304 North Cardinal St.
Dorchester Center, MA 02124

Integer to English Words LeetCode Solution

Problem – Integer to English Words LeetCode Solution

Convert a non-negative integer `num` to its English words representation.

Example 1:

``````Input: num = 123
Output: "One Hundred Twenty Three"
``````

Example 2:

``````Input: num = 12345
Output: "Twelve Thousand Three Hundred Forty Five"
``````

Example 3:

``````Input: num = 1234567
Output: "One Million Two Hundred Thirty Four Thousand Five Hundred Sixty Seven"
``````

Constraints:

• `0 <= num <= 231 - 1`

Integer to English Words LeetCode Solution in Java

``````private final String[] LESS_THAN_20 = {"", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", "Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen", "Seventeen", "Eighteen", "Nineteen"};
private final String[] TENS = {"", "Ten", "Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", "Eighty", "Ninety"};
private final String[] THOUSANDS = {"", "Thousand", "Million", "Billion"};

public String numberToWords(int num) {
if (num == 0) return "Zero";

int i = 0;
String words = "";

while (num > 0) {
if (num % 1000 != 0)
words = helper(num % 1000) +THOUSANDS[i] + " " + words;
num /= 1000;
i++;
}

return words.trim();
}

private String helper(int num) {
if (num == 0)
return "";
else if (num < 20)
return LESS_THAN_20[num] + " ";
else if (num < 100)
return TENS[num / 10] + " " + helper(num % 10);
else
return LESS_THAN_20[num / 100] + " Hundred " + helper(num % 100);
}
``````

Integer to English Words LeetCode Solution in Python

``````def numberToWords(self, num):
to19 = 'One Two Three Four Five Six Seven Eight Nine Ten Eleven Twelve ' \
'Thirteen Fourteen Fifteen Sixteen Seventeen Eighteen Nineteen'.split()
tens = 'Twenty Thirty Forty Fifty Sixty Seventy Eighty Ninety'.split()
def words(n):
if n < 20:
if n < 100:
return [tens[n/10-2]] + words(n%10)
if n < 1000:
return [to19[n/100-1]] + ['Hundred'] + words(n%100)
for p, w in enumerate(('Thousand', 'Million', 'Billion'), 1):
if n < 1000**(p+1):
return words(n/1000**p) + [w] + words(n%1000**p)
return ' '.join(words(num)) or 'Zero'
``````

Integer to English Words LeetCode Solution in C++

``````class Solution {
public:
static string numberToWords(int n) {
if(n == 0) return "Zero";
else return int_string(n).substr(1);
}
private:
static const char * const below_20[];
static const char * const below_100[];
static string int_string(int n) {
if(n >= 1000000000)   return int_string(n / 1000000000) + " Billion" + int_string(n - 1000000000 * (n / 1000000000));
else if(n >= 1000000) return int_string(n / 1000000) + " Million" + int_string(n - 1000000 * (n / 1000000));
else if(n >= 1000)    return int_string(n / 1000) + " Thousand" + int_string(n - 1000 * (n / 1000));
else if(n >= 100)     return int_string(n / 100) + " Hundred" + int_string(n - 100 * (n / 100));
else if(n >= 20)      return string(" ") + below_100[n / 10 - 2] + int_string(n - 10 * (n / 10));
else if(n >= 1)       return string(" ") + below_20[n - 1];
else return "";
}
}
};

const char * const Solution::below_20[] =  {"One", "Two", "Three", "Four","Five","Six","Seven","Eight","Nine","Ten", "Eleven","Twelve","Thirteen","Fourteen","Fifteen","Sixteen","Seventeen","Eighteen","Nineteen"};
const char * const Solution::below_100[] = {"Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", "Eighty", "Ninety"};
``````
Integer to English Words LeetCode Solution Review:

In our experience, we suggest you solve this Integer to English Words LeetCode Solution and gain some new skills from Professionals completely free and we assure you will be worth it.

If you are stuck anywhere between any coding problem, just visit Queslers to get the Integer to English Words LeetCode Solution

Find on Leetcode

Conclusion:

I hope this Integer to English Words LeetCode Solution would be useful for you to learn something new from this problem. If it helped you then don’t forget to bookmark our site for more Coding Solutions.

This Problem is intended for audiences of all experiences who are interested in learning about Data Science in a business context; there are no prerequisites.

Keep Learning!

More Coding Solutions >>

LeetCode Solutions

Hacker Rank Solutions

CodeChef Solutions