
5
6
7
8

Challenge 28: Determine Size of a Dictionary

Answer:

def lengthDictionary(Students):
  return len(Students)

Challenge 29: Average of Values of Keys in a Dictionary

Answer:

def calculateAvg(ages):
  length = len(ages)
  return(sum(ages.values()) / length)

Challenge 30: Return Key With Maximum Value

Answer:

def oldestStudent(ages):
  value = list(ages.values())
  key = list(ages.keys())
  return key[value.index (max(value))]

Challenge 31: Increment Dictionary Values

Answer:

def updateAges(ages, n):
  new_ages = {}
  for word in ages:
    new_ages[word] = ages[word] + n
  return new_ages

Challenge 32: Size of a Dictionary Within a Dictionary

Answer:

def totalStudents(students):
  return(len(students.keys()))

Challenge 33: Average Values Within Multiple Dictionaries

Answer:

def calculateAverageAge(students):
  result = {}
  add_age = 0
  for thing in students.values():
      age = thing['age']
      add_age = add_age + age
    
  return(add_age / len(students.keys()))    
   

Challenge 34: Keys Matching in Multiple Dictionaries

Answer:

def find_students(address, students):
  names = []
  for key, subdict in students.items():
       for sublist in subdict.values():
          if (sublist == address):
             names.append(key)
              
  return sorted(names)

Quiz 5: Dictionaries

Q1. What is the output of the following code?

Dict = { 'Dict1': {'Fruitname': 'Mango', 'season': 'Summer'}, 
         'Dict2': {'Fruitname': 'Orange', 'season': 'Winter'}}
print(Dict['Dict1']['Fruitname'])
print(Dict['Dict2']['season'])  

• Mango
  Winter
• Orange
  Winter

Q2. What is the output of the following code?

Dict1 = {
  "FruitName": "Mango",
  "season": "Spring",
}
Dict1["season"] = "Summer"
print(sorted(Dict1.values()))

• [‘Mango’, ‘Summer’]
• [‘Mango’, ‘Spring’]

Q3. What is the output of the following code?

Dict1 = {
  "FruitName": "Mango",
  "season": "Spring",
}
Dict1.pop("season")
print(Dict1.values())

• dict_values([‘Mango’])
• dict_values([‘Spring’, ‘Mango’])

Q4. What is the output of the following code?

Dict1 = {
  "FruitName": "Mango",
  "season": "Spring",
}
Dict1.clear()
print(Dict1)

• {}
• [‘Mango’,‘Spring’]

Challenge 35: Implement a Rectangle Class

Answer:

class Rectangle:
  def __init__(self, x1, y1, x2, y2): # class constructor
    if x1 < x2 and y1 > y2:
      self.x1 = x1 # class variable
      self.y1 = y1 # class variable
      self.x2 = x2 # class variable
      self.y2 = y2 # class variable
    else:
      print("Incorrect coordinates of the rectangle!")

Challenge 36: Implement Getter Methods

Answer:

class Rectangle:
  def __init__(self, x1, y1, x2, y2): # class constructor
    if x1 < x2 and y1 > y2:
      self.x1 = x1 # class variable
      self.y1 = y1 # class variable
      self.x2 = x2 # class variable
      self.y2 = y2 # class variable
    else:
      print("Incorrect coordinates of the rectangle!")
        
  def width(self):
    return self.x2 - self.x1
      
  def height(self):
    return self.y1 - self.y2

Challenge 37: Implement Area and Perimeter Member Methods

Answer:

class Rectangle:
  def __init__(self, x1, y1, x2, y2): # class constructor
    if x1<x2 and y1>y2:
      self.x1 = x1 # class variable
      self.y1 = y1 # class variable
      self.x2 = x2 # class variable
      self.y2 = y2 # class variable
    else:
      print("Incorrect coordinates of the rectangle!")
        
  def width(self):
    return self.x2-self.x1
      
  def height(self):
    return self.y1-self.y2
  
  def area(self):
    return self.width()*self.height()
  
  def perimeter(self):
    return 2*self.width()+2*self.height()

Challenge 38: Implement a Print Method

Answer:

class Rectangle:
  def __init__(self, x1, y1, x2, y2): # class constructor
    self.x1 = x1 # class variable
    self.y1 = y1 # class variable
    self.x2 = x2 # class variable
    self.y2 = y2 # class variable        
  def __str__(self):
    return(str(self.x1)+', '+str(self.y1)+', '+str(self.x2)+', '+str(self.y2))
  #write your code here

Challenge 39: Inheritance

Answer:

class Rectangle:
  def __init__(self, x1, y1, x2, y2): # class constructor
    self.x1 = x1 # class variable
    self.y1 = y1 # class variable
    self.x2 = x2 # class variable
    self.y2 = y2 # class variable
        
  def width(self):
    return self.x2 - self.x1
      
  def height(self):
    return self.y2 - self.y1
  
  def area(self):
    return self.width() * self.height()
  
class Square(Rectangle):
  def __init__(self, x1, y1, length):
    x2 = x1 + length
    y2 = y1 + length
    super().__init__(x1, y1, x2, y2)

Quiz 6: Classes

Q1. In Python __init__ is

• the method associated with extending a list with another list
• the name of the constructor method for a class

Q2. With the following code, which of the options is true?

class Person:
  def __init__(self, fname, lname):
    self.firstname = fname
    self.lastname = lname

  def printname(self):
    print(self.firstname, self.lastname)

class Student(Person):
  def __init__(self, fname, lname, year):
    super().__init__(fname, lname)
    self.batch= year

x = Student("Alex", "Vice", 2019)
x = Student("Anna", "Bate", 2018)
print(x.batch)

• 2019
• 2018

Challenge 40: Return Even Numbers From 1 to n

Answer:

class MyRange:
  def __init__(self, n):
    self.n = n

  def __iter__(self):
    return self

  def next(self):
    evenArray = [] # next method returns this list
    for i in range(1, self.n+1):
      if i % 2 is 0: # checks if number is even
        value = i
        evenArray.append(i) # adds the even number to the list
      else: # number was odd
        i+=1
    return evenArray
    
myrange = MyRange(8)
print (myrange.next())

Challenge 41: Return Numbers From n Down to 0

Answer:

class MyRange:
  def __init__(self, n):
    self.n = n

  def __iter__(self):
    return self

  def next(self):
    myArray = []
    for i in range(self.n, -1, -1): # from n to 0
      myArray.append(i) # adds the even number to the list
    return myArray

Challenge 42: Return Sequence of Fibonacci Numbers

Answer:

class MyRange:
  def __init__(self, n):
    self.n = n

  def __iter__(self):
    return self

  def next(self):
    myArray = []
    for i in range(self.n): # from n to 0
      if i == 0 or i == 1:
        myArray.append(i) # adds the even number to the list
      else:
        myArray.append(myArray[i-2]+myArray[i-1])
    return myArray
  
myrange = MyRange(8)
print(myrange.next())

Challenge 43: Yield Odd Numbers From 1 to n

Answer:

def odd(n):
  for value in range(n + 1):
    if value % 2 is not 0:
      yield value

Challenge 44: Yield Numbers From n Down to 0

Answer:

def reverse(n):
  for value in range(n, -1, -1):
    yield value

Challenge 45: Yield Fibonacci Sequence From 1st to Nth Number

Answer:

def fibonacci(n):
  myArray = []
  for i in range(n):
    if i is 0 or i is 1:
      myArray.append(i)
      yield i
    else:
      x = myArray[i-2] + myArray[i-1]
      myArray.append(x)
      yield x

Quiz 7: Asynchronous Programming

Q1. Which of the following statements allow you to execute an asynchronous function myPrint(x) once?

• Option 1

import asyncio
async def myPrint(x):
  print(x)
  await asyncio.sleep(1) 
  return

loop = asyncio.get_event_loop()
results = loop.run_until_complete(myPrint(1))
loop.close()

• Option 2

import asyncio
async def myPrint(x):
  print(x)
  await asyncio.sleep(1) 
  return

loop = asyncio.get_event_loop()
results = loop.run_until_complete(asyncio.gather(myPrint(1))
                                                 myPrint(2))
loop.close()

Q2. Which of the following statements allow you to execute an asynchronous function myPrint(x) multiple times?

• Option 1

import asyncio
async def myPrint(x):
  print(x)
  await asyncio.sleep(1) 
  return

loop = asyncio.get_event_loop()
results = loop.run_until_complete(myPrint(1))
loop.close()

• Option 2

import asyncio
async def myPrint(x):
  print(x)
  await asyncio.sleep(1) 
  return

loop = asyncio.get_event_loop()
results = loop.run_until_complete(asyncio.gather(myPrint(1), myPrint(2)))
loop.close()

Conclusion:

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This Problem is intended for audiences of all experiences who are interested in learning about Data Science in a business context; there are no prerequisites.

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