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# Insert into a Binary Search Tree LeetCode Solution – Queslers

## Problem – Insert into a Binary Search Tree

You are given the `root` node of a binary search tree (BST) and a `value` to insert into the tree. Return the root node of the BST after the insertion. It is guaranteed that the new value does not exist in the original BST.

Notice that there may exist multiple valid ways for the insertion, as long as the tree remains a BST after insertion. You can return any of them.

Example 1:

``````Input: root = [4,2,7,1,3], val = 5
Output: [4,2,7,1,3,5]
Explanation: Another accepted tree is:
``````

Example 2:

``````Input: root = [40,20,60,10,30,50,70], val = 25
Output: [40,20,60,10,30,50,70,null,null,25]``````

Example 3:

``````Input: root = [4,2,7,1,3,null,null,null,null,null,null], val = 5
Output: [4,2,7,1,3,5]``````

Constraints:

• The number of nodes in the tree will be in the range `[0, 104]`.
• `-108 <= Node.val <= 108`
• All the values `Node.val` are unique.
• `-108 <= val <= 108`
• It’s guaranteed that `val` does not exist in the original BST.

### Insert into a Binary Search Tree LeetCode Solution in Java

``````class Solution {
public TreeNode insertIntoBST(TreeNode root, int val) {
if(root == null) return new TreeNode(val);
if(root.val > val) root.left = insertIntoBST(root.left, val);
else root.right = insertIntoBST(root.right, val);
return root;
}
}
``````

### Insert into a Binary Search Tree LeetCode Solution in C++

``````class Solution {
public:
TreeNode* insertIntoBST(TreeNode* root, int val) {
if(!root) return new TreeNode(val);
if(root->val > val) root->left = insertIntoBST(root->left, val);
else root->right = insertIntoBST(root->right, val);
return root;
}
};
``````

### Insert into a Binary Search Tree LeetCode Solution in Python

``````class Solution:
def insertIntoBST(self, root: Optional[TreeNode], val: int) -> Optional[TreeNode]:
if root is None: return TreeNode(val)
if root.val > val:  root.left = self.insertIntoBST(root.left, val)
else: root.right = self.insertIntoBST(root.right, val)
return root
``````
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