Group() Groups() Groupdict() Hacker Rank Solution – Queslers

Problem : Group() Groups() Groupdict() Hacker Rank Solution

A group() expression returns one or more subgroups of the match.
Code :

>>> import re
>>> m = re.match(r'(\w+)@(\w+)\.(\w+)','[email protected]')
>>> m.group(0)       # The entire match 
'[email protected]'
>>> m.group(1)       # The first parenthesized subgroup.
'username'
>>> m.group(2)       # The second parenthesized subgroup.
'hackerrank'
>>> m.group(3)       # The third parenthesized subgroup.
'com'
>>> m.group(1,2,3)   # Multiple arguments give us a tuple.
('username', 'hackerrank', 'com')

groups()
A groups() expression returns a tuple containing all the subgroups of the match.
Code :

>>> import re
>>> m = re.match(r'(\w+)@(\w+)\.(\w+)','[email protected]')
>>> m.groups()
('username', 'hackerrank', 'com')

groupdict()
A groupdict() expression returns a dictionary containing all the named subgroups of the match, keyed by the subgroup name.
Code :

>>> m = re.match(r'(?P<user>\w+)@(?P<website>\w+)\.(?P<extension>\w+)','[email protected]')
>>> m.groupdict()
{'website': 'hackerrank', 'user': 'myname', 'extension': 'com'}

Task :

You are given a string S.
Your task is to find the first occurrence of an alphanumeric character in S(read from left to right) that has consecutive repetitions.


Input Format :

A single line of input containing the string S.

Constraints :

  • 0 < len(S) < 100

Output Format :

Print the first occurrence of the repeating character. If there are no repeating characters, print -1.


Sample Input :

..12345678910111213141516171820212223

Sample Output :

1

Explanation :

.. is the first repeating character, but it is not alphanumeric.
1 is the first (from left to right) alphanumeric repeating character of the string in the substring 111.

Group() Groups() Groupdict() Hacker Rank Solution in python 2

from __future__ import print_function
import re
r=re.search(r'([0-9a-zA-Z])\1',raw_input())
print(r.group(1) if r else -1)

Group() Groups() Groupdict() Hacker Rank Solution in python 3

# Enter your code here. Read input from STDIN. Print output to STDOUT
import re
m = re.findall(r"([A-Za-z0-9])\1+",input())
if m:
    print(m[0])
else:
    print(-1)

Group() Groups() Groupdict() Hacker Rank Solution in pypy

# Enter your code here. Read input from STDIN. Print output to STDOUT
import re
s=raw_input()
m=re.search(r'([a-z0-9])\1+',s)
if m is None:
    print -1
else:
    print m.group(0)[1]

Group() Groups() Groupdict() Hacker Rank Solution in pypy 3

# Enter your code here. Read input from STDIN. Print output to STDOUT
import re
m = re.search(r'([a-zA-Z0-9])\1', input().strip())
print(m.group(1) if m else -1)
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