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# Hamming Distance LeetCode Solution

## Problem – Hamming Distance

The Hamming distance between two integers is the number of positions at which the corresponding bits are different.

Given two integers `x` and `y`, return the Hamming distance between them.

Example 1:

``````Input: x = 1, y = 4
Output: 2
Explanation:
1   (0 0 0 1)
4   (0 1 0 0)
↑   ↑
The above arrows point to positions where the corresponding bits are different.``````

Example 2:

``````Input: x = 3, y = 1
Output: 1``````

Constraints:

• `0 <= x, y <= 231 - 1`

### Hamming Distance LeetCode Solution in Java

``````public class Solution {
public int hammingDistance(int x, int y) {
return Integer.bitCount(x ^ y);
}
}
``````

### Hamming Distance LeetCode Solution in C++

``````class Solution {
public:
int hammingDistance(int x, int y) {
int dist = 0, n = x ^ y;
while (n) {
++dist;
n &= n - 1;
}
return dist;
}
};
``````

### Hamming Distance LeetCode Solution in Python

``````    def hammingDistance(self, x, y):
"""
:type x: int
:type y: int
:rtype: int
"""
return bin(x^y).count('1')
``````
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