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# Input() Hacker Rank Solution – Queslers

## Problem : Input() Hacker Rank Solution

This challenge is only forPython 2.input()in Python 2, the expression input() is equivalent to eval(raw _input(prompt)).
code :

``````>>> input()
1+2
3
>>> company = 'HackerRank'
>>> website = 'www.hackerrank.com'
>>> input()
'The company name: '+company+' and website: '+website
'The company name: HackerRank and website: www.hackerrank.com'
``````

You are given a polynomial P of a single indeterminate (or variable), x.
You are also given the values of x and k. Your task is to verify if P(x) == k.

#### Constraints :

All coefficients of polynomial P are integers.
x and y are also integers.

#### Input Format :

The first line contains the space separated values of x and k.
The second line contains the polynomial P.

#### Output Format :

Print True if P(x)==k. Otherwise, print False.

#### Sample Input :

``````1 4
x**3 + x**2 + x + 1
``````

#### Sample Output :

``````True
``````

#### Explanation :

P(1) = 1^3 + 1^2 + 1 + 1 = 4 = k
Hence, the output is True.

### Input() Hacker Rank Solution in python 2

``````# Enter your code here. Read input from STDIN. Print output to STDOUT

x,k = map(int,raw_input().split())
print k==input()``````

### Input() Hacker Rank Solution in python 3

``````# Enter your code here. Read input from STDIN. Print output to STDOUT
ui = input().split()
x = int(ui)
print(eval(input()) == int(ui))
``````

## Input() Hacker Rank Solution in pypy

``````x,k=map(int,raw_input().strip().split(" "))
p=eval(raw_input())
if(p==k):
print True
else:
print False``````

### Input() Hacker Rank Solution in pypy 3

``````s = input() # read input
# s = "1 4";
f = input()
# f = "x^3 + x^2 + x + 1"
(x,y) = s.split() # args
x=int(x)
y=int(y)
# print (x, y)
z=eval(f)
if (z == y):
print ("True")
else:
print ("False")``````
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##### Input() Hacker Rank Solution Conclusion:

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This Problem is intended for audiences of all experiences who are interested in learning about Data Science in a business context; there are no prerequisites.

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