**Physical Address**

304 North Cardinal St.

Dorchester Center, MA 02124

You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed. All houses at this place are **arranged in a circle.** That means the first house is the neighbor of the last one. Meanwhile, adjacent houses have a security system connected, and **it will automatically contact the police if two adjacent houses were broken into on the same night**.

Given an integer array `nums`

representing the amount of money of each house, return *the maximum amount of money you can rob tonight without alerting the police*.

**Example 1:**

**Input:** nums = [2,3,2]
**Output:** 3
**Explanation:** You cannot rob house 1 (money = 2) and then rob house 3 (money = 2), because they are adjacent houses.

**Example 2:**

**Input:** nums = [1,2,3,1]
**Output:** 4
**Explanation:** Rob house 1 (money = 1) and then rob house 3 (money = 3).
Total amount you can rob = 1 + 3 = 4.

**Example 3:**

**Input:** nums = [1,2,3]
**Output:** 3

**Constraints:**

`1 <= nums.length <= 100`

`0 <= nums[i] <= 1000`

```
class Solution {
public:
int rob(vector<int>& nums) {
int n = nums.size();
if (n < 2) return n ? nums[0] : 0;
return max(robber(nums, 0, n - 2), robber(nums, 1, n - 1));
}
private:
int robber(vector<int>& nums, int l, int r) {
int pre = 0, cur = 0;
for (int i = l; i <= r; i++) {
int temp = max(pre + nums[i], cur);
pre = cur;
cur = temp;
}
return cur;
}
};
```

```
class Solution:
def rob(self, nums):
def rob_helper(nums):
dp1, dp2 = 0, 0
for num in nums:
dp1, dp2 = dp2, max(dp1 + num, dp2)
return dp2
return max(nums[0] + rob_helper(nums[2:-1]), rob_helper(nums[1:]))
```

```
public class Solution {
public int rob(int[] nums) {
if (nums.length == 0)
return 0;
if (nums.length < 2)
return nums[0];
int[] startFromFirstHouse = new int[nums.length + 1];
int[] startFromSecondHouse = new int[nums.length + 1];
startFromFirstHouse[0] = 0;
startFromFirstHouse[1] = nums[0];
startFromSecondHouse[0] = 0;
startFromSecondHouse[1] = 0;
for (int i = 2; i <= nums.length; i++) {
startFromFirstHouse[i] = Math.max(startFromFirstHouse[i - 1], startFromFirstHouse[i - 2] + nums[i-1]);
startFromSecondHouse[i] = Math.max(startFromSecondHouse[i - 1], startFromSecondHouse[i - 2] + nums[i-1]);
}
return Math.max(startFromFirstHouse[nums.length - 1], startFromSecondHouse[nums.length]);
}
}
```

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