Gray Code LeetCode Solution

Problem – Gray Code LeetCode Solution

An n-bit gray code sequence is a sequence of 2n integers where:

• Every integer is in the inclusive range [0, 2n - 1],
• The first integer is 0,
• An integer appears no more than once in the sequence,
• The binary representation of every pair of adjacent integers differs by exactly one bit, and
• The binary representation of the first and last integers differs by exactly one bit.

Given an integer n, return any valid n-bit gray code sequence.

Example 1:

Input: n = 2
Output: [0,1,3,2]
Explanation:
The binary representation of [0,1,3,2] is [00,01,11,10].
- 00 and 01 differ by one bit
- 01 and 11 differ by one bit
- 11 and 10 differ by one bit
- 10 and 00 differ by one bit
[0,2,3,1] is also a valid gray code sequence, whose binary representation is [00,10,11,01].
- 00 and 10 differ by one bit
- 10 and 11 differ by one bit
- 11 and 01 differ by one bit
- 01 and 00 differ by one bit

Example 2:

Input: n = 1
Output: [0,1]

Constraints:

• 1 <= n <= 16

Gray Code LeetCode Solution in Python

class Solution:
    # @return a list of integers
    '''
    from up to down, then left to right
    
    0   1   11  110
            10  111
                101
                100
                
    start:      [0]
    i = 0:      [0, 1]
    i = 1:      [0, 1, 3, 2]
    i = 2:      [0, 1, 3, 2, 6, 7, 5, 4]
    '''
    def grayCode(self, n):
        results = [0]
        for i in range(n):
            results += [x + pow(2, i) for x in reversed(results)]
        return results

Gray Code LeetCode Solution in C++

class Solution {
    void utils(bitset<32>& bits, vector<int>& result, int k){
        if (k==0) {
            result.push_back(bits.to_ulong());
        }
        else {
            utils(bits, result, k-1);
            bits.flip(k-1);
            utils(bits, result, k-1);
        }
    }
public:
    vector<int> grayCode(int n) {
        bitset<32> bits;
        vector<int> result;
        utils(bits, result, n);
        return result;
    }
};

Gray Code LeetCode Solution in Java

public List<Integer> grayCode(int n) {
    List<Integer> result = new LinkedList<>();
    for (int i = 0; i < 1<<n; i++) result.add(i ^ i>>1);
    return result;
}

Gray Code LeetCode Solution Review:

In our experience, we suggest you solve this Gray Code LeetCode Solution and gain some new skills from Professionals completely free and we assure you will be worth it.

If you are stuck anywhere between any coding problem, just visit Queslers to get the Gray Code LeetCode Solution

Find on Leetcode

Conclusion:

I hope this Gray Code LeetCode Solution would be useful for you to learn something new from this problem. If it helped you then don’t forget to bookmark our site for more Coding Solutions.

This Problem is intended for audiences of all experiences who are interested in learning about Data Science in a business context; there are no prerequisites.

Keep Learning!

More Coding Solutions >>

LeetCode Solutions

Hacker Rank Solutions

CodeChef Solutions