Integer to English Words LeetCode Solution

Problem – Integer to English Words LeetCode Solution

Convert a non-negative integer num to its English words representation.

Example 1:

Input: num = 123
Output: "One Hundred Twenty Three"

Example 2:

Input: num = 12345
Output: "Twelve Thousand Three Hundred Forty Five"

Example 3:

Input: num = 1234567
Output: "One Million Two Hundred Thirty Four Thousand Five Hundred Sixty Seven"

Constraints:

• 0 <= num <= 231 - 1

Integer to English Words LeetCode Solution in Java

private final String[] LESS_THAN_20 = {"", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", "Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen", "Seventeen", "Eighteen", "Nineteen"};
private final String[] TENS = {"", "Ten", "Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", "Eighty", "Ninety"};
private final String[] THOUSANDS = {"", "Thousand", "Million", "Billion"};

public String numberToWords(int num) {
    if (num == 0) return "Zero";

    int i = 0;
    String words = "";
    
    while (num > 0) {
        if (num % 1000 != 0)
    	    words = helper(num % 1000) +THOUSANDS[i] + " " + words;
    	num /= 1000;
    	i++;
    }
    
    return words.trim();
}

private String helper(int num) {
    if (num == 0)
        return "";
    else if (num < 20)
        return LESS_THAN_20[num] + " ";
    else if (num < 100)
        return TENS[num / 10] + " " + helper(num % 10);
    else
        return LESS_THAN_20[num / 100] + " Hundred " + helper(num % 100);
}

Integer to English Words LeetCode Solution in Python

def numberToWords(self, num):
    to19 = 'One Two Three Four Five Six Seven Eight Nine Ten Eleven Twelve ' \
           'Thirteen Fourteen Fifteen Sixteen Seventeen Eighteen Nineteen'.split()
    tens = 'Twenty Thirty Forty Fifty Sixty Seventy Eighty Ninety'.split()
    def words(n):
        if n < 20:
            return to19[n-1:n]
        if n < 100:
            return [tens[n/10-2]] + words(n%10)
        if n < 1000:
            return [to19[n/100-1]] + ['Hundred'] + words(n%100)
        for p, w in enumerate(('Thousand', 'Million', 'Billion'), 1):
            if n < 1000**(p+1):
                return words(n/1000**p) + [w] + words(n%1000**p)
    return ' '.join(words(num)) or 'Zero'

Integer to English Words LeetCode Solution in C++

class Solution {
public:
    static string numberToWords(int n) {
        if(n == 0) return "Zero";
        else return int_string(n).substr(1);
    }
private:
    static const char * const below_20[];
    static const char * const below_100[];
    static string int_string(int n) {
        if(n >= 1000000000)   return int_string(n / 1000000000) + " Billion" + int_string(n - 1000000000 * (n / 1000000000));
        else if(n >= 1000000) return int_string(n / 1000000) + " Million" + int_string(n - 1000000 * (n / 1000000));
        else if(n >= 1000)    return int_string(n / 1000) + " Thousand" + int_string(n - 1000 * (n / 1000));
        else if(n >= 100)     return int_string(n / 100) + " Hundred" + int_string(n - 100 * (n / 100));
        else if(n >= 20)      return string(" ") + below_100[n / 10 - 2] + int_string(n - 10 * (n / 10));
        else if(n >= 1)       return string(" ") + below_20[n - 1];
        else return "";
        }
    }
};

const char * const Solution::below_20[] =  {"One", "Two", "Three", "Four","Five","Six","Seven","Eight","Nine","Ten", "Eleven","Twelve","Thirteen","Fourteen","Fifteen","Sixteen","Seventeen","Eighteen","Nineteen"};
const char * const Solution::below_100[] = {"Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", "Eighty", "Ninety"};

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